official quant thread for cat08

[masoom]

Originally Posted by MaskedMenace

1) Let S = (SQroot(100)-SQroot(99)+SQroot(98 )-SQroot(97)+...+SQroot(2)-SQroot(1)); then S lies in

(a) (3,4) (b) (4,5) (c) (5,6) (d) none

Taking this as (sqrt(100)-sqrt(1))/2 -->4.5
so s lies in between (4,5)

dude.. why u took the mean of the extremes...
i mean it will give us a rough idea... but wats the logic behind it..
coz i did it a bit diffrently..

[Varun Khullar]

please solve this one :2) If x = (0.12345678910111213............) and y = 1/x find x + y Please give answer in the form of p/q


shivam champermowne constant ko cat main dalna band kar,totally irrelevant
we aren't studying fractals

Champernowne Constant -- from Wolfram MathWorld

1/10 +2/100 +3/1000+........so on

[hismajesty143]

Originally Posted by masoom

please solve this one :2) If x = (0.12345678910111213............) and y = 1/x find x + y Please give answer in the form of p/q

This is the fastest way which I know:

Find out 1/.1234 = 8.103
Now if the divisor increases, the quotient will only reduce. So, we can take the quotient to be roughly 8.1

Now add: 8.1+.1234567 = 8.2234567
In p/q we have 82234567/10000000

Now you can compare with the options, and you'll surely get the answer.

[masoom]

Originally Posted by Varun Khullar

please solve this one :2) If x = (0.12345678910111213............) and y = 1/x find x + y Please give answer in the form of p/q


shivam champermowne constant ko cat main dalna band kar,totally irrelevant
we aren't studying fractals

Champernowne Constant -- from Wolfram MathWorld

1/10 +2/100 +3/1000+........so on

@ shivam bhai.. baap re baap...
itna bhayanak constant.. naam bhi yaad nahi ho raha iska ..
itna torture mat kar yaar

[shivam_01]

Originally Posted by Varun Khullar

please solve this one :2) If x = (0.12345678910111213............) and y = 1/x find x + y Please give answer in the form of p/q


shivam champermowne constant ko cat main dalna band kar,totally irrelevant
we aren't studying fractals

Champernowne Constant -- from Wolfram MathWorld

1/10 +2/100 +3/1000+........so on

i tell u the answer to this question is totally independent upon the Champernowne Constant -- from Wolfram MathWorld numbers

wait i will post the solution...

anyway the questions are not framed by me varun bhai

[Varun Khullar]

Originally Posted by Unhappy_Demon

A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is more than m-d?

A. 16%
B. 32%
C. 48%
D. 84%
E. 92%


IF you give me a set of data

I know, how to calculate mean.
I know,how to calculate median.
I know,how to calculate standard deviation.


BUT still , i don't understand the above question properly ...in fact the percentage wala term is killer words to me .

can anybody explain the question with a simple example ?

and finally solve this problem ?

OA later

84% is the answer, bell curve man le,
68/2 = 34
50+34 = 84 .. answer

[Varun Khullar]

Originally Posted by shivam_01

i tell u the answer to this question is totally independent upon the Champernowne Constant -- from Wolfram MathWorld numbers

wait i will post the solution...

anyway the questions are not framed by me varun bhai

ha yaar solvable tho hai.. paar mujhe college ke dino ki yaad agayi dekh kar fractals walli book ki yaad..

1/8+1/9 ...is the continued fraction for it
i think we might have to approximate for this.
This number is like pi like we can't really say its 22/7 we just approximate it to be

approx 8.1 and .. 8.22345......

[MaskedMenace]

Originally Posted by masoom

dude.. why u took the mean of the extremes...
i mean it will give us a rough idea... but wats the logic behind it..
coz i did it a bit diffrently..

ok...I just took the mean of extremes...

sqrt(100) -sqrt(99)+sqrt(9 ....+sqrt(2)-sqrt(1)
how did yu do ? no solid funda behind it...

[MaskedMenace]

7) Find the last four digits in the binary expansion of the
number

7654823986734573975876926.

anybody explain this....
shivam bhai...answers post karo..

[Varun Khullar]

Originally Posted by MaskedMenace

7) Find the last four digits in the binary expansion of the
number

7654823986734573975876926.

anybody explain this....
shivam bhai...answers post karo..

1110 i think

926 can be written 2^9+2^8+2^7+2^4+2^3+2^2+2^1+0