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official quant thread for CAT 2009
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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Re: official quant thread for CAT 2009 - 06-07-2009, 11:09 AM

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Originally Posted by mithun_sarmah View Post
HI Guys
Plz help me with the following probs .plz giv detailed explanations.
1) given that 2100! = (504)^P*Q where P and Q are natural numbers and Q is not a multiple of 7.wats the value of P? Ans 348

4) the sum of all the edges of a cuboid is 76cm. if all the edges are integers, wat is minimum possible length of its longest diagonal? ans 11cm

plz giv the explanations....thanks in advance.
1) find the highest power of 7 in 2100!, you'll get 348.

4) a+b+h = 19
find min of root(a^2+b^2+h^2)
a = b = h ==> 6,6,7
minimum = root(121) = 11
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Re: official quant thread for CAT 2009 - 06-07-2009, 11:18 AM

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Originally Posted by hi.shivani View Post
The last non zero digit is 6.
Please check ur ans again.. i think itshould be 8.


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Re: official quant thread for CAT 2009 - 06-07-2009, 11:22 AM

HI ,
can nyone explain the chinese theorem and eulers theorem? or if there is ny link to these explaination, plz mention it.

thanks in advance
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Re: official quant thread for CAT 2009 - 06-07-2009, 11:27 AM

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Originally Posted by mithun_sarmah View Post
HI ,
can nyone explain the chinese theorem and eulers theorem? or if there is ny link to these explaination, plz mention it.

thanks in advance

I think these theorems have been explained quite a lot over here

Just go to search and find it for yourself


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Re: official quant thread for CAT 2009 - 06-07-2009, 11:51 AM

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Originally Posted by vineet.nitd View Post
Please check ur ans again.. i think itshould be 8.
Yup...my bad...its 8 itself


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Re: official quant thread for CAT 2009 - 06-07-2009, 11:57 AM

Check out this link

Reminder Theory | CAT4MBA
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Re: official quant thread for CAT 2009 - 06-07-2009, 11:59 AM

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Originally Posted by mithun_sarmah View Post
HI ,
can nyone explain the chinese theorem and eulers theorem? or if there is ny link to these explaination, plz mention it.

thanks in advance

Check out this link :

Reminder Theory | CAT4MBA
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Re: official quant thread for CAT 2009 - 06-07-2009, 12:16 PM

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Originally Posted by mithun_sarmah View Post
HI ,
can nyone explain the chinese theorem and eulers theorem? or if there is ny link to these explaination, plz mention it.

thanks in advance
Chinese Remainder Theorem

This theorem is useful if the divisors are relatively prime. Some thing like a number when divided by 7, gives a remainder 5; when divided by 9, a remainder 2 and when divided by 11, a remainder 10. Then what is the remainder when the number is divided by 7*9*11.

If two numbers a and b are relaively prime, then there always exist two integers r and s such that ar+bs=1.

This forms the basis for applying the Chinese remainder theorem(CRT).

If N (mod a) = x (mod a)
& N (mod b) = y (mod b) , where a and b are relatively prime.

then, N (mod ab) = (ar*y +bs*x) (mod ab).

What is the remainder when (3^1001)/1001?

In the above problem 1001=7*11*13.

So, first we take 7 and 11 and apply CRT and once we get remainder with 77(7*11), we take 77 and 13 and apply CRT to get the remainder with 1001(77*13).

3^1001(mod7)=5(mod7) and 3^1001(mod11)=3(mod11).
Since gcd(7,11)=1 =>7r+11s=1=>r=-3 and s=2
So,3^1001(mod77)=(7*3*-3 + 11*5*2)mod77=47(mod77)

Also, 3^1001(mod13)= 9(mod13).
Again, since gcd(77,13)=1=>77t+13u=1=>t=-1,u=6
So,3^1001(mod1001)=(77*9*-1+13*47*6)mod1001=2973(mod1001)=971(mod1001)

Euler Totient Theorem
Let n = a1^p1 *a2^p2*...., where a1,a2... are prime numbers
E(n) = n*(1-1/a1)*(1-1/a2)*....

Suppose a and n are co-primes with each other, then a^E(n) = 1 mod n

The Euler number of n, is E=E1*E2*E3 ... ,where Ei is individual euler number for each prime factor raise to the power some number.

Let Ez =LCM(E1,E2,E3...)

Ez is called the effective euler number of n.

Supposing a and n are co-primes with each other, then as already discussed that a^E = 1 mod n; similarly a^Ez = 1 mod n.

Also, note that euler number of every prime is 1 less than that number and this lays the foundation to Fermat little theorem,a special case of Euler Totient Function.

Suppose p is a prime number and a is not a multiple of p then a^(p-1) = 1 mod p.

Note: Effective euler number is not the same as the euler number. Euler number signifies the number of coprimes less than a number while effective euler number is hypothetical but always satisfies the euler's theorem.(Just replace euler number with effective euler number)


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Last edited by vineet.nitd; 06-07-2009 at 12:28 PM.
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Re: official quant thread for CAT 2009 - 06-07-2009, 12:25 PM

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Originally Posted by prateek7563 View Post
A triangle ABC has its three sides in the ratio 2 : 3 : 4. A line DF is drawn parallel to BC and passing thru the mid point of AB meet CF at F. If the quadrilateral DBCF formed is a parallelogram, then

What will be the minimum perimeter of the quadrilateral DBCF?
so the perimeter is 3x +3x+ 2x =8x
so the minimum should be 8
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Re: official quant thread for CAT 2009 - 06-07-2009, 12:35 PM

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Originally Posted by chandan.mnnit View Post
385 = 5*7*11

=> Number of two digit numbers as factors of 385 = 3C2 + 1 (consider 11 also) = 4

as the factors are single digit and the question asks about 2 digit factors so choosing any 2 factors (like 5 and 7) from the above three factors to get the 2 digit factors( like 5*7 = 35 or 7*11 = 77...etc) required.....Hope it helps!!
in3c2 what is 3? from 2 single digit no you have to select 2 because with 11 you would get a no greater than 2 digit,,, i dont get the concept either but other method is fine . i just want to understand the meaning of 3c2
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