|
| Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe ! |
|
has no status.
Newbie PaGaL
Posts: 10
Join Date: Jul 2006
Location: here
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 1
Thanked 4 Times in 4 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 11:41 AM
ohhhh ok got it. 
Good question.
 Only the divine can help me through now !
|
|
|
» Quote
|
|
The Following User Says Thank You to chubbles_k For This Useful Post:
|
|
|
has no status.
Newbie PaGaL
Posts: 10
Join Date: Jul 2006
Location: here
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 1
Thanked 4 Times in 4 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 11:49 AM
Quote:
Originally Posted by yashraj
I am getting c as the answer.
m/n =3/2 .
Did this using graphs.
For m=1 n=1
For m=2 n=3
For m=10/3 n=2
For m=6/5 n=2
Only left out is m/n=3/2
Hence c is the answer.
|
hey yashraj,
how to do it using graphs ?? please tell ..
did u draw graph for each of |x-1|, |x-2|, |x-4| ???
I tried drawing the graphs for these and then took the common area between |x-1| and |x-4| and then subtracted the area of |x-2| from this common area... left over area is where the value of m will lie ??
but not sure if this is how we do it ???
Only the divine can help me through now !
Last edited by chubbles_k; 16-04-2007 at 12:03 PM.
|
|
|
» Quote
|
|
The Following User Says Thank You to chubbles_k For This Useful Post:
|
|
|
roflmao!!
Addicted PaGaL
Posts: 763
Join Date: Jul 2006
Location: Delhi
Groans: 44
Groaned at 34 Times in 20 Posts
Thanks: 1,928
Thanked 1,867 Times in 442 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 11:49 AM
hey all..!!!
a gud start to QQAD...thanks vineet bhai...
Well here is my approach...
the four intervals here are..:::
(-inf,1],[1,2],[2,4],[4,inf).....
correspondingly for these intervals
x has values...
3-m, m-1, 5-m, m+3....
now i dnt knw how to arrive at the answer....
by putting m= 3.....
x becomes 0,2,2,6....
so only three real solutions...
thus for m=3,n=3...hence m=n...thus option b is ruled out....
by putting m= 6....
we get x= -3,-1,5,9..thus n=4....
hence m/n= 6/4 i.e 3/2...thus c is also ruled out....but people hv quoted c as the answer here.....
where m i going wrng....????:(
some1 pls guide...
|
|
|
» Quote
|
|
The Following User Says Thank You to marijuana_user For This Useful Post:
|
|
|
has no status.
Newbie PaGaL
Posts: 10
Join Date: Jul 2006
Location: here
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 1
Thanked 4 Times in 4 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:01 PM
Quote:
Originally Posted by marijuana_user
hey all..!!!
a gud start to QQAD...thanks vineet bhai...
Well here is my approach...
the four intervals here are..:::
(-inf,1],[1,2],[2,4],[4,inf).....
by putting m= 6....
we get x= -3,-1,5,9..thus n=4....
|
by putting x=-1 u get m=4
and for x>=4 u get m=x-3
Only the divine can help me through now !
Last edited by chubbles_k; 16-04-2007 at 12:04 PM.
|
|
|
» Quote
|
|
The Following User Says Thank You to chubbles_k For This Useful Post:
|
|
|
Mission 1
QuantaSaurus
Posts: 2,824
Join Date: Nov 2005
Location: Gurgaon <-------> Bokaro Steel City
Age: 26
Groans: 78
Groaned at 74 Times in 43 Posts
Thanks: 2,446
Thanked 3,318 Times in 991 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:10 PM
Quote:
Originally Posted by marijuana_user
hey all..!!!
a gud start to QQAD...thanks vineet bhai...
Well here is my approach...
the four intervals here are..:::
(-inf,1],[1,2],[2,4],[4,inf).....
correspondingly for these intervals
x has values...
3-m, m-1, 5-m, m+3....
now i dnt knw how to arrive at the answer....
|
Try from this piece of information 
Put the values of m and see that in how many cases x satisfies the range taken .
x<1-> x=3-m ;1<x<2-> x=m-1 ;2<x<4 -> x=5-m ;4<x -> x=m+3
Last edited by vineet.nitd; 16-04-2007 at 12:12 PM.
|
|
|
» Quote
|
|
The Following User Says Thank You to vineet.nitd For This Useful Post:
|
|
|
has no status
Hardcore PaGaL
Posts: 455
Join Date: Aug 2005
Location: The darkest side of the most natural satellite.
Age: 24
Groans: 29
Groaned at 16 Times in 9 Posts
Thanks: 654
Thanked 1,185 Times in 332 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:15 PM
Well I really could not come up with a graph, which I could attach with the post, but the solution from Graphical method looks very simple
After finding out the realtion between x and m for various intervals of x, plot a graph of x v/s m .
From the graph, following can be inferred.
1. for m<1 , n=0
2. for m=1, n=1 (x=4)
3. for 1<m<2 , n=2
4. for m=2, n=3
5. for 2<m<3 , n=4
6. for m=3, n=3
7.for m>3, n=2
so (3) rules out option (a), (2) rules out option (b), (7) rules out option (d), and (4) rules out option (e). So the answer is (c)
Amrutesh
BLACK EYE without an Article. 
I C
i-cynic: An idealist whose rose-colored glasses have been removed, snapped in two, and stomped into the ground, immediately improving my vision
|
|
|
» Quote
|
|
has no status.
Hardcore PaGaL
IIM Calcutta 
Posts: 493
Join Date: Aug 2005
Location: Fruit Market
Age: 25
Groans: 4
Groaned at 8 Times in 6 Posts
Thanks: 82
Thanked 247 Times in 58 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:18 PM
Graphical solution.....
C the attached image.
On this graph if u draw lines parallel to X -axis (that means m is constant) , the number of points at which it intersects the drawn graph = n.
Now I hope its clear.
Over n Out
Apple
Anyone can count the seeds in an Apple, but only God can count the number of Apples in a seed.
|
|
|
» Quote
|
|
The Following 21 Users Say Thank You to Apple For This Useful Post:
|
0000 (23-05-2007),
arindam83 (30-04-2007),
chop suey (17-04-2007),
crazyfootballer (17-04-2007),
Destiny's_Child (18-04-2007),
hansingring (03-11-2007),
HarshaRocks (21-04-2007),
icvsjha (17-04-2007),
krishor (23-06-2007),
krsh.vik (16-04-2007),
lehmanbrothershereicome (16-04-2007),
minkuvg (13-09-2007),
ninja_talli (16-04-2007),
prof_calculus (17-04-2007),
rahulworld (21-10-2007),
rani_das (17-04-2007),
ringsofsaturn (01-05-2007),
sid_dharth (16-04-2007),
snipeking (02-06-2007),
sunilnatraj (16-04-2007),
zlickfish (16-05-2007)
|
|
I will come back...
Hardcore PaGaL
Posts: 541
Join Date: Aug 2006
Location: Omnipresent
Groans: 0
Groaned at 2 Times in 2 Posts
Thanks: 199
Thanked 278 Times in 167 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:20 PM
Quote:
Originally Posted by marijuana_user
hey all..!!!
a gud start to QQAD...thanks vineet bhai...
Well here is my approach...
the four intervals here are..:::
(-inf,1],[1,2],[2,4],[4,inf).....
correspondingly for these intervals
x has values...
3-m, m-1, 5-m, m+3....
now i dnt knw how to arrive at the answer....
by putting m= 3.....
x becomes 0,2,2,6....
so only three real solutions...
thus for m=3,n=3...hence m=n...thus option b is ruled out....
by putting m= 6....
we get x= -3,-1,5,9..thus n=4....
hence m/n= 6/4 i.e 3/2...thus c is also ruled out....but people hv quoted c as the answer here.....
where m i going wrng....????:(
some1 pls guide...
|
put m= 6
for the intereval 2,4 the value of x = 5-m = 5-6 = -1..it donot come in the interval (2,4)
so the value -1 not a solution..
---------------------------------------------------------------------------------------------------
O, Wind,
If winter comes,
can Spring be far behind? —Percy Bysshe Shelley
|
|
|
» Quote
|
|
The Following 2 Users Say Thank You to doomsayer For This Useful Post:
|
marijuana_user (16-04-2007),
rani_das (17-04-2007)
|
|
has no status.
Expert PaGaL
Posts: 125
Join Date: Mar 2005
Groans: 3
Groaned at 0 Times in 0 Posts
Thanks: 30
Thanked 12 Times in 8 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:24 PM
Quote:
Originally Posted by chubbles_k
hey yashraj,
how to do it using graphs ?? please tell ..
did u draw graph for each of |x-1|, |x-2|, |x-4| ???
I tried drawing the graphs for these and then took the common area between |x-1| and |x-4| and then subtracted the area of |x-2| from this common area... left over area is where the value of m will lie ??
but not sure if this is how we do it ???
|
We can draw graphs for each of the mods.
At point 1 the value will be +2,slope till now is -2 , mod1,2,3 all are decresing.
At point 2 value will be +3 . From p1 to p2 the slope is +1 bcoz mod1 is increasing, mod1 is decreasing and mod3 is increasing. so slope =+1
At point 3 value =1. Slope frm p2 to p3 = -1. mod1 is increasing, mod2 is increasing and mod3 is decresing so, +1 -1 -1 = -1
Graph will increase by +2 after p3 which is 4.
NOTE : When mod2 decreases slope increases unlike mod1 and 2 because mod2 has a negative sign.
if u r not living on the edge u r ocuppying a lot of space
|
|
|
» Quote
|
|
The Following User Says Thank You to yashraj For This Useful Post:
|
|
|
Mission 1
QuantaSaurus
Posts: 2,824
Join Date: Nov 2005
Location: Gurgaon <-------> Bokaro Steel City
Age: 26
Groans: 78
Groaned at 74 Times in 43 Posts
Thanks: 2,446
Thanked 3,318 Times in 991 Posts
|
Re: CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions -
16-04-2007, 12:25 PM
Quote:
Originally Posted by Apple
Graphical solution.....
C the attached image.
On this graph if u draw lines parallel to X -axis (that means m is constant) , the number of points at which it intersects the drawn graph = n.
Now I hope its clear.
Over n Out
Apple |
Bravo . This is wot i was looking for .
I have always believed that a graph plot should speak out every bit of the soln. .Think more and write less .
Last edited by vineet.nitd; 16-04-2007 at 12:32 PM.
|
|
|
» Quote
|
| Thread Tools |
|
|
| Display Modes |
 Linear Mode
|
|
Posting Rules
|
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts
HTML code is Off
|
|
|
| |
Help
