official quant thread for cat08

[implex]

Originally Posted by vivek417

Implex...where can we post the answers???? is there anything on the page?? I can just see d questions??


Thanks
Vivek

You can post your answers, by posting your keys using the comment button !!
Best of Luck
Cheers!

[shivam_01]

Originally Posted by implex

You can post your answers, by posting your keys using the comment button !!
Best of Luck
Cheers!

@Implex it would be nice if u can post the question here

My office firewall has blocked the bloging sites so unable to open it ....

[MaskedMenace]

Use the Below Attachment (next post)...

[Varun Khullar]

Originally Posted by shivam_01

@Implex it would be nice if u can post the question here

My office firewall has blocked the bloging sites so unable to open it ....

attachment for the test

[implex]

Originally Posted by shivam_01

@Implex it would be nice if u can post the question here

My office firewall has blocked the bloging sites so unable to open it ....

I did not want to post the problems directly as I want it to be taken as a test!!
There is a special reason and a special marking scheme for this paper!!

Anyways
Use the doc Varun has attached

[shivam_01]

Originally Posted by implex

I did not want to post the problems directly as I want it to be taken as a test!!
There is a special reason and a special marking scheme for this paper!!

Anyways
Use the doc Varun has attached

Ok Implex

All will paste the answers tommorrrow and discussion will resume then on this thread after monday noon

Till then no body please post the explanations here

[cittu]

hi friends! m new to this community
seek help...how to find the remainder when (2^133) is divided by 133

[shivam_01]

Originally Posted by cittu

hi friends! m new to this community
seek help...how to find the remainder when (2^133) is divided by 133

@ Chittu welcome to PG

answer is 128

if correct i will post my approach

[linksuresh]

Originally Posted by cittu

hi friends! m new to this community
seek help...how to find the remainder when (2^133) is divided by 133

guess the ans shd be 128
133 = 7*19
euler(133) = 6*18 = 108
so 2^25 mod (7*19)
7x+2 = 19y+14 ..
solving.. y=6..
133k + 128
hence remainder is 128

[shivam_01]

Originally Posted by shivam_01

@ Chittu welcome to PG

answer is 128

if correct i will post my approach

In this case take the
2^133 mod 7 and 2^133 mod 19 sepeartely

and the first one gives the remainder as 2 and the second one as 14

so we have
7x+2=19y+14
which gives the answer as 128

Am i correct ??