official quant thread for cat08

[aditya_g]

Hello all,

can anyone help me out in solving this question?

How to find whether the number PQR84 is a perfect square or not?

Is thr any method to find the answer????????

thanks in advance.

aditya

[MaskedMenace]

Originally Posted by aditya_g

Hello all,

can anyone help me out in solving this question?

How to find whether the number PQR84 is a perfect square or not?

Is thr any method to find the answer????????

thanks in advance.

aditya

22^2 =>484

v need five digit number ending with 84

(100 + 22 )^2 = 10000 + 4400 + 484

14884 it is of the form PQR84 so its a perfect square

also v can have many ... just append number in hundred's place for a number which can end in 84

22^2 ends with 84 => 122^2 ==>PQR84 , 222^2 ==> PQR84

28^2 ends with 84 => 128^2 ==> PQR84 , 228^2 ==> PQR84

72^2 ends with 84 => 172^2 ==> PQR84 , 272^2 ==> PQR84 n soo...

[Unhappy_Demon]

Originally Posted by HYgoldking

(1)There are 12 even integers greater than x and less than y.

x=1 y=25 (2 to 24 --> 12 even integer) odd integer (3-23) --> 11
x=0 y=26 (2 to 24 --> 12 even integer) odd integer (1-25) --> 13

(2)there are 24 integers greater than x and less than y

x=1 y=26 (3-25 --> 12 odd integer)
x=2 y=27 (3-25 --> 12 odd integer)
x=3 y=28 (5-27 --> 12 odd integer)

B if statement (2) ALONE is sufficient to answer the question but statement (1) alone is not sufficient;

well done

OA is B indeed

[naresh007]

Hey puys try this problem:

Q) The roots of the equation x^4 + mx^3 + 71x^2 + px + q = 0 are in AP with common difference = 1. Find p+q , if m is -ive.

a) -22 b) -34 c) -24 d) -28 e) None


Hoping for Rahul's approach

[prakharc]

Originally Posted by naresh007

Hey puys try this problem:

Q) The roots of the equation x^4 + mx^3 + 71x^2 + px + q = 0 are in AP with common difference = 1. Find p+q , if m is -ive.

a) -22 b) -34 c) -24 d) -28 e) None


Hoping for Rahul's approach

roots :- a,a+1,a+2,a+3

Taking two at a time sum = 71

6a^2 + 18a + 11=71
=> a=2 ......roots are 2,3,4,5

p=-154
q=120

p+q= -34 ans

[raghav507]

Originally Posted by naresh007

Hey puys try this problem:

Q) The roots of the equation x^4 + mx^3 + 71x^2 + px + q = 0 are in AP with common difference = 1. Find p+q , if m is -ive.

a) -22 b) -34 c) -24 d) -28 e) None


Hoping for Rahul's approach

hi,
i am getting -34 as answer...

[naresh007]

Yeap..right ans!
Actually,i did a stupid mistake in middle of calculation in hurry...i.e. a(a+1) as a^2 + 1..so endup with irrational roots..how come ans'll be -34..so, posted..

Originally Posted by prakharc

roots :- a,a+1,a+2,a+3

Taking two at a time sum = 71

6a^2 + 18a + 11=71
=> a=2 ......roots are 2,3,4,5

p=-154
q=120

p+q= -34 ans

[HYgoldking]

If xyz = 450 than what is the maximum possible value of 3x+4y+5z?
If xyz = 450 than what is the minimum possible value of 3x+4y+5z?

[rocha]

Originally Posted by HYgoldking

Q1. )If xyz = 450 than what is the maximum possible value of 3x+4y+5z?
Q2. )If xyz = 450 than what is the minimum possible value of 3x+4y+5z?

For second one im getting 90 as the answer...
The first one , m getting 2257

[KillFRenzy]

Originally Posted by rocha

For second one im getting 90 as the answer...
The first one , m getting 2257

Approach??