[MaskedMenace]

Originally Posted by HYgoldking

A = 1/36

B = (6*5)/(36*36) = 5/(6*36) = 5/216 B' = 211/216

probability that A will win = A*B' = 1/36 * 211/216

Yeah..this is the ryt method..
I tried it like this...

for B getting two consecutive 7's...
(1,6)
(2,5)
(3,4)
(4,3)
(5,2)
(6,1)
In the first attempt If he gets any one of this....this is 6/36
In the nxt attempt.......this is 6/36
so.....1/36

so...probability of a winning is A * B'(since independent)
1/36*(1-1/36) = 35/1296

[raghav507]

hi,
i am getting 35/216...
by using the infinite GP method...
is it correct...

[MaskedMenace]

Originally Posted by raghav507

hi,
i am getting 35/216...
by using the infinite GP method...
is it correct...

raghav ...how to use Infinite gp here ? ..can u pls elaborate ?

[dare2]

Originally Posted by raghav507

hi,
i am getting 35/216...
by using the infinite GP method...
is it correct...

sorry again..

[raghav507]

Originally Posted by MaskedMenace

raghav ...how to use Infinite gp here ? ..can u pls elaborate ?

hi,
i have used the following hypothesis...
A wins in turn 1 (means we get 12)

A doesn't win in turn 1 (means we don't get 12)
B wins in turn 2 (means we get 7)

A doesn't win in turn 1 (means we don't get 12)
B doesn't win in turn 2 (means we don't get 7)
A wins in turn 3 (means we get 12)

and so on...
we get an infinite GP...

i don't know whether this is the correct approach but just had a try...

[raghav507]

Originally Posted by dare2

sorry again..

bhai ab toh answer bata hi do...
with the method...

[MaskedMenace]

Originally Posted by dare2

sorry again..

ok raghav...thanx...
@dare...wht abt mine ? i edited d post..

[dare2]

Originally Posted by raghav507

hi,
i am getting 35/216...
by using the infinite GP method...
is it correct...

also, 35/216 is too less.. dont u think so??
i thing u guys misread the question..

[shivam_01]

Originally Posted by dare2 (official quant thread for cat08)
one more.. easy one..

Two students play a game based on the total roll of two standard dice. Student A says that a 12 will be rolled first. Student B says that two consecutive 7s will be rolled first. The students keep rolling until one of them wins. What is the probability that A will win?

@Dare

yaar ye consecutive 7s aane ke kya matlab hain can anyone explain me

approach is

Lets us supppose A win

A + A'B'A + A'B'A'B'A + A'B'A'B'A'B'A + ......... upto infinity

where A is the proability of winning of A and B is the proability of winning of B and
A' is the proability of losing of A and B' is the proability of losing of B and

[raghav507]

Originally Posted by shivam_01

@Dare

yaar ye consecutive 7s aane ke kya matlab hain can anyone explain me

approach is

Lets us supppose A win

A + A'B'A + A'B'A'B'A + A'B'A'B'A'B'A + ......... upto infinity

where A is the proability of winning of A and B is the proability of winning of B and
A' is the proability of losing of A and B' is the proability of losing of B and

hi shivam,
i have used the same approach...
but some how kuch gadbad ho raha hai...

@dare2
what is meant by consecutive 7s?
does it mean - once A gets 7 then B shud also get 7 to win...? or anything else...?