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official quant thread for CAT 2009
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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Re: official quant thread for CAT 2009 - 27-06-2009, 05:30 PM

Two different infinite geometric progressions
both have sum 1 and the same second term.
One has third term 1/8.
The second term of the progression upto
2 places of decimal is[/FONT][/FONT](A) 0.40 (B) 0.30 (C) 0.25 (D) 0.20 (E) 0.15
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Re: official quant thread for CAT 2009 - 27-06-2009, 05:31 PM

Quote:
Originally Posted by mahi101987 View Post
no

ur close to the answer anyways
6800?? Is it right dude??
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Re: official quant thread for CAT 2009 - 27-06-2009, 05:36 PM

Quote:
Originally Posted by janvats View Post
Two different infinite geometric progressions
both have sum 1 and the same second term.
One has third term 1/8.
The second term of the progression upto
2 places of decimal is[/FONT][/FONT](A) 0.40 (B) 0.30 (C) 0.25 (D) 0.20 (E) 0.15

c.........0.25

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Re: official quant thread for CAT 2009 - 27-06-2009, 05:39 PM

t ans given is choice e. 0.15
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Re: official quant thread for CAT 2009 - 27-06-2009, 05:41 PM

Quote:
Originally Posted by janvats View Post
Two different infinite geometric progressions
both have sum 1 and the same second term.
One has third term 1/8.
The second term of the progression upto
2 places of decimal is[/FONT][/FONT](A) 0.40 (B) 0.30 (C) 0.25 (D) 0.20 (E) 0.15
Let the 2nd term be a and the common ratio be r.
First term = a/r ; Sum = (a/r)/(1-r)=1
Therefore a/r = 1-r..................1
Given third term = ar = 1/8

Multipying 1 by r^2 ar = r^2 - r^3 = 1/8

this gives r = 1/2
THEREFORE a = 1/4

Therefore second term = 0.25
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Re: official quant thread for CAT 2009 - 27-06-2009, 06:01 PM

hey how do i do these?
1.the amt of work in a leather factory is increased by 50%.By what % is it neccessary to increase the no of workers to complete the new amt of work in previously planned time,if the productivity of the new labour is 25% more(40%)
2.a shopkeeper first raises the price of jewellery by x% then he decreases the new price by x %.after 1 such up down cycle,the price of a jewellery is decreased by rs21025.after the 2nd updown cycle it was sold for rs484416.what was the original price of the jewellery?(rs 525625)


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Re: official quant thread for CAT 2009 - 27-06-2009, 06:04 PM

Quote:
Originally Posted by Decent_flirt View Post
Let the 2nd term be a and the common ratio be r.
First term = a/r ; Sum = (a/r)/(1-r)=1
Therefore a/r = 1-r..................1
Given third term = ar = 1/8

Multipying 1 by r^2 ar = r^2 - r^3 = 1/8

this gives r = 1/2
THEREFORE a = 1/4

Therefore second term = 0.25
Quote:
Originally Posted by janvats View Post
t ans given is choice e. 0.15
same M getin ...r u sure answer is .15....!!!1

rgds
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Re: official quant thread for CAT 2009 - 27-06-2009, 06:33 PM

Hello Guys..
Please help!!

How many 6-digit numbers contain exactly 4 different digits?

a) 4536
b) 294840
c) 191520
d) None of these

Thanks in advance!!
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Re: official quant thread for CAT 2009 - 27-06-2009, 06:47 PM

Quote:
Originally Posted by subu_222412 View Post
Hello Guys..
Please help!!

How many 6-digit numbers contain exactly 4 different digits?

a) 4536
b) 294840
c) 191520
d) None of these

Thanks in advance!!
is the answer is b) 294840...


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Re: official quant thread for CAT 2009 - 27-06-2009, 06:48 PM

Quote:
Originally Posted by manjushaa View Post
hey how do i do these?
1.the amt of work in a leather factory is increased by 50%.By what % is it neccessary to increase the no of workers to complete the new amt of work in previously planned time,if the productivity of the new labour is 25% more(40%)
2.a shopkeeper first raises the price of jewellery by x% then he decreases the new price by x %.after 1 such up down cycle,the price of a jewellery is decreased by rs21025.after the 2nd updown cycle it was sold for rs484416.what was the original price of the jewellery?(rs 525625)
Leth the initial work = 1
let the number of workers be 1
Let the number of days in which it is completed = 1.
Therefor efficiency = 1.

Now work = 1.5
efficiency = 1.25
Therefore 1.25*x=1.5

x=1.2
Therefore increase = 20% and not 40%
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