CAT 2007: Quantitative Questions a Day 101 to 133 - The Discussions

[pratyush_sinha]

Originally Posted by vineet.nitd

And why do you think so?

was sleeping thats why!

[vineet.nitd]

Originally Posted by pratyush_sinha

Now this is an aha moment!!!!

So the answer is 1/12

And the next question is how?

[kondapalli]

Originally Posted by vineet.nitd

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Quantitative Question # 104 (the answer for both Part A and Part B are in the same set of options)
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Question(s): (Part A)A regular hexagon ABCDEF is inscribed in a circle with radius r. Another regular hexagon is formed (lying fully inside the circle with radius r) with 2 of its vertices internally on AB and another 2 on the circle. What is the ratio of the sides of the smaller hexagon to the larger hexagon?

(a) 1/18 (b) 1/12 (c) 1/13 (d) 1/6 (e) none of the foregoing

I am getting an irrational fraction for this...how could options be so neat? Is it None of the foregoing then?

[Aarav]

Originally Posted by kondapalli

I am getting an irrational fraction for this...how could options be so neat?

B'coz QQAD Team gives highest priority to neatness and aplomb

[pratyush_sinha]

Originally Posted by vineet.nitd

And the next question is how?

As it has already been pointed out by our dear sunit,

a=0

or
a= 1/12x -y = 1/12y- x =0

solving them gives x =1/3 or 1/4 and same for y

subtracting them 1/12.

[kondapalli]

Hi ,

Is teh ans to the first one 1/(4aqrt(3)+6) ...by any chance...


Sorry ......I was wrong...will come up with correct ans...

By the answer is 1/13 for the first one....me right?

[pratyush_sinha]

And dear vineet (the more i solve more fondness I develope for youe team)

my answer was (c) for the first one/

Was it right!

[Aarav]

Originally Posted by pratyush_sinha

And dear vineet (the more i solve more fondness I develope for youe team)

my answer was (c) for the first one/

Was it right!

You are right, the answer to Part (A) is 1/13 only. For Part (B), we will not say much and let you figure out. Everything is in front of you

[kondapalli]

Nope.....!!!

Ans to first one is 1/(7+4sqrt(3)) right?.....

Side of the big hexagon = r(radious of hte circle

Now let the side of hte small hexagon be x

then we have sqrt(3)/2*r + x + sqrt(3)/2*x = r

Hence x = ( 7+4sqrt(3) ) r

Hence None of the foregoing....What say about my ans??

[pratyush_sinha]

Originally Posted by Aarav

You are right, the answer to Part (A) is 1/13 only. For Part (B), we will not say much and let you figure out. Everything is in front of you

aarav bhai,

answer 1/12 nahi hai!!

kuchh to bolo!!!