[mahi101987]

Find out which student came from which city and went to which city for doing project ??

[kumar08]

Originally Posted by MN_09

Hi Puys,

If anybody knws the soln for the prob given below pls provide me an explanation :

If x = ( 60^99 - 58^99 ) divided by 60^98 + 58^98, which of the following holds true ?

a.) 0<x <= 0.5 b.) 0.5 < x <= 1 c.) 1 < x <= 2 d.) x> 2

( 60^99 - 58^99 )/60^98 + 58^98
Dividing Numarator and dinominator by 60

(1-(58/60)^99)/(1+(58/60)9 ~= 1-some small value/1+some small value
=~ approx 1 but less then 1

hence i think B

Correct me if i am wrong

Thank you

[WIMWI]

Originally Posted by kumar08

Originally Posted by Toughluck2009
Hi Puys

Help with this:

What is the coefficient of x^200 in [(1 + x)(1 + 2x^3)(1 + 4x^9)(1 + 8x^27)(1 + 16x^81)(1 + 32x^243)(1 + 64x^729)]^2?

1. 0 2. 228 3. 230 4. 229 5. 231


Hey is this Ans correct?


there is power 2 over the main expression
so I think...max power possible can be 121*2=242
I think power 200 is possible....

can some one through some light on this? Correct me if i am wrong...

Thank you

Thanks for pointing out the same. I have revised the earlier solution (answer is still 0). Please cross-check again

1. 0

terms containing powers of x greater than 200 can be neglected as they wont give 200 (no negative powers)
remaining terms can give powers of x (before squaring) = sum of (0,1,3,9,27,81) taken 2 at a time = (0,1,3,9,27,81;4,10,28,82;12,81,84;36,90;10

After squaring the expression either powers of x will be doubled or taken 2 at a time since (a+b+c+...)^2=a^2+b^2+c^2+...+2ab+2bc+2ca+...

since the original non-squared expression doesn't contain any power of 100, final expression will not contain any power of 200
taking sum of powers of x taking 2 at a time can give a maximum power of 90+108=198<200

=> there will be no x^200 term in the final expression

hope solution is clear now

what is the official solution btw ?

[vishrock]

Originally Posted by randeepsingh

ma take ::

22^2+222^2+..........+(22...49times)^2
= 3 = Ans

lemme knw the official ans ..

Dude official ans is 6

Already solved by someone few pages back.
But here is one more approach.
(2)^2 + (22)^2 + (222)^2 + .... + (222...49 times) is divided by 9.

2^2 { 1 + 11^2 + 111^2 + .........till (1111...49)^2}
=> 2^2 { 1 + 2^2 + 3^2 ........ 49^2 }
=> 2^2 * sum of aquares till 49
=> 4 * 49*50*99/6
=> 49*25*33 * 4
=> 3300 * 49
=> 161700

Now use division by 9, i.e. sum of digits shd be divisible by 9.

Ans = 6

[souravdddd]

what will be the soln to
remainder of 23! divided by 47??

[kumaraloks]

Originally Posted by mahi101987

Find out which student came from which city and went to which city for doing project ??

Engineering College:-
Mumbai-Chinmay,Esha,Anand,Hari
Delhi-Bhola,Govind,Jade
Pune-Indu
Indore-Dinesh,Freddy

For Projects:-
Bangalore-Hari
Chennai-Anand,Jade,Freddy,Indu
Madurai-Dinesh,Chinmay
Hyderabad-Bhola,Govind,Esha

Please post the right answers..

[WIMWI]

Question in Post #6501 : Poster mahi101987

Danish ---- Indore ---- Madurai
Chinmay ---- Mumbai ---- Madurai
Esha ---- Mumbai ---- Hyd
Bhola ---- Delhi ---- Hyd
Jade ---- Delhi ---- Chennai
Hari ---- Mumbai ---- Bang
Indu ---- Pune ---- Chennai
Freddy ---- Indore ---- Chennai
Govind ---- Delhi ---- Hyd
Anand ---- Mumbai ---- Chennai

[kumaraloks]

Originally Posted by kumar08

( 60^99 - 58^99 )/60^98 + 58^98
Dividing Numarator and dinominator by 60

(1-(58/60)^99)/(1+(58/60)9 ~= 1-some small value/1+some small value
=~ approx 1 but less then 1

hence i think B

Correct me if i am wrong

Thank you

Dude how can u get 1 when u divide nr and dr by 60.If u divide it by 60 den it will come 60^98 in numerator and in denominator it will come 60^97 and not 1.Please look at ur solution once more and explain..Thanks in advance

[mahi101987]

@ Kumaraloks adn WIMWI

I dont have the official answers but can u explain ur methods

i am getting a different set of answers these are mine

Engg..

MUMBAI... chinmaya esha indu hari
DELHI.... bhola govind jade
PUNE... anand
Indore.... freddy dinesh

Projects...

BAngalore... hari
chennai.... anand jade freddy esha
madurai... dinesh indu
hyderabad.... bhola govind esha

[Whats in a name]

Originally Posted by mahi101987

Find out which student came from which city and went to which city for doing project ??

hi Mahi... m not able to view the embedded pic in ur post... is it a jpg image?