[prakharc]

Originally Posted by dare2

10 sportmen are to be selected for two teams consisting of 6 members each. if there are 3 members common to both team, how many total number of ways are there for selecting the team?

10C3 * 7C1 * (6C3/2) = 8400 ways.......??

[prakharc]

Originally Posted by dare2

lets try this one from implex's test.

9) Let A and B be two points on the plane. Let S be the set of points P such that PA^2+PB^2 is at most 10. Find the area of S

A) 2π
B) π
C) 4π
D) 6π
E) none of these

A and B will be end points of diameter of a circle.... So PA^2+PB^2 = (Dia)^2 => Dia= sqrt(10)
So area of S= 10(pi)/4 = 2.5 pi

[hi.shivani]

Originally Posted by dare2

10 Sportmen Are To Be Selected For Two Teams Consisting Of 6 Members Each. If There Are 3 Members Common To Both Team, How Many Total Number Of Ways Are There For Selecting The Team?

10c3*7c3=4200

[H.U.C]

Is the Answer is 2.
We can solve it by using remainder theorem. Take 32^32 first , and express it as
(2^3 *2^2)^32. Express 7 as 2^3 -1 . Now use remainder theorem .Put 2^3 = 1 . U will be left with 2^64 .Express i as (2^63*2) ....here 2^63 can be break up into 2^3 .So remaining will be 2.
Hence 2 .Pls let me knoe if i m wrong somewhere .

[H.U.C]

Cpl of questions on Number systems:

1. whats the remainder when 5^7^9^7^5 is divided by 18?
a. 12
b. 11
c. 5
d. 7
e. 10

2. whats the remainder when 32^32^32^32^32^.... infinity is divided by 7?
a. 3
b. 5
c. 4
d. 2
e. 1

Sol1 :- Is answer is 5 .Here we can use pattern method .We see that when we try to divide higher power of 5 with 18 we get a pattern which repeats itself after 6 . IN order to find pattern divide till 5^3 .Remainder when we divide 5^3 with 18 is -1 , hence we can conclude that pattern will repeat after 6 .
So now task is simplified .
we just need to find what is the remainder when 7^5^..... is divided by 6 .
We can express 7^5... as (6+1)^5^.... .Hence remainder is 1 .
So answer should come from 5^1 /18 .remainder is 5
Sol2 :-Is the Answer is 2.
We can solve it by using remainder theorem. Take 32^32 first , and express it as
(2^3 *2^2)^32. Express 7 as 2^3 -1 . Now use remainder theorem .Put 2^3 = 1 . U will be left with 2^64 .Express i as (2^63*2) ....here 2^63 can be break up into 2^3 .So remaining will be 2.
Hence 2 .Pls let me knoe if i m wrong somewhere .

[Varun Khullar]

Originally Posted by dare2

lets try this one from implex's test.

9) Let A and B be two points on the plane. Let S be the set of points P such that PA^2+PB^2 is at most 10. Find the area of S

A) 2π
B) π
C) 4π
D) 6π
E) none of these

its area inside an ellipse
a = root b = 2root2
piab = 4pi

[poojadatta]

Originally Posted by prakharc

Total distance covered by rear ends= 300 + 600 + 600 = 1500=1.5kms
Time taken = 1.5/(90+72)= 33 1/3 secs
So distance = (72000/3600)*100/3 - 300 = 366 2/3 m

can you tell me what actually question is asking for please? and why u took
So distance = (72000/3600)*100/3 - 300 = 366 2/3 m

[cos_sec]

32^32^32^32^... infinity divided by 7

Remainder is 4.:argue:

Option c

[cos_sec]

Solution for the first one is correct..

Its 5

Second needs some more thinking...

[dare2]

Originally Posted by Varun Khullar

its area inside an ellipse
a = root b = 2root2
piab = 4pi

y ellipse?? n y not a cirlce?