[kinscool]

[QUOTE=priyalli;1581618]

Originally Posted by kinscool

its given like this only in time package

hey i meant ..my post was wrong...not the question

[Ankurb]

Originally Posted by justtj

they would each be at integral value at follow time as there can be only 5 integral divisions between 11 and 12...

11:12, 11:24,11:36,11:48

correct me if i am wrong...

you got it all correct, may be the question is not properly constructed but that's the answer.

[justtj]

Originally Posted by priyalli

A number is divided into five parts .Twice the first part,thrice the second part and four times the fourth part are equal .Twice the second part ,five time the rhird part and six time sthe last part are equal .which of the following is always true if all the parts are integers ????
a)The first part is a multiple of 72
b)The second part is divisible by the forth part
c)the product of the first and fourth parts is divisible by 30
d)the first part is a factor of the last part

pls give the explanation also......

let 5 parts be a,b,c,d,e

from 1st statement, 2a = 3b = 4d
from 2nd statement, 2b = 5c = 6e

hence we can say 4a = 6b = 15c = 8d = 18e

dividing by 720,
we can say numbers r in ratio

90:60:24:45:20

a)The first part is a multiple of 72
false
b)The second part is divisible by the forth part
false
c)the product of the first and fourth parts is divisible by 30
true
d)the first part is a factor of the last part
false

[prateek7563]

Originally Posted by justtj

huh?
m i missing something?

-> sides r 1, 2 , root 3

Angles will be 180/(3 + root 3), (2*180)/(3 + root 3), (root3*180)/(3 + root 3)
comes out to be 38, 76 and 66

and 38 + 76 + 66 = 180

i didi by the "Solution of Triangles" .I cant understand ur approach

[priyalli]

A number is divided into five parts ,Twice the first part,thrice the second part and four times the fourth part are equal .Twice the second part ,five times the third part and six times the last part are equal .Which of the following is always true if all the parts are integers ??????
1-the first part is a multiple of 72
2--the second part is divisible by the fourth part
3--the first part is the factor of the last part
4-- the product of the first and the fourth parts is divisible by 30

plss elaborate by steps

[justtj]

Originally Posted by Ankurb

you got it all correct, may be the question is not properly constructed but that's the answer.

the question is correct...
maybe we can expect this type of language in CAT...

question asks

between 11 to 12, how many times will both {minute and hour} hands of clock will be at an integral values.

it does not say whether they will intersect or overlap.

[justtj]

Originally Posted by prateek7563

i didi by the "Solution of Triangles" .I cant understand ur approach

my approach is simple, based on ratio..

the bigger the side, larger will be the opposite angle, right?

so the angles will be in same ratio as the opposite side.

(period.) question ends here...


further to find angles...
r3 = root3, short form

angles r in ratio 1 : 2 : r3

so we can say
1*x + 2*x + r3*x = 180
x*(3 + r3) = 180
x = 180 / (3 + r3)

x comes out to be 38

hence we get the angles...

wots ur approach?
howcome u got side opposite to root3 = 60? and other one as 120?

[chandan.mnnit]

Originally Posted by Ankurb

you got it all correct, may be the question is not properly constructed but that's the answer.

11:12, 11:24,11:36,11:48

Ankurb these answers does not satisfy the question that has been asked

becoz the angle of the hor hand at 48 min would be 24 degree(from 11 o clock position) or 354 degree from the 12 o clock position

and minute hand would be at 48*6 degree that is 288 degree from 12 o clock position.

and the rest of the answers 11:12, 11:24,11:36 ...on looking at them you can just tell that these are not correct....

I think the answer should be 0....

Ur thought!!!!


On second thought after reading the post by justtj the answers make sense

[justtj]

Originally Posted by priyalli

A number is divided into five parts ,Twice the first part,thrice the second part and four times the fourth part are equal .Twice the second part ,five times the third part and six times the last part are equal .Which of the following is always true if all the parts are integers ??????
1-the first part is a multiple of 72
2--the second part is divisible by the fourth part
3--the first part is the factor of the last part
4-- the product of the first and the fourth parts is divisible by 30

plss elaborate by steps

really really elaborate version


let 5 parts be a,b,c,d,e

from 1st statement, 2a = 3b = 4d
from 2nd statement, 2b = 5c = 6e

hence we can say 4a = 6b = 15c = 8d = 18e

dividing by 720,
we can say numbers r in ratio

90:60:24:45:20

a)The first part is a multiple of 72
first part is 90, and is not a multiple of 90
hence false


b)The second part is divisible by the forth part
second part = 60, is not divisible by 4th part = 45
hence false

c)the product of the first and fourth parts is divisible by 30
product of 1st and 3rd = 90 * 24
it is divisible by 30
hence true

d)the first part is a factor of the last part
first is 90 and it is not a factor of 20
hence false


if you still cant understand.
pm me.

[priyalli]

Thre friends Aarvind ,Bharat and chandu are about to have their breakfast aravind has 7 apples ,bharat has 5 apples and chandu has no apples but has 12 coines .he offers to pay for some apples .they agree to share the 12 aaples equally among themselves and agree that chandu would pay 12 coins for his share .Bharat suggests that he be paid 5 coins and Aravind be paid 7coins .Aravind says that he should get more than 7 coins .how much should ararvind get ???????


steps ........