CAT 2007: Quantitative Questions a Day 134 till the end - The Discussions

cloudsonfire

Q>Within a 5X5 table, a box is marked at the intersection of second row and third column. How many rectangles formed by the boxes of the table do not contain the marked box?

im a confused in a table axb , any box marked (p,q) should be unique !!???

priyank12

Hello All,

Joined this thread a bit late.....

Has anyone compiled all the questions discussed here....

I would be highly thankful if anyone can upload the same, coz its difficult for me to go thru all the previous pages..

Thanks in advance!!

Riva_M

Quote:

Originally Posted by krsh.vik

Aarav and Vineet bhai

Please don't get disheartened by the fact that there is not much activity on this thread

I diligently follow the thread and discussions here

I am pretty sure there a lot many following QQAD. You people deserve a round of applause. I thought of posting my views at the end of this season .. But then, I couldn't resist

I have learnt a lot from QQAD which helped me in approaching the problems in a systematic and logical manner

It is really helping me in LR also

Kudos and Hats-off to u

I second that

I might have joined PG just this month but hv been following it religiously for quite a bit of time, helped me get back to the basics, stick to them and tackle tougher problems everytime. I Owe a lot to Aarav and Vineet and QQAD thread, you have no idea how much respect we have for you, YOU ROCK

varun nakra1

Quote:

Originally Posted by cloudsonfire

Q>Within a 5X5 table, a box is marked at the intersection of second row and third column. How many rectangles formed by the boxes of the table do not contain the marked box?im a confused in a table axb , any box marked (p,q) should be unique !!???

By unique u mean wat? if a square has been marked p*q it automatically becomes unique....

In fact the total number of such squares which dont contain the 2*3 marked square will be
26 + 5 + 2(2+2) =39....

getafix

Quote:

Originally Posted by cloudsonfire

Q>Within a 5X5 table, a box is marked at the intersection of second row and third column. How many rectangles formed by the boxes of the table do not contain the marked box?

im a confused in a table axb , any box marked (p,q) should be unique !!???

ya but this rectangle can have dimensions larger than 1X1 and can actually contain the marked point....like for example there are 2 4x5 rectangles which contain that point...

btw is the answer 113??

cloudsonfire

wat i meant was in any such table intersection of 2nd row and 3rd column will be unique!!!! ......so except one box rest is the answer!!!

can anyone plzz xplain me the question in detail !!!

debashis_dan

hii to u all after a long time. am going on well with my prep for CAT 2009. maths basics (doing from arun sharma & Trishna book) will be over in a week.
wish u all the verrrrrry best for this year's CAT. for the benefit of u all, i'm posting this year's Quant question a day series here. It's in the form of a winzip file as the size exceeded the max limit for MSWORD files allowed here.

ALL THE BEST.

sandeep jha

Quote:

Originally Posted by anupsu

1 H 2 H 3 H 4
Consider that the Hondas occupy the positions marked as H.
Now the rest can be filled in certain ways
First consider only slots 1,2,3 to be filled

We get (3+4)*3c2 possible ways

Answer = 21
total = 108+21+21+2 = 152 ways

yaar can anyone explain this question once again.....cud not get it???

warrior

Quote:

Originally Posted by cloudsonfire

Q>Within a 5X5 table, a box is marked at the intersection of second row and third column. How many rectangles formed by the boxes of the table do not contain the marked box?

here possible rectangles are 6C2*6C2

but need to sub those containing the designated box

going vertically if i choose 1st line then i need to choose line 3,4,5,6 ; same for if i choose line 2

going by the same logic if horizontally i choose line 1 then i need to choose 4,5,6 as the other line

so we have (4+4)(3+3+3) = 8*9=72 which has our box

so we have 225-72 =153

warrior

3 Honda Civics, 4 Pajeros, and 5 BMWs are to be parked in front of a dude's house for whom girl's family is coming to see him. In how many ways the cars be parked such that no 2 Honda Civics are next to each other, no Pajero is adjacent to a BMW, and all the cars are being parked?

we have three honda cities and 4 places around these three

of these four the middle two need to be filled

so we have three options 2 middle ones filled, 2 middle and one side one filled and all four filled

if 2 -> we have only two ways

if 3-> we have 2 ways to choose from. also we can split either bmv or pajero in 2

so we have 2*(3C1*1*4+3C2*3*1)

if 4-> 4C1*1*6+4C2*3*4+4C3*3*1

total 152