CAT 2007: Quantitative Questions a Day 1 to 50 - The discussions

[richa bhatia]

my options a n d
for x<1 x=3-m
for 1<x<2 x=m-1
for 2<x<4 x=5-m
for 4<x x=m+3
then i put d values of m

m=n @ m=3
m/n=6/2 @ m=6 ::::::: i ddi wrong sth.. 6/2 is not 3/2
m=n-1 @ m=2

for m=3/5 *n
n has to be a multiple of 5 , but max no of solutuions can be 4.. so this is not possible

i tried for m=5,10,15,20 but could not get n=3/5*m


my ans choice chnage to a c and d

[Apple]

Solution ::
x>= 4 ------ > m>= 1 and x =m+3
2<=x<=4 ---> 1<=m<=3 and x =5-m
1<=x<=2 ------> 2<=m<=3 and x= m-1
x<=1 ------> m>= 2 and x=3-m

n could be 0,1,2,3,4.
From here we can deduce :: m<1 => n=0
m=1 => n=1
1<m<2 or 3<m => n=2
m=2 or m=3 => n=3
2<m<3 => n=4
So we get answer (c).
Cheers
Apple

[Superstar]

Hi All,

So once again have to start with QQAD...Unlucky chap...Huh...

Now coming to the question...

I feels the answer has to be

a>

As I don't see five solutions or its multiples ever possible in such a graph...

What do you say guys???

[jbadri]

I think the answer is (e).

The relation between m & n is as below

MN00112233435262

The only possible option that can never be true is 'e' (i.e. m-n = -1)

It definitely took more than 5 mins to tabulate values and come to a conclusion. Looking forward to see others solution.

[prof_calculus]

Originally Posted by krsh.vik

answer is c m/n=3/2
for the four intervals (-inf,1)[1,2)[2,4)[4,inf)
values of x are 3-m,m-1,5-m,3+m
for m=6/5 n=2
m=2 n=3
m=1 n=1
m=10/3 n =2
hence c is the answer

I go with your solution, buddy.

It is (C) for me also.

pc

[Aarav]

Perfect solutions out there krsh.vik and Apple. Yeah, prof_calculus you are right too Try solving this through graphical method also. I believe, you all will appreciate the fact that the approach is more important than the answer. If getting the answer was the only aim, so many questions you can see from here and there and solve. I will just say, avoid the mindset right now that the question is to solved in 2 minute or 3 minutes. We toil hard to give you a perfect question each day so that your takeaway from QQAD is maximum.

I will just quote what Allan Border once famously said ... "Follow excellence and everthing else will follow you". Learn as much through right ways/methods, you will score marks when it actually matters.

[gmat_delhi2007]

my take is (a)
cant c hw n=5. acc to me the max value n can take is 4.

[chubbles_k]

Originally Posted by vineet.nitd

I am not commenting on ur ans at this moment .

For which values of m , n takes max. value ?

n is max(=3) for m=2,3. is it not vineet?

my answer is (c).

[vineet.nitd]

Originally Posted by chubbles_k

n is max(=3) for m=2,3. is it not vineet?

No , look for value of n for 3>m>2 .



@folks .. Would luv if you come out with a graphical solution for this one.Almost all attempts right or wrong have the same approach till now.

krish and PC you are right . Apple has got the foolproof solution

[yashraj]

I am getting c as the answer.

m/n =3/2 .

Did this using graphs.
For m=1 n=1
For m=2 n=3
For m=10/3 n=2
For m=6/5 n=2

Only left out is m/n=3/2
Hence c is the answer.