THE OFFCICAL CAT2008: DI - lOGICAL REASOING

[saumyakumar123]

Just Wanted to Know why is everyone keeping so quiet?
sorry forgot to introduce myself. I am Saumya from bangalore i ll be taking CAT for the Last time this year. So looking forward to learn a lot from you guys.

[made_for_iims]

Originally Posted by marijuana_user

Hi!

Some DS questions::

1. 8 teams participated in IPL. Every team played exactly two matches against every other team. No match ended in a draw. A team got 1 point for a win and no point for a loss. If no 2 teams had the same points, what was the rank of Rajasthan Royals (RR)

A-> RR won more den 60% and less than 70% matches it played.
B-> No 2 of the bottom three teams had points as consecutive numbers.

2. There are 101 teams participating in a tournament. Each team playes with any other team at most once. THe number of matches played by nth team,Tn is n (n<=99). How many matches were played by T101.

A-> T100 played 100 matches
B-> T50 played a game with T51.


Regards!

First Question

A. We can reframe it like...RR won 9 matches
==> We cant determine from this
since the possible values could be
13,12,10,9,6,4,2,0 (here first team won all matches except one match from RR)...
and rest all won all matches frm the successive teams.
14,12,9,8,7,4,2,0 (here RR lost against fifth team...rest all won all matches frm successive teams)

B.
==> We cant determine anything frm this...as it is we have two above cases which doesnt have No consecutive numbers in bottom three...

A&B
=> combining the two...still we have atleast these two above cases

Cant be determined

[made_for_iims]

Question 2:

Given...
T1=1 ,T2=2 , T3=3....T99=99

A.
Now we know that T100 played 100 matches....
=>T100 played with every other team
So if we remove T100 frm the pic....
we'll have
T1=0 T2=1 T3=2 T4 =3 T99=98
Now considering T99.... it can play with atmost 98 teams(removing T1,T100 and itself)...and it had played 98 matches...so it played with everyone rest...including T101....

now removing T99 too
T1=0 T2=0 T3=1 T4=2..... T98=96
Now T98 can play atmost with 96 teams (T0,T1,T99,T100 and itself).....

So it'll play with T101 too.... this ways we can def calc how many matches T101 played.... its 50 matches.... but since its DS we need not calculate it....


B.
Here if we assume that Tn played all the matches with T(100-n)....T(n-1) (Upto 99) + with T100.... we can have T101 playing Zero matches and T100 as 99....

And also we can have option above too.... SO we cant determine answer with B alone

[aky_akshay]

Originally Posted by marijuana_user

Hi!

Some DS questions::

1. 8 teams participated in IPL. Every team played exactly two matches against every other team. No match ended in a draw. A team got 1 point for a win and no point for a loss. If no 2 teams had the same points, what was the rank of Rajasthan Royals (RR)

A-> RR won more den 60% and less than 70% matches it played.
B-> No 2 of the bottom three teams had points as consecutive numbers.

2. There are 101 teams participating in a tournament. Each team playes with any other team at most once. THe number of matches played by nth team,Tn is n (n<=99). How many matches were played by T101.

A-> T100 played 100 matches
B-> T50 played a game with T51.


Regards!

1. I think both A & B together are not sufficient.
2. Staement A alone is sufficient.

[Arshis]

Originally Posted by naresh007

Here's my First Puzzle:
call it Great Einstein's Riddle:

He said that 98% of the world could not solve it. But several NIEHS scientists were able to solve it, and they said it's not all that hard if you pay attention and are very patient. Give it a try:
There are 5 houses in 5 different colors in a row. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage. Other facts:
1. The Brit lives in the red house.
2. The Swede keeps dogs as pets.
3. The Dane drinks tea.
4. The green house is on the immediate left of the white house.
5. The green house's owner drinks coffee.
6. The owner who smokes Pall Mall rears birds.
7. The owner of the yellow house smokes Dunhill.
8. The owner living in the center house drinks milk.
9. The Norwegian lives in the first house.
10. The owner who smokes Blends lives next to the one who keeps cats.
11. The owner who keeps the horse lives next to the one who smokes Dunhill.
12. The owner who smokes Blue masters drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The owner who smokes Blends lives next to the one who drinks water.

The question is: WHO OWNS THE FISH?

Hey the answer is GERMAN..........
I got the answer thru d method of compilin the problem by a table.......... but it consumed a lot of time arnd 12-15 mins.... is there a faster method to reach to d result....

[marijuana_user]

Originally Posted by made_for_iims

First Question

A. We can reframe it like...RR won 9 matches
==> We cant determine from this
since the possible values could be
13,12,10,9,6,4,2,0 (here first team won all matches except one match from RR)...
and rest all won all matches frm the successive teams.
14,12,9,8,7,4,2,0 (here RR lost against fifth team...rest all won all matches frm successive teams)

B.
==> We cant determine anything frm this...as it is we have two above cases which doesnt have No consecutive numbers in bottom three...

A&B
=> combining the two...still we have atleast these two above cases

Cant be determined

Hey Harsh,

EVen i did it the same way. BUt here is what the official key says ::

Total No of matches :: 56..(8C2)*2

--> The total number of points of all the teams taken together = 56. From A the total number of points of A is 9 but nothing can be said abt its rank. From B the total points of RR are unknown.

COmbining both::

RR can't have rank 1 or rank below 4 as then in that case the total no. of points won't be 56.

If there are 5 rank below RR then points can be 12,10,9,8,7,6,3,1.

If there are 4 teams below RR , the min. points above wud be 10,11,12 but the teams below RR cannot have points satisfying B statement.

Hence ans C.

Regards!
Marijuana!

[made_for_iims]

Originally Posted by marijuana_user

Hey Harsh,

EVen i did it the same way. BUt here is what the official key says ::

Total No of matches :: 56..(8C2)*2

--> The total number of points of all the teams taken together = 56. From A the total number of points of A is 9 but nothing can be said abt its rank. From B the total points of RR are unknown.

COmbining both::

RR can't have rank 1 or rank below 4 as then in that case the total no. of points won't be 56.

If there are 5 rank below RR then points can be 12,10,9,8,7,6,3,1.

If there are 4 teams below RR , the min. points above wud be 10,11,12 but the teams below RR cannot have points satisfying B statement.

Hence ans C.

Regards!
Marijuana!

hmmm since above two cases are 100% possible(I literally tallied their points now ).... Answer can never be C....may be they are missing something...or they forgot to mention some extra fact too...

[bangaram]

Originally Posted by shivam_01

410 students of 5 different colleges have registered in TathaGat for a classroom program. These colleges are NSIT, IIT, Jamia, JSS and North Campus (DU). TathaGat team has divided the city in a grid network as shown in the figure below. The grid network follows the co–ordinate rule to identify the points on it. One can travel along this grid only. The five colleges are shown by dots ( .</span>)</span> and the number written in bracket below a college’s name represent the number of students from the respective college.


67. If TathaGat team decides to open only one center, find out the co-ordinate of this only center such that the sum of the total distance traveled by all the students is minimum.
(0, 4) (8, 7) (6, 15) (6, 4) none of these
68. After six months team proposed to start another center without shifting the first center of the above problem. Find out the co-ordinate of the second center assuming that this proposal is put forward just to further minimize the sum of the distance traveled by all the students.
(0, 4) (8, 7) (6, 15) (6, 4) none of these
69. The ratio of the number of student in two centers of the first two problems is given by
23:18 17:24 29:12 30:11 none of these
70. If the team decided to open two centers in a way such that the sum of the total distances traveled by all the students is minimum. Find out the coordinates of these two centers along the grid line. (do not use data from the previous question)
(0, 4) & (8, 7) (0, 4) & (6, 15) (8, 7) & (6, 15) (6, 15) & (6, 4) none of these



Attachment 10149

what is the logic behind this question? I couldn't get it... is it calculating the centroid or something like that for the pentagon or there's some other funda behind it? In the first q, does the total distance minimum implies individual distance from the college to the center should be min?

[nikunj14_83]

Hi Puys,
I am just not able to interpret this ques so plz help me out in this one....


Ans are-
1)Stage 3
2)No change
3) 4
4) Healthy & Infected

[sarsij]

Originally Posted by nikunj14_83

Hi Puys,
I am just not able to interpret this ques so plz help me out in this one....


Ans are-
1)Stage 3
2)No change
3) 4
4) Healthy & Infected

Hey......I tried to solve it.....and it looked as if I could have cracked at least 3 questions in the actual exam condition........

Here is what I can tell you....

Make this chart.......
Initially Stahe 1 Stage 2 Stage 3
Healthy -> 48% 53.33% 33.33% 11.11%
Infected -> 32% 24.33% 44% 44.44%
Resistant -> 20% 22.67% 22.67% 44.45%

Here if you assume that initially there were 48 Healthy plants and 32 Infected plants and 20 Resistsnt plants then you can keep on calculating the number of plants in later stages. Also keep in mind the following rules which are mentioned in the question

1. Healthy + Infected = Healthy becomes Infected (i.e. number of healthy plants decreases and Infected ones increases, this happens in Stage 2.)

2. Infected + Resistant = Infected Plants die out (ie, Number of Infected plants will decrese and the Number of Resistant plants will remain same)

3. Resistant + Healthy = Healthy PLants will become Resistant (ie, Number of Resistant plants will increase and the number of healthy plants will decrease).

I hope I have made the question clear. Guess it should not be difficult to crack it now.

Hope it helps