official quant thread for cat08 - Page 11
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Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 12:57 PM

Quote:
Originally Posted by stalwart_itsme View Post
thanks bro... i missed out... its a squre with side 4 units ... so area 16...you got it...
Guys i want some explaination, even though my doubt is very pitty. if we take co-ordinates as (2,0),(0,2),(-2,0),(0,-2) this also satisfies the equation, also co-ordinates (2,1) satisfies and even (2,2) satisfies, so what made us to decide on the co-ordinates to be (2,2)?
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 01:14 PM

hi

hope this image will help u, purple ones are the co-ordinates given by me and red ones by stalwart.

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Originally Posted by IIM maniac View Post
Guys i want some explaination, even though my doubt is very pitty. if we take co-ordinates as (2,0),(0,2),(-2,0),(0,-2) this also satisfies the equation, also co-ordinates (2,1) satisfies and even (2,2) satisfies, so what made us to decide on the co-ordinates to be (2,2)?
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 01:47 PM

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Originally Posted by parmindersaluja View Post
hi

hope this image will help u, purple ones are the co-ordinates given by me and red ones by stalwart.
I am able to come to these figures but one thing i am not able to understand is even though three sets of co-ordinates satisfies the equation, so how could (2,2) be the unique co-ordinates?? Sorry if my query if very silly but still it is.
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 01:55 PM

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Originally Posted by IIM maniac View Post
Guys i want some explaination, even though my doubt is very pitty. if we take co-ordinates as (2,0),(0,2),(-2,0),(0,-2) this also satisfies the equation, also co-ordinates (2,1) satisfies and even (2,2) satisfies, so what made us to decide on the co-ordinates to be (2,2)?
dude ... the coordinates (2,0),(0,2),(-2,0),(0,-2) does not cover the full area... full area occupied by the eqation |x+y|+|x-y|=4 is covered only when the points (2,2)(2,1),(2,-2),(-2,2),(2,-1),(-2,1) are all considered...

Please correct me if i am wrong...


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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 01:57 PM

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Originally Posted by IIM maniac View Post
I am able to come to these figures but one thing i am not able to understand is even though three sets of co-ordinates satisfies the equation, so how could (2,2) be the unique co-ordinates?? Sorry if my query if very silly but still it is.
because |x+y| + |x-y| = 4, can take values such as (4,0), (0,4), (3,1), (1,3), (2,2)...and their negative counterparts...
now, solving for (x,y) for the extreme cases (4,0), (0,4), (-4,0) and (0,-4) will give u values of x and y which will form a square encompassing all other values.

P.S. if u still have any doubt, dont hesitate to ask.
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 02:07 PM

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Originally Posted by parmindersaluja View Post
because |x+y| + |x-y| = 4, can take values such as (4,0), (0,4), (3,1), (1,3), (2,2)...and their negative counterparts...
now, solving for (x,y) for the extreme cases (4,0), (0,4), (-4,0) and (0,-4) will give u values of x and y which will form a square encompassing all other values.

P.S. if u still have any doubt, dont hesitate to ask.
Thanks for the reply, so you mean to say we should consider the extreme case after which this equation does not get satisfied? is it? or in proper words , we should consider the case or co-ordinates that covers the full range which is in case of (4,0), (0,4), (-4,0) and (0,-4). thats why area is 16, is it?
   
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Re: official quant thread for cat08
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Smile Re: official quant thread for cat08 - 22-01-2008, 02:08 PM

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Originally Posted by stalwart_itsme View Post
The numbers are..

1001
1003
1005
1007
1009
1011
1013
1015
1017
1019
1021
...
...
1191
1193
1195
1197
1199
(since only odd numbers...)
100
so divisible by 3 are 1005,1011,1017...goes on till 1197
so a=1005 d=6 last number = 1197
tn=a+(n-1)*d
1197=1005+(n-1)*6
192=6n-6
n=33...
something went wrong i suppose...... pls help me out...
i am not very much sure but question is saying that every digit in n is odd so i eliminated all the numbers containing 10.. earlier also i was getting the same result but ans does not matched. its a question of CAT 05. have a discussion and come to any conclusion


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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 02:12 PM

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Originally Posted by 80199 View Post
i am not very much sure but question is saying that every digit in n is odd so i eliminated all the numbers containing 10.. earlier also i was getting the same result but ans does not matched. its a question of CAT 05. have a discussion and come to any conclusion
hey i posted this on page 10, anyways please confirm the answer
for all the digits to be odd, the thousands and the hundreds digit needs to be 1 and 1
so 1 + 1 = 2
the other two digits can be 1,3,5,7,9
but the sum should be divisble by 3 so
2 + 4 = 6---possible 2 numbers
2 + 7 = 9 --not possible
2 + 10 = 12---possible 5 numbers
2 + 13 = 15 --not possible
2 + 16 = 18 --possible 2 numbers
so 9 numbers possible
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 02:16 PM

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Originally Posted by 80199 View Post
i am not very much sure but question is saying that every digit in n is odd so i eliminated all the numbers containing 10.. earlier also i was getting the same result but ans does not matched. its a question of CAT 05. have a discussion and come to any conclusion
Kindly check earlier posts as PUYs have solved this question, still FYI we have 9 values for it, 1113, 1119,1131,1137,1155,1173,1179,1191,1197.
   
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Re: official quant thread for cat08
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Re: official quant thread for cat08 - 22-01-2008, 02:19 PM

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Originally Posted by IIM maniac View Post
Thanks for the reply, so you mean to say we should consider the extreme case after which this equation does not get satisfied? is it? or in proper words , we should consider the case or co-ordinates that covers the full range which is in case of (4,0), (0,4), (-4,0) and (0,-4). thats why area is 16, is it?
@parmindersaluja,Can you please comment on this?
   
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