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Re: official quant thread for CAT 2009 -
31-01-2009, 01:52 PM
Quote:
Originally Posted by now-or-never
Good books on quants plzz..
the other thread are not active so need to ask it here..
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I like Arun Sharma's books a lot .... quite comprehensive ....... for VA/RC, there's the TMH book ......... in fact, Arun Sir is taking online classes too this year; check it out, they offer a free demo .... www.vidyacenter.com/mindworkzz
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Re: official quant thread for CAT 2009 -
31-01-2009, 02:06 PM
Quote:
Originally Posted by Unhappy_Demon
adding few comments in your solution , can you comment on those ..
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@Unhappy_Demon
As given in the question his speed always decreases by 20% of his speed at beginning of his journey. this means his speed always decreases by 0.2x, and it does not depend on his speed at the time.
Hope that removes the confusion.
 
Thanks.
PEACE.
Varun.
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Re: official quant thread for CAT 2009 -
31-01-2009, 03:34 PM
Quote:
Originally Posted by Unhappy_Demon
how much time you are going to eat up for this ....
A farmer leaves his home at 8 a.m. and heads towards the village temple. His target is to reach the temple at 12 noon. His speed decreases by 20% (of the original speed at the beginning of his journey) for every hour travelled by him and then remains constant for the next 1 hour. At the end of three hours, he has travelled only 70% of the distance. By what percent should he increase his speed for the last one hour (as compared to his third hour speed), so that he reaches the village temple in time?
OPTIONS 1) 49.33 2) 49.34 3) 71.41 4) 71.42 5) 71.44
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let the speed be 100 then as per question sped at the begining of 2nd and 3rd hours be 80 and 60 respectively.
now total distance travel in 3 hours is= 100+80+60=240 = 70% x
now x= 342.857
diffrence= 102.857
% change= ((102.857/60)x 100 - 100)= 71.42
hence option (4)
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Follow Every Rainbow, Till You Find Your Dream,
A Dream That Will Need Every Love You Can Give,
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Re: official quant thread for CAT 2009 -
31-01-2009, 03:49 PM
Now solve this ..
1) A natural number ( greater than one) is called squareful number if its prime factorisation contains at least one square. How many squareful numbers below 101 are there
A) 63 B) 61 C) 39 D) 67 E) 41
2) How many pair of consecutive natural numbers less than 51 are squareful numbers as defined above
A) 2 B) 3 C) 4 D) 5 E ) 6
Happy solving.....:xmas:
Climb Every Mountain, Ford Every Stream,
Follow Every Rainbow, Till You Find Your Dream,
A Dream That Will Need Every Love You Can Give,
Every Day Of Your Life As Long As You Live.
.................................................. ..........
 CAT-2009
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Re: official quant thread for CAT 2009 -
31-01-2009, 04:07 PM
Quote:
Originally Posted by kanu09
Now solve this ..
1) A natural number ( greater than one) is called squareful number if its prime factorisation contains at least one square. How many squareful numbers below 101 are there
A) 63 B) 61 C) 39 D) 67 E) 41
2) How many pair of consecutive natural numbers less than 51 are squareful numbers as defined above
A) 2 B) 3 C) 4 D) 5 E ) 6
Happy solving.....:xmas:
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1) all multiples of 4,9,25,49
4 == 25
9 == 9
25 ==3
49 == 2
so, 39
2){8,9} {24,25} {48,49} {49,50} also {27,28} {44,45}
so, 6
Last edited by MaskedMenace; 31-01-2009 at 04:25 PM.
Reason: got it wrong !!
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Re: official quant thread for CAT 2009 -
31-01-2009, 04:20 PM
Quote:
Originally Posted by kanu09
Now solve this ..
1) A natural number ( greater than one) is called squareful number if its prime factorisation contains at least one square. How many squareful numbers below 101 are there
A) 63 B) 61 C) 39 D) 67 E) 41
Considering prime factors:
for 2 : All factors of 4 = 100/4 = 25
3 : All factors of 9 = 100/9 = 11 -2(36 and 72 common) = 9
5 : All factors 0f 25 = 100/25 = 4 -1(100) = 3
7: ..........49=2
Total such nos = 39
2) How many pair of consecutive natural numbers less than 51 are squareful numbers as defined above
A) 2 B) 3 C) 4 D) 5 E ) 6
My take is 6....(8,9),(24,25),(27,2  ,(44,45),(48,49),(49,50)
Happy solving.....:xmas:
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Hope am clear... :-)
Last edited by sumitbce; 31-01-2009 at 04:25 PM.
Reason: Modified
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Re: official quant thread for CAT 2009 -
31-01-2009, 04:22 PM
Quote:
Originally Posted by MaskedMenace
1) all multiples of 4,9,25,49
4 == 25
9 == 11
25 ==3
49 == 2
so, 41
2){8,9} {24,25} {48,49} {49,50}
so, 4
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Menace you considered some common values ( 36 and 72)...u have to subtract that from the answer for Q 1.
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Re: official quant thread for CAT 2009 -
31-01-2009, 04:23 PM
Quote:
Originally Posted by sumitbce
Hope am clear... :-)
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yep! and we missed two more in q2 :P
ans will be 6
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Is AIMing for better accuracy :P
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Re: official quant thread for CAT 2009 -
31-01-2009, 08:46 PM
Quote:
Originally Posted by kanu09
Now solve this ..
1) A natural number ( greater than one) is called squareful number if its prime factorisation contains at least one square. How many squareful numbers below 101 are there
A) 63 B) 61 C) 39 D) 67 E) 41
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4=>4,8,12...100=>25
9=>9,18,27...99=>11-2=9
16=>similar to 4
25=>25,50,75=>3
49=>49,98=>2
total of 39.
option (C)
Quote:
2) How many pair of consecutive natural numbers less than 51 are squareful numbers as defined above
A) 2 B) 3 C) 4 D) 5 E ) 6
Happy solving.....:xmas:
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squareful numbers before 51 are
{4,8,9,12,16,18,20,24,25,27,28,32,36,40,44,45,48,4 9,50}
so,6 pairs
option (E)
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Re: official quant thread for CAT 2009 -
31-01-2009, 09:05 PM
Quote:
Originally Posted by shashank3012
4=>4,8,12...100=>25
9=>9,18,27...99=>11-2=9
16=>similar to 4
25=>25,50,75=>3
49=>49,98=>2
total of 39.
option (C)
squareful numbers before 51 are
{4,8,9,12,16,18,20,24,25,27,28,32,36,40,44,45,48,4 9,50}
so,6 pairs
option (E)
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One from my side
In the given figure ABCD is a parallelogram P is a point on the extended line DA such that PQ = 73.5, QR = 11.2 what ‘ll be the length of RC?
Confusion is the part of solution but Remember that Solution comes outof that confusion----Jigar.A.Patel
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