[prateek7563]

Originally Posted by capriccio

hey puys plz help me out at solving this type of questions..

A watch was running 14 mins late at 6.00 a.m on a saturday.exactly one week later, it was running 28 minutes fast.if the clock gained time uniformly,then what was the actual time when the clock showed 6.07 pm on tuesday?

Plz anyone explain the approach in detail..

wait i misread the question, IS IT 6:00 PM

[abhay15783]

Originally Posted by capriccio

hey puys plz help me out at solving this type of questions..

a watch was running 14 mins late at 6.00 a.m on a saturday.Exactly one week later, it was running 28 minutes fast.If the clock gained time uniformly,then what was the actual time when the clock showed 6.07 pm on tuesday?

plz anyone explain the approach in detail..

Gained 14+28= 42 Minutes in 7*24=168 hours So time gained in 84 Hours=21 Minutes Time lagging m=14 minutes hence has gained 7 Minutes Actual time is 6 p.m. Correct me if i am wrong

[capriccio]

Originally Posted by abhay15783

Gained 14+28= 42 Minutes in 7*24=168 hours So time gained in 84 Hours=21 Minutes Time lagging m=14 minutes hence has gained 7 Minutes Actual time is 6 p.m. Correct me if i am wrong

abhay i dont have the OA with me..but ur logic seems correct..thanx bro..

[capriccio]

solve this..
the units digit of 1^1! + 2^2!+ 3^3!+.....81^81! is ?

i dont have the OA..but m gettin it 1..plz check if m correct?

[prateek7563]

See,
clock gains 6 min a day. By tuesday morning 600am it will gain 18 min.


Hence , at 600 am in tue it shows 6:04 am.

Also clock gains 3 min in 12 hours.

Hence when original time is 6 pm , clock shows 6:08 pm . Hence answer shuld be 559pm.

[capriccio]

Originally Posted by prateek7563

See,
clock gains 6 min a day. By tuesday morning 600am it will gain 18 min.


Hence , at 600 am in tue it shows 6:04 am.

Also clock gains 3 min in 12 hours.

Hence when original time is 6 pm , clock shows 6:08 pm . Hence answer shuld be 559pm.

bro..if the clock gains 3 mins in 12 hrs ..at 6 pm it will show 6.07 pm and when the actual time shud be 6 pm..so i think it shud b the answer..correct me if m wrong..

[prateek7563]

Originally Posted by capriccio

bro..if the clock gains 3 mins in 12 hrs ..at 6 pm it will show 6.07 pm and when the actual time shud be 6 pm..so i think it shud b the answer..correct me if m wrong..

oh man i added the 604 and 3 minutes wrongly, thnx for letting me know.

Anyways answer is 600pm

[capriccio]

answer the questions on the basis of the info given below..
A set c is defined such that c=(z-2,z-1,z,z+1,z+2) and z is an integer.

for z=72 to 136,how many of the sets will always contain a multiple of 9?
a.24 b.23 c.32 d.8 e.7

for z=11 to 99,how many sets will contain atleast one perfect square?

a.19 b.21 c.18 d.6 e.none of these

plz give a detail solution..

[prateek7563]

Originally Posted by capriccio

answer the questions on the basis of the info given below..
A set c is defined such that c=(z-2,z-1,z,z+1,z+2) and z is an integer.

For z=72 to 136,how many of the sets will always contain a multiple of 9?
A.24 b.23 c.32 d.8 e.7

for z=11 to 99,how many sets will contain atleast one perfect square?

A.19 b.21 c.18 d.6 e.none of these

plz give a detail solution..

for :

1. Answer is 32.

2. None

[capriccio]

Originally Posted by prateek7563

for :

1. Answer is 32.

2. None

sorry bro..both ae incorrect..the correct answer is

1.23
2.19