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official quant thread for CAT 2009
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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No_Talent No_Talent is offline
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Re: official quant thread for CAT 2009 - 07-07-2009, 09:38 PM

Quote:
Originally Posted by chandan.mnnit View Post
One question from my side -

At the farewell party of a certain class, having n students, each student of the class gave a gift to exactly k other students of the class. What is the least possible number of students in the class who recieved at least one gift?
It seems to me that anybody can have more than 1 gifts. Ans as it hs asked for least possible number so ans should be 0.
I am a bit buffled with the language of the question. Was expecting a "max number of people" in the question


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Re: official quant thread for CAT 2009 - 07-07-2009, 09:38 PM

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Originally Posted by nishant.pilania View Post
i think ans : k+1

is it correct??
yes please post the method!!!


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Re: official quant thread for CAT 2009 - 07-07-2009, 09:44 PM

Quote:
Originally Posted by chandan.mnnit View Post
One question from my side -

At the farewell party of a certain class, having n students, each student of the class gave a gift to exactly k other students of the class. What is the least possible number of students in the class who recieved at least one gift?
it's k +1

Each of K number of people can give k-1 gifts to the other people of the group and 1 gift to a particular person out of the group, so that each gives a gift exactly to k other people.

So least possible number of students in the class who recieved at least one gift is k+1


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Re: official quant thread for CAT 2009 - 07-07-2009, 09:57 PM

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Originally Posted by first_timer View Post
it's k +1

Each of K number of people can give k-1 gifts to the other people of the group and 1 gift to a particular person out of the group, so that each gives a gift exactly to k other people.

So least possible number of students in the class who recieved at least one gift is k+1
Hey man can you please explain the last line ie So least possible number of students in the class who recieved at least one gift is k+1

Got the mistake that i was doing....didnt read the atleast one part ...ab jaa ke chamki... :(


Opportunity knocked at my door!!My doorman threw him out

CAT 08' : Q = 95%ile,DI = 59%ile,VA = 99.46%ile . OA = 98%ile

Last edited by chandan.mnnit; 07-07-2009 at 10:06 PM.
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Re: official quant thread for CAT 2009 - 07-07-2009, 09:57 PM

Quote:
Originally Posted by chandan.mnnit View Post
yes please post the method!!!
just k fixed selected people will get gifts from all other people
and persons from selected group also give gifts to these selected people only and one extra man

thus K+1
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Re: official quant thread for CAT 2009 - 07-07-2009, 10:02 PM

Quote:
Originally Posted by chandan.mnnit View Post
Hey man can you please explain the last line ie So least possible number of students in the class who recieved at least one gift is k+1
the group of k ppl will receive at least 1 gift.
And one extra person outside the group will get at least 1 gift.

So least no. of people receiving gifts is k+1


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Re: official quant thread for CAT 2009 - 07-07-2009, 10:19 PM

Quote:
Originally Posted by chandan.mnnit View Post
One question from my side -

At the farewell party of a certain class, having n students, each student of the class gave a gift to exactly k other students of the class. What is the least possible number of students in the class who recieved at least one gift?

okay here's an easy explanation

let n=3
and k=1

let those three students be a,b and c

a gives one gift to b
b gives one gift to a.
c gives one gift to a.

(drawing a small diagram would be helpful)

a and b are the only students who got gifts in this case, ie keeping in mind that we have to find out "the least possible number of students in the class who recieved at least one gift"

no of students who got the gift = 2 = 1+1= k+1.

this works with any number of students and any number of gifts.
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Re: official quant thread for CAT 2009 - 07-07-2009, 10:52 PM

7^7mod 13 gives 6 as remainder...
any easy method to find this??
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Re: official quant thread for CAT 2009 - 07-07-2009, 10:56 PM

--------------<repeat>-----------
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Re: official quant thread for CAT 2009 - 07-07-2009, 11:07 PM

Quote:
Originally Posted by ankur123xyz View Post
7^7mod 13 gives 6 as remainder...
any easy method to find this??
we wont be able to apply Eulers theorem here..... the easiest way would be to solve by conventional method -
7*(7)^6 mod 13
= 7*(49)^3 mod 13
= 7*(10)^3 mod 13
= 7*10 *(100) mod 13
=70 * 9 mod 13
= 5*9 mod 13
= 45 mod 13
=6


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