official quant thread for cat08

[Fuzon]

Thanks but can I know why M can take only even values is it because the value of the D should be integer.

M can take only even values as the result shd be divisible by 12 which does not have any odd multiple , and the number from which it has to be subtracted is even 452-31M, so M can be even ONLY !

Hope im clear this time !

[maverick_srikan]

Puys,

Need some help.

Could someone temme the formula for finding the number of permutations for:

1. AABB
2. AABC

Thanks!

[piyushpth]

Originally Posted by ashutosh84

guys A Ques To Stimulate Ur Gray Cells:

1+1/2+1/3+1/4+1/5+.......infinity

Does this series diverge? 1 + 1/2 + 1/3 + 1/4 + ... = 1 + (1/2) + (1/3+1/4) + (1/5+1/6+1/7+1/8 ) + (1/9+1/10+...+1/16) + ........ >= 1 + 1/2 + 1/2 + 1/2 + .......... It follows that the sum can be made as large as we please by taking enough terms. In fact this series diverges quite slowly. Does anybody has some other opinion

[piyushpth]

Originally Posted by maverick_srikan

Puys,

Need some help.

Could someone temme the formula for finding the number of permutations for:

1. AABB
2. AABC

Thanks!

For AABB it should be factorial(4)/(factorial(2)*factorial(2)) = 6 And for AABC it should be factorial(4)/factorial(2) = 12

[maverick_srikan]

Originally Posted by piyushpth

For AABB it should be factorial(4)/(factorial(2)*factorial(2)) = 6 And for AABC it should be factorial(4)/factorial(2) = 12

Could you give me the general formula for the same?
for AABB, the formula would be 4!/2!*2! because there are 2 items which repeat themselves?

[pallaviagrawal]

Originally Posted by maverick_srikan

Could you give me the general formula for the same?
for AABB, the formula would be 4!/2!*2! because there are 2 items which repeat themselves?

the numerator has the total no of items,and the denominator has the total no of times a particular item is repeated.
in AABC numerator is given by 4!(2 A,one B ,one C) and denominator is given by 2!(two A)*1(one B)!*1(one C)!

[pallaviagrawal]

Originally Posted by piyushpth

Does this series diverge? 1 + 1/2 + 1/3 + 1/4 + ... = 1 + (1/2) + (1/3+1/4) + (1/5+1/6+1/7+1/8 ) + (1/9+1/10+...+1/16) + ........ >= 1 + 1/2 + 1/2 + 1/2 + .......... It follows that the sum can be made as large as we please by taking enough terms. In fact this series diverges quite slowly. Does anybody has some other opinion

yes the sum of the series tends to infinity..

[maverick_srikan]

Originally Posted by pallaviagrawal

the numerator has the total no of items,and the denominator has the total no of times a particular item is repeated.
in AABC numerator is given by 4!(2 A,one B ,one C) and denominator is given by 2!(two A)*1(one B)!*1(one C)!

Thanks a lot!

[poojadatta]

Originally Posted by maverick_srikan

Puys,

Need some help.

Could someone temme the formula for finding the number of permutations for:

1. AABB
2. AABC

Thanks!

hi
The general formula would look like this if there are n items and among them if there are p similar items and q similar items and remaining items are different for each other then the formula will be n!/p!*q!.
i,e AABB n=4 (AABB) p=2(AA) q=2(BB) => 4!/2!*2!
AABC n=4 p=2(AA) reaming two are different from other items =>4!/2!.

Hey if am wrong anywhere let me know.

[poojadatta]

helpie

If a naughty bird having speed of 120 km/hr sitting on train1 having speed of 60km/hr. Now if the bird travels towards train2 whose speed is 60km/hr and is coming from the opposite side what would be the distance traveled by the bird when it reaches the train1 second time(to and from from train1 to train2). The distance between two train in the beginning is 12km.