[neversaydie_001]

Originally Posted by naresh007

Hello..puys...,

Find the teaser for the Day...Question.No: 16th

Billiards Tournament

Seven amateur billiards players gather to play a billiards tournament. The players were divided into two sections: Section A has 4 players; and Section B has 3 players. Each player played against every other player in his/her Section.


With the information below, can you determine each person's section, and to whom they won and lost.

Keep Rockin...n...Keep Solvin

Section A:Mary,Jill,Greg,John
Section B:Betty,Chris,Tina

Section A
Greg won against all players in his section.
Mary won against all but Greg.
Jill won against John but lost to the other two.

Section B
Tina defeated Chris.
Chris defeated Betty.
Betty defeated Tina.

Pretty easy one..

[vivs_d]

There are a number of long fuses, of which you only know that they burn for exactly one hour after you light them at one end. However, you don't know whether they burn with constant speed. Fore example, the first half of the fuse is burned in only 10 minutes while the rest takes the other fifty minutes to burn completely. With what least number of fuses can you measure exactly seven eighths of an hour in time? You can safely assume that you have a lighter.

[Iota]

Originally Posted by vivs_d

There are a number of long fuses, of which you only know that they burn for exactly one hour after you light them at one end. However, you don't know whether they burn with constant speed. Fore example, the first half of the fuse is burned in only 10 minutes while the rest takes the other fifty minutes to burn completely. With what least number of fuses can you measure exactly seven eighths of an hour in time? You can safely assume that you have a lighter.

a very old puzzle .

number of candles required is 3.

lit all the three together, but the first one in bth the ends.
so the first one will be burnt out in 1/2 hr. the other two are left over to be burnt for 1/2 hr more.
now lit the second candle in the other end also. so this will burn it in 1/4 hrs. the last one is left to be burnt for 1/4 hrs.
lit @ the other end as well. it will take time of 1/8 hrs.
so total time = 1/2+1/4+1/8 = 7/8

[implex]

Originally Posted by Iota

a very old puzzle .

number of candles required is 3.

lit all the three together, but the first one in bth the ends.
so the first one will be burnt out in 1/2 hr. the other two are left over to be burnt for 1/2 hr more.
now lit the second candle in the other end also. so this will burn it in 1/4 hrs. the last one is left to be burnt for 1/4 hrs.
lit @ the other end as well. it will take time of 1/8 hrs.
so total time = 1/2+1/4+1/8 = 7/8

given the question if first half can burn in 10 mins and rest in 50 mins .. we cant assume what u did? can we ?

but there seems no other way to do it

[Iota]

Originally Posted by implex

given the question if first half can burn in 10 mins and rest in 50 mins .. we cant assume what u did? can we ?

but there seems no other way to do it

ya exactly,
but the question also says that the candle to be burnt is in 1 hr total.
pls note that we are not considerin the fraction of candle burnt(which wont be uniform obviously ) but the time required -- which will always be 1 hr in total. e.g say after 15 mins the candle will need another 45 mins to burn completely....so here we can take the time as a base.isn't so?

i think this was the trck here in this puzzle...

[naresh007]

Hello puys…. it’s been very long time I’m not posted..:( sorry for the delay.

Here’s the answer for the Q.No:16th

Section A:

John: Lost to everyone.
Jill: Beat John, Lost to Mary and Greg.
Mary: Beat John, and Jill. Lost to Greg.
Greg: Beat everyone.

Section B:

Betty: Beat Tina. Lost to Chris.
Tina: Beat Chris. Lost to Betty.
Chris: Beat Betty. Lost to Tina.

Originally Posted by naresh007

Question.No: 16th - Billiards Tournament

Seven amateur billiards players gather to play a billiards tournament. The players were divided into two sections: Section A has 4 players; and Section B has 3 players. Each player played against every other player in his/her Section.

Players: Betty, Chris, Greg, Jill, John, Mary, and Tina.

1. Every player from Section B has the same win-loss record.

2. John lost all of his games.

3. Mary, who defeated Jill, won more games than exactly 5 of the players.

4. Jill lost to Greg, and Tina defeated Chris.

With the information below, can you determine each person's section, and to whom they won and lost.

Keep Rockin...n...Keep Solvin

[naresh007]

Hey Puys,


Find my today's Question.No: 17th -- Motor Bike Race Tournament

For Questions 1 to 5 read the following instructions:
Nine Bikes participated in a F1-MotorBike tournament. Five races were held in this tournament. The winner of a race gets 5 points, 2nd gets 3 and the 3rd gets 1. The table gives the point’s tally.

Bike: Points
A # 5
B # 5
C # 8
D # 2
E # 5
F # 6
G # 4
H # 10
I # 0

One race is held between five Bikes. The first race is held among the first 5 Bikes from the left in the above table. Out of these Bikes, A drops out of the race and a new Bike. I.e. F enters into the race. In the next race, B drops out and G enters and so on. It is also given that H is the only Bike that scored in 2 consecutive races.

Q.1) What was the position of Bike F in race 4?
a. 4th b. 2nd c. 3rd d. cannot be determined e.1st


Q.2)What is the ratio of the points scored by “G” and E in race 5?
a. 1:3 b. 3:1 c. 1:5 d. cannot be determined e. 5:1


Q.3) The first 3 rankers of the race 3 in some order?
a. C,E,G b. D,E,F c. C,D,F d. C,E,F e. C,G,F


Q.4) D could have come third in which of the following races?
a. Race 1 b. Race 3 c. Race 4 d. Race 5 e. cannot be determined


Q.5) Suppose if C had 6 points and E had 7 points while the points of the rest of the Bikes remain unchanged then E could’ve come second in
a. One race b. Two races c. At most one race d. At most 2 races e. cannot be determined

Keep Rockin...n...Keep Solvin

[implex]

Originally Posted by naresh007

Hey Puys,


Find my today's Question.No: 17th -- Motor Bike Race Tournament

For Questions 1 to 5 read the following instructions:
Nine Bikes participated in a F1-MotorBike tournament. Five races were held in this tournament. The winner of a race gets 5 points, 2nd gets 3 and the 3rd gets 1. The table gives the point’s tally.

Bike: Points
A # 5
B # 5
C # 8
D # 2
E # 5
F # 6
G # 4
H # 10
I # 0

One race is held between five Bikes. The first race is held among the first 5 Bikes from the left in the above table. Out of these Bikes, A drops out of the race and a new Bike. I.e. F enters into the race. In the next race, B drops out and G enters and so on. It is also given that H is the only Bike that scored in 2 consecutive races.

Q.1) What was the position of Bike F in race 4?
a. 4th b. 2nd c. 3rd d. cannot be determined e.1st


Q.2)What is the ratio of the points scored by “G” and E in race 5?
a. 1:3 b. 3:1 c. 1:5 d. cannot be determined e. 5:1


Q.3) The first 3 rankers of the race 3 in some order?
a. C,E,G b. D,E,F c. C,D,F d. C,E,F e. C,G,F


Q.4) D could have come third in which of the following races?
a. Race 1 b. Race 3 c. Race 4 d. Race 5 e. cannot be determined


Q.5) Suppose if C had 6 points and E had 7 points while the points of the rest of the Bikes remain unchanged then E could’ve come second in
a. One race b. Two races c. At most one race d. At most 2 races e. cannot be determined

Keep Rockin...n...Keep Solvin

answers
1 F stands 2nd in race 4 option b)
2 G/E can be 3:1 or 1:3 so cannot be determined exactly option d)
3.its option a) as C , E, G are the rankers their order can be C/E/G or C/G/E but order is immaterial to the question
4. D comes third in race 2 and race 4 so option C
5 .if the points get rearranged either E can come 2nd in 0 race or in 2 races
so option d

[satanica]

Originally Posted by naresh007

Hey Puys,


Question.No: 17th -- Motor Bike Race Tournament

First Race Point Distribution
A-5, B-0, C-3, D-0, E-1

Second Race Point Distribution
B-5, C-0, D-1, E-0, F-3

Third Race Point Distribution
C-5, D-0, F-0 (E and G's points cannot be determined)

Fourth Race Point Distribution
D-1, E-0, F-3, G-0, H-5

Fifth Race Point Distribution
F-0, H-5, I-0 (E and G's points cannot be determined)

Q1
Ans. b

Q2
Ans. d

Q3
Ans. a (considering 'some order' as any order)

Q4
Ans. c

Q5 (in doubt of the language of the question)
Ans. b or d
(only two scenarios are possible for E i.e. 7 = 5+1+1 = 3+3+1)

[Iota]

Originally Posted by naresh007

Hey Puys,


Find my today's Question.No: 17th -- Motor Bike Race Tournament

Keep Rockin...n...Keep Solvin

1. F gets 3 points, so 2nd --> option (b).
2. ratio can be 3:1 and 1:3 -> so can't be determined --> option (c).
3. C,G,E option --> (a).
4. Race #4 ; option -->C.
5. at most 2 races ;option -->d.