official quant thread for cat08

[hellion]

Originally Posted by implex

17+3+13+3+7=40
this is the minimum time
(17,3) go
(3) returns
(13,3) go
(3) returns
(3,7) go

shouldn't it be 17+7 = 24?
Why is (3) returning?
Or did I misinterpret the question again?

[selebratinglife]

Originally Posted by implex

yeah right but what's the approach!!

I've done it by what you can term as trial & error..And a bit of common sense since x and y are integers..since (4,4) is obvious..checked it for 1,2,3 and -1,-2,-3

[implex]

Originally Posted by hellion

shouldn't it be 17+7 = 24?
Why is (3) returning?
Or did I misinterpret the question again?

There is just too much i read in the question, there are many questions where there is one torch or something My mistake
it should be 17+7

[implex]

Originally Posted by selebratinglife

I've done it by what you can term as trial & error..And a bit of common sense since x and y are integers..checked it for 1,2,3 and -1,-2,-3 since (4,4) is obvious..

hmmmm, the value on rhs was small if it was big, you would have been in trouble!

[selebratinglife]

Originally Posted by implex

98 ) Find the number of solutions in real numbers x^4+|x|=10
a) 0 b) 1 c) 2 d) 4 e) 8

Is it 2?Consider f(x)=x^4+|x|-10=0,f(1) is negative and f(2) is +ve . Also f(-1) is -ve and f(-2) +ve

[selebratinglife]

Originally Posted by implex

hmmmm, the value on rhs was small if it was big, you would have been in trouble!

Right!..And what's the official/your approach..

[implex]

Originally Posted by selebratinglife

Right!..And what's the official/your approach..

x=2y/(y-2) this will give only 5 solns for integers!!

y-2=+-2y
y-2=+-2
y-2=+-1
y-2=+-4

[Hi2All]

Originally Posted by hellion

No of males -> m No of females->f

m = 2(f-15)
f = 5(m-45)
m = 2[5m-240]
m = 53.333

Don't know where i have gone wrong

Friend..
U hav gone wrong in ur first statement itself..

Let No of males=>m No of females=>f

If 15 females are absent,remaining females=f-15
So,according to the question...

f-15=2m (This is the place where u mis understood the question..)
f-2m=15----(1)

If 45 males are absent,then remaining males are=m-45
f=5(m-45)
f-5m=-225---(2)

Subtracting (1)-(2)
3m=240
m=80

f-2m=15
f-160=15
f=175


Rgds
Sidh...

[selebratinglife]

Originally Posted by implex

96 Find the number of positive integer triplets(a,b,c) that satisfy abc=4(a+b+c) with a<b<c
a) 4 b) 5 c) 6 d)7 e) none of these

No solution?

[amitkrsingh]

Originally Posted by implex

New Problem!

Is answer e)none of these