official quant thread for cat08

[MaskedMenace]

Originally Posted by rahulshaitan

shivam bhai please cross check the answer for 5. i m getting the answer as 82

please check the underlined in your ans no.5 solution and correct me if i m wrong

its getting 89 only..9^9 -> (10-1)^9-> only 9c8*10 -1 is nt divisible..so 89

[rahulshaitan]

Originally Posted by shivam_01

can u post ur approach
i checked mine as well as with scci calci
its coming as 89 only ....

Am i wrong somewhere ??

sorry i did a cal mistake
the answer is coming out to be 90 only

[dare2]

@shivam
well done for that logicians problem..

now my question..

Long ago, there was a king who had six sons. The king possessed a huge amount of gold, which he hid carefully in a building consisting of a number of rooms. In each room there were a number of chests; this number of chests was equal to the number of rooms in the building. Each chest contained a number of golden coins that equaled the number of chests per room. When the king died, one chest was given to the royal barber. The remainder of the coins had to be divided fairly between his six sons.

how many coins are left out?

1. 1
2. 3
3. 4
4. none of these
5. cannot be determined

[MaskedMenace]

Originally Posted by rahulshaitan

shivam Bhai Please Cross Check The Answer For 5. I M Getting The Answer As 82

Please Check The Underlined In Your Ans No.5 Solution And Correct Me If I M Wrong

9^9 = 729^3 = 29^3 = 41*29 =89

[MaskedMenace]

Originally Posted by dare2

@shivam
well done for that logicians problem..

now my question..

Long ago, there was a king who had six sons. The king possessed a huge amount of gold, which he hid carefully in a building consisting of a number of rooms. In each room there were a number of chests; this number of chests was equal to the number of rooms in the building. Each chest contained a number of golden coins that equaled the number of chests per room. When the king died, one chest was given to the royal barber. The remainder of the coins had to be divided fairly between his six sons.

how many coins are left out?


1. 1
2. 3
3. 4
4. none of these
5. cannot be determined

is it none of these ?....as it is to b divided fairly ...

[HYgoldking]

Originally Posted by dare2

@shivam
well done for that logicians problem..

now my question..

Long ago, there was a king who had six sons. The king possessed a huge amount of gold, which he hid carefully in a building consisting of a number of rooms. In each room there were a number of chests; this number of chests was equal to the number of rooms in the building. Each chest contained a number of golden coins that equaled the number of chests per room. When the king died, one chest was given to the royal barber. The remainder of the coins had to be divided fairly between his six sons.

how many coins are left out?

1. 1
2. 3
3. 4
4. none of these
5. cannot be determined

Answer is (4) none of these

(N^3-N) % 6 = 0

[dare2]

Originally Posted by MaskedMenace

is it none of these ?....as it is to b divided fairly ...

right answer..

remainder problems are on their peak 2day.. so posted one more..

[proletarian]

Originally Posted by dare2

@shivam
well done for that logicians problem..

now my question..

Long ago, there was a king who had six sons. The king possessed a huge amount of gold, which he hid carefully in a building consisting of a number of rooms. In each room there were a number of chests; this number of chests was equal to the number of rooms in the building. Each chest contained a number of golden coins that equaled the number of chests per room. When the king died, one chest was given to the royal barber. The remainder of the coins had to be divided fairly between his six sons.

how many coins are left out?

1. 1
2. 3
3. 4
4. none of these
5. cannot be determined

if n is the number of rooms=chests=coins in a chest
then no: of coins left out =n^3 -n =n(n-1)(n+1) which is always divisible by 6
So option 4

[poojadatta]

A small break from remainder.... coz I need to know how to do this question

Find the maximum value of (7-x)^4(2+x)^5.

Please post your approach also.....

(Posted questions in VA thread too...sorry for saying this in quant thread but poor va thread no activity there )

[MaskedMenace]

Originally Posted by poojadatta

A small break from remainder.... coz I need to know how to do this question

Find the maximum value of (7-x)^4(2+x)^5.

Please post your approach also.....

(Posted questions in VA thread too...sorry for saying this in quant thread but poor va thread no activity there )

is it zero ?(No it is not Zero)