Quote:
Originally Posted by janvats
Two different infinite geometric progressions
both have sum 1 and the same second term.
One has third term 1/8.
The second term of the progression upto
2 places of decimal is[/FONT][/FONT](A) 0.40 (B) 0.30 (C) 0.25 (D) 0.20 (E) 0.15
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Let the 2nd term be
a and the common ratio be r.
First term = a/r ; Sum = (a/r)/(1-r)=1
Therefore a/r = 1-r..................
1
Given third term = ar = 1/8
Multipying
1 by r^2 ar = r^2 - r^3 = 1/8
this gives r = 1/2
THEREFORE a = 1/4
Therefore second term =
0.25