official quant thread for cat08 - Page 762
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Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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Re: official quant thread for cat08
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parthatayi
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Re: official quant thread for cat08 - 20-08-2008, 03:36 PM

Quote:
Originally Posted by dheeraj.del View Post
Suppose 2 more people were invited - x& y -
The combinations for dance are -
Amrita & x
Amrita & y
Satyam & x
Satyam & y
x & y
i.e. total of 5 combinations. this is satisfied 3n -7 i.e. 3*4 - 7 = 5. hence the answer
how abt when n=7...the answer should be 20...but the expression 3n-7 does not yield 20 for n=7

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Re: official quant thread for cat08
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masoom
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Re: official quant thread for cat08 - 20-08-2008, 03:58 PM

hey guys.. i got confused big tym on this problem..

area of the bounded region by :

|x+y|+|x-y|=4...


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Re: official quant thread for cat08
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Fuzon
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Re: official quant thread for cat08 - 20-08-2008, 04:07 PM

Quote:
hey guys.. i got confused big tym on this problem..

area of the bounded region by :

|x+y|+|x-y|=4...
Answr : Is the answer 8 units??

Reasoning:

LHS and RHS wd be same in case of foll values

(2,2),(-2,-2),(2,-2),(-2,2)

So the fig formed is a square with diagonal of 4 and side of 2Root2

Thus area bound is (2root2)^2 = 8 units ....

answrs plz
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 20-08-2008, 04:11 PM

Quote:
Originally Posted by Fuzon View Post
Answr : Is the answer 8 units??

Reasoning:

LHS and RHS wd be same in case of foll values

(2,2),(-2,-2),(2,-2),(-2,2)

So the fig formed is a square with diagonal of 4 and side of 2Root2

Thus area bound is (2root2)^2 = 8 units ....

answrs plz
yeah answer is 8 sq units
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 20-08-2008, 04:11 PM

Quote:
Originally Posted by masoom View Post
hey guys.. i got confused big tym on this problem..

area of the bounded region by :

|x+y|+|x-y|=4...


is it 8 square units?
   
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Re: official quant thread for cat08
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v-factor
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Re: official quant thread for cat08 - 20-08-2008, 04:12 PM

Quote:
Originally Posted by masoom View Post
hey guys.. i got confused big tym on this problem..

area of the bounded region by :

|x+y|+|x-y|=4...
The area should be bounded between lines x=+2, x=-2, y=+2 and y=-2
16 square units.


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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 20-08-2008, 04:13 PM

Quote:
Originally Posted by Fuzon View Post
Answr : Is the answer 8 units??

Reasoning:

LHS and RHS wd be same in case of foll values

(2,2),(-2,-2),(2,-2),(-2,2)

So the fig formed is a square with diagonal of 4 and side of 2Root2

Thus area bound is (2root2)^2 = 8 units ....

answrs plz
answer is ryt..

yups these 4 points will satisfy the equation..

but how do u proceed further to decide that the square will be of diagonal 4...


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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 20-08-2008, 04:19 PM

Quote:
Originally Posted by masoom View Post
hey guys.. i got confused big tym on this problem..

area of the bounded region by :

|x+y|+|x-y|=4...
I am getting the side as 4 unit and the area as 16 units.
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 20-08-2008, 04:20 PM

Quote:
Originally Posted by masoom View Post
answer is ryt..

yups these 4 points will satisfy the equation..

but how do u proceed further to decide that the square will be of diagonal 4...


joining the four points gives 4 triangles with base and height 2.
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 20-08-2008, 04:24 PM

Quote:
Originally Posted by dare2 View Post
joining the four points gives 4 triangles with base and height 2.

yups in that way i got it..

but i had a silliest of doubt...

do all the points on the line joining these points satisfy the given equation...


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