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| official quant thread for cat08 -
27-12-2007, 08:10 PM
hi frnds
as cat 07 is over and there r puys who want to gear up for cat 08....i am starting this official quant thread for cat 08....i request the administrator and other puys to make it an official thread.
best of luck
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| Re: official quant thread for cat08 -
27-12-2007, 08:13 PM
Quote:
Originally Posted by convivial  hi frnds
as cat 07 is over and there r puys who want to gear up for cat 08....i am starting this official quant thread for cat 08....i request the administrator and other puys to make it an official thread.
best of luck
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| Re: official quant thread for cat08 -
27-12-2007, 09:44 PM
Quote:
Originally Posted by convivial one more thing guys.....plz start posting questions |
ok frnds..here's first one 4m me.....an easy one just 2 start up 1.find the number of negative integers which satisfy the equation mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3 | | | | | The Following 2 Users Say NO Thank You to convivial For This Un-useful Post: | | | The Following 2 Users Say Thank You to convivial For This Useful Post: | | | | | |
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| Re: official quant thread for cat08 -
06-01-2008, 12:42 AM
Quote:
Originally Posted by convivial ok frnds..here's first one 4m me.....an easy one just 2 start up
1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3 |
Ans is 2 values....-1 and -2.
Just plug in the values..correct me if I'm wrong | | | | | | | |
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| Re: official quant thread for cat08 -
06-01-2008, 11:24 PM
Quote:
Originally Posted by convivial ok frnds..here's first one 4m me.....an easy one just 2 start up
1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3 | Is the answer 0? I could not find any negative integer till -3 to satisfy this condition and as the value of x decreases further the difference between the RHS and LHS values increases. Thus there could not be any any other value beyond -3.
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| Re: official quant thread for cat08 -
07-01-2008, 12:51 AM
Quote:
Originally Posted by convivial ok frnds..here's first one 4m me.....an easy one just 2 start up
1.find the number of negative integers which satisfy the equation
mod(x+1/x)+mod(x+1)=(x+1)^2/mod(x)
a)0
b)1
c)2
d)3 |
is it 0????
Cheers  ,
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| Re: official quant thread for cat08 -
07-01-2008, 01:26 AM
Quote:
Originally Posted by bubai376 is it 0???? | the answer is 1 i.e option (b)
Last edited by convivial; 07-01-2008 at 01:29 AM.
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| Re: official quant thread for cat08 -
07-01-2008, 01:48 AM
Guys Guys.... easy yaaro.... please follow the rules of the previous years Official Quant threads... like no posting of reply before certain fixed time daily....( you can refer to them on previous official threads...) otherwise, there is no use of having a chat like thread b/w 4-5 people solving as soon as questions are posted, as that will not help weaker students.... wanna be official, then act like one. | | | | | The Following 13 Users Say Thank You to HeadsMan For This Useful Post: | asterias (17-06-2008), bubai376 (11-01-2008), charan4ever (09-06-2008), jagannath_4all (27-04-2008), karthik_ceg (05-06-2008), mahi101987 (26-04-2008), maverick_robin (09-01-2008), pavanpadekal (13-05-2008), rahulsi (01-09-2008), rmbt (09-01-2008), rosh! (02-04-2008), saran_raj (30-06-2008), subhamita (06-06-2008) | | | | |
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| Re: official quant thread for cat08 -
07-01-2008, 02:01 AM
Quote:
Originally Posted by HeadsMan Guys Guys.... easy yaaro.... please follow the rules of the previous years Official Quant threads... like no posting of reply before certain fixed time daily....( you can refer to them on previous official threads...) otherwise, there is no use of having a chat like thread b/w 4-5 people solving as soon as questions are posted, as that will not help weaker students.... wanna be official, then act like one. |
ok frnd....thanx 4 ur advise...will keep this in mind...carry on | | | | | The Following User Says Thank You to convivial For This Useful Post: | | | | | |
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| Re: official quant thread for cat08 -
08-01-2008, 09:57 AM
Can u please explain how the answer is 1.
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