CAT 2008: Quantitative Questions a Day 1 to 50 - The discussions

pavanpadekal

Quote:

Originally Posted by implex

this solution is beautifully wrong!!

the thing is all that glitters is not gold

Buddy,
I hope you do take this in the right spirit.
I do like all the help you extend to people committing mistakes with the day's QQAD including myself.But somehow comments like the one above in bold are a tad discouraging.Kindly avoid them.The corrections are welcome.We appreciate your help

vikas2405

according to the given rules any two of the following 4-tupples can be selected
{1,2,4,8}, {3,6,9,12} and {7,11,13,14}.
How ever 5 and 10 can never be part of S'.
Hence n(X) = 2.
Answer - (1)

sudeepdeb

answer(1): 2

The subsets which follow the conditions b and c are:
i) 1->8->4->2
ii) 3->9->12->6
iii) 7->11->13->14
iv) 5->10

Since S' has exactly 8 elements, subset (iv) will be left out always.

So the only subset which can't be part of S' is (iv), having 2 elements.

implex

Quote:

Originally Posted by pavanpadekal

Buddy,
I hope you do take this in the right spirit.
I do like all the help you extend to people committing mistakes with the day's QQAD including myself.But somehow comments like the one above in bold are a tad discouraging.Kindly avoid them.The corrections are welcome.We appreciate your help

man they were not discouraging, the thing is the solution looks beautiful at the first instance, but if u look close, its flawed. and thats what the phrase was for! It was all in good faith! My apologies totally!

Shontu

hi puys!!!!!!!

i am new around this
a friend of mine introed me to this
the Q's are explicitly AWESOME and WICKED

anyway for QQAD #008

option 3 i.e.
n(x)=3
how??
consider that s'' is subset of this s' with the same conditions other that condition 1if we extend this to find if
1 can belong to s'' then we end up saying that any element belonging to {1, 8, 4, 2} belongs to s'
in similar lines we observe
{3, 9, 12, 6}
{5, 10}
{7, 11, 13, 14}
{15}

X belongs to {5, 10, 15}
hence n(x)=3

Aarav

Great work on today's problem, will have tough time tomorrow assembling the list of names for all those who cracked today's problem

The suggestion to give problems of similar topics is good, and we tried similar thing in QQAD 2006 as well. But, it didn't lead to desired results due to various reasons. I would prefer to keep you guessing on what's coming next at you and that's where the excitement lies the most.

JaiRamJiKi

Jai Ram Ji Ki,

Hum bhi aa sakta hu is discussion me ??

Vaise to hum aa hi gaya hu...

Koi hame bhi bataiye k Quant ki Basics kaha se padhe jaye??

TIA

ideacrash

Quantitative Question # 008

i think 7,11and 13 cant be part of S', so n(X) = 3.

so Ans = 2.

spidy_rules

hey guys,

Please make a choice b/w the following 2 books on quant

1.Trishna's Quantitative ability
2.Arun Sharma.

Please justify!!..

kavita_iet

A person is said to be n years old, where n is a non-negative integer, if the person has lived at least n years and has not lived n+1 years. At some point in time, Anupam is 4 years old and Nilesh is three times as old as Shrikant. At some other time, Shrikant is twice as old Anupam, and Nilsh is 5 times as old as Anupam. At yet another time, Nilesh is twice as old as Anupam, and Anupam is Y years old. There are different possibilities of what Y can be. What is the largest possible value of Y?
Time Anupam Nilesh Shrikant
1 4 yrs 3x x
2 k 5k 2k
3 y 2y
5k-3x = k-4
2k-x = k-4
=>3k = 2x solving we get x= 12 and k = 8
Time Anupam Nilesh Shrikant
1 4 yrs 36 12
2 8 40 16
3 32 64
y = 32 is logically the max value