CAT 2008: Quantitative Questions a Day 1 to 50 - The discussions

Aarav

Quote:

Originally Posted by Apurv

To all those who're experiencing problems getting QQAD everyday at the right time

Dear puys,

I happen to get my QQAD on time in the mornings so if anyone wants me to auto-forward it to them, please PM me your email address and I'll set it to auto-forward from my Gmail.

Thanks and cheers,
Apurv

Apurv, we will be off this weekend and hopefully things should be fine by early next week. I fear the auto-forward may not work just in case you also miss the NL [since it is really erratic]

Thanks for your help

srikar2097

Problem 2:

ABC is an acute angled triangle. CD be the altitude through C. If AB = 8, and CD = 5. Find the distaance between the mid-points of AD and BC.

Answer: (22.25)^1/2 or 4.7 (approx.)

Let the line joining midpoints be GE.
E is midpoint of BC. Draw a line passing through E || to AB. This intersects DC at G and AC at F; both midpoints (by midpoint theorem)

Also join GF. In triangle ABC, GF passed through G, F (both mid points). Hence GF||DC and half of it. Also GF is perpendicular to FE. triangle GFE (joining 3 midpoints of triangle ABC) is a right angle triangle.

Again FE = AB * 1/2 = 4
so GE = (22.25)^1/2 or 4.7 (approx.)

Aarav

Quote:

Originally Posted by srikar2097

Problem 2:

ABC is an acute angled triangle. CD be the altitude through C. If AB = 8, and CD = 5. Find the distaance between the mid-points of AD and BC.

Answer: (22.25)^1/2 or 4.7 (approx.)

Let the line joining midpoints be GE.
E is midpoint of BC. Draw a line passing through E || to AB. This intersects DC at G and AC at F; both midpoints (by midpoint theorem)

Also join GF. In triangle ABC, GF passed through G, F (both mid points). Hence GF||DC and half of it. Also GF is perpendicular to FE. triangle GFE (joining 3 midpoints of triangle ABC) is a right angle triangle.

Again FE = AB * 1/2 = 4
so GE = (22.25)^1/2 or 4.7 (approx.)

Your answer is correct for this.

No takers for 1st problem of set 3?

The answer to integer values of p is p > 5/2 => 7 values.

srikar2097 · 08:00 PM

Quote:

Originally Posted by Aarav

Your answer is correct for this.

No takers for 1st problem of set 3?

The answer to integer values of p is p > 5/2 => 7 values.

I'm going after it now

Also, Aarav tomorrow also will as fun filled as today ??

Aarav

Quote:

Originally Posted by srikar2097

I'm going after it now

Also, Aarav tomorrow also will as fun filled as today ??

Nahi yaar, give me some break, meri bhi zindagi hai, ghar hai, ghar waale hain. We will resume from Monday or Tuesday and next week -> and that will be proper QQAD.

smartie

Aarav..wanted to ask about question 2 from set 1...is 6/6+9=10 wrong?

srikar2097

Quote:

Originally Posted by Aarav

Nahi yaar, give me some break, meri bhi zindagi hai, ghar hai, ghar waale hain. We will resume from Monday or Tuesday and next week -> and that will be proper QQAD.

Some how I just didn't think of all those things you mentioned

You are always there, in this thread or other, I kind of assumed by default

Anyway thanks a lot for today. I was really hectic at work, but I was just solving these sets. If someone from work gets to know I'll probably be thrown out

siddooba

Quote:

Originally Posted by srikar2097

Some how I just didn't think of all those things you mentioned

You are always there, in this thread or other, I kind of assumed by default

Anyway thanks a lot for today. I was really hectic at work, but I was just solving these sets. If someone from work gets to know I'll probably be thrown out

Today was real fun

- thanks a lot

I'm still trying to solve the first question of Set 3 .. Its tough ..

smartie

Quote:

Nahi yaar, give me some break, meri bhi zindagi hai, ghar hai, ghar waale hain. We will resume from Monday or Tuesday and next week -> and that will be proper QQAD.

We had real fun today..even more than QQAD

Although coudnt solve set3 coz of exams tomorrow,solving the first two sets was really enjoyable( inspite of making mistakes)...