Quantitative questions a day 51 to 100 - The discussions
PaGaLGuY.com - The Everything of MBA, CAT 2008, GMAT, XAT, IIM
         Home          MBA Forums         PG Office Blog         Contact Us         About Us                  Jobs @ PG
Exclusive Bschool Content:      Interviews      B-School Watch     MBAs speak     Placements     GMAT & MBA Abroad      Form Notifications
» Sponsors





Go Back   PaGaLGuY.com - The Everything of MBA, CAT 2008, GMAT, XAT, IIM > Exam Resources > Quantitative Questions and Answers

Notices
Quantitative Questions and Answers Discuss Quantitative and other Math related questions. Post your math doubts and get it solved by the smartest brains this side of the universe !

Tags: , , , ,

Reply
 
LinkBack Thread Tools Display Modes
Quantitative questions a day 51 to 100 - The discussions
Old
  (#1)
Aarav
Persevering to be the best
Student
 
Status: Offline
Posts: 4,253
Join Date: Oct 2004
Location: Kingdom of Heaven
Groans: 0
Groaned at 43 Times in 33 Posts
Thanks: 884
Thanked 4,018 Times in 1,219 Posts
Quantitative questions a day 51 to 100 - The discussions - 17-04-2006, 09:56 PM

I'm starting a new thread as the discussions will happen on this new thread for next 50 questions and the sectional test

Happy solving


What lies in front of you or behind you is nothing compared to what lies within you - T.M.W.S.H.F

The greatest events in the life aren't the loudest, but the quietest hours - Anonymous

Subscribe to QQAD: http://www.pagalguy.com/index.php?categoryid=65

   
Reply With Quote
Sponsored Links
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#2)
Apple
has no status.
Hardcore PaGaL
 
Apple's Avatar
 
Status: Offline
Posts: 492
Join Date: Aug 2005
Location: Fruit Market
Age: 24
Groans: 4
Groaned at 7 Times in 5 Posts
Thanks: 82
Thanked 242 Times in 55 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 08:46 AM

Question:51
Allwin went to the market and bought some chikoos, mangoes, and bananas. Allwin bought 42 fruits in all. The number
of bananas is less than half the number of chikoos; the number of mangoes is more than one-third the number of
chikoos and the number of mangoes is less than three-fourths the number of bananas.
How many more/less bananas did Allwin buy than mangoes?
(a) 3 (b) 6 (c) 11 (d) none of the foregoing



I got (a) . Chikoo = 23 banana=11 Mangoes =8.
Cheers Apple


Anyone can count the seeds in an Apple, but only God can count the number of Apples in a seed.

  Send a message via Yahoo to Apple  
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#3)
siddhesh_j
has no status.
Addicted PaGaL
 
siddhesh_j's Avatar
 
Status: Offline
Posts: 1,204
Join Date: Nov 2005
Location: on my throne
Age: 23
Groans: 95
Groaned at 84 Times in 44 Posts
Thanks: 1,772
Thanked 1,202 Times in 293 Posts
Smile Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 09:10 AM

my answer to the qn # 51 :
c=23 , b=11 , m =8

the eqn comes to c/2>3/4b>m>c/3

only soln is above one ; so option (a) 3 is the correct option


~I have stopped posting on this forum for personal reasons~
~PMs won't be screened regularly~
~Reach me through my blog~



  Send a message via Yahoo to siddhesh_j  
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#4)
crazyfootballer
has no status.
Addicted PaGaL
 
crazyfootballer's Avatar
 
Status: Offline
Posts: 902
Join Date: Aug 2005
Location: Delhi
Groans: 2
Groaned at 13 Times in 8 Posts
Thanks: 171
Thanked 340 Times in 111 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 09:27 AM

C+M+B=42
B<C/2 M<3/4B M>C/3

C/3 < M < 3C/8 1)
4C/9 < B < C/2 2)

Adding 1) and 2)
7C//9 < B+M < 7C/8

C + 7C/8 = 42 (taking extreme)
=> C = 22.xx But B+M is less than 7C/8 hence C>22.xx

C + 7C/9 = 42 (taking other extreme)
=> C = 23.xx But B+M is greater than 7C/9 hence C<23.xx

=>C=23
therefore, B=11, M=8
Hecne answer is 3.

P.S - I am not sure whether my method is correct or not. Someone pls comment on this.

Last edited by crazyfootballer; 18-04-2006 at 09:37 AM.
   
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#5)
IdiotR
has no status.
Hardcore PaGaL
 
IdiotR's Avatar
 
Status: Offline
Posts: 746
Join Date: Feb 2006
Location: Inside a boiling pot
Groans: 9
Groaned at 13 Times in 11 Posts
Thanks: 29
Thanked 69 Times in 32 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 10:01 AM

given c+b+m=42--------1)
and b<1/3*c--------------2)
m>1/3*c-----------3)
m<3/4*b-----------4)
from 1)

m=42-b-c>42-c/2-c (from eqn 2)i.e 42-3c/2
i.e 2m>84-3c
i.e 2m>84-9m(from eqn 3) i.e m>7.6
similarly
c=42-b-m
>42-5c/6
i.e c>22.2

similarly
b>10.5
hence possible vals for m,b,c are 8,11,23 to satisfy c+b+m=42
hance option 3 as 11-3=8
Not sure of itz correctness,somebody comment on ths...




tashbeeh na poori ho saki; terey husn-ey jamaal ki
misaal key liyey lafz na rahey ;awaaz ke liyey dum na raha

-Varun.
   
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#6)
chetna
has no status.
Addicted PaGaL
 
chetna's Avatar
 
Status: Offline
Posts: 872
Join Date: Mar 2005
Location: Delhi
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 25
Thanked 34 Times in 25 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 10:46 AM

Quote:
Originally Posted by IdiotR
given c+b+m=42--------1)
and b<1/3*c--------------2)
m>1/3*c-----------3)
m<3/4*b-----------4)
from 1)

m=42-b-c>42-c/2-c (from eqn 2)i.e 42-3c/2
i.e 2m>84-3c
i.e 2m>84-9m(from eqn 3) i.e m>7.6
similarly
c=42-b-m
>42-5c/6
i.e c>22.2

similarly
b>10.5
hence possible vals for m,b,c are 8,11,23 to satisfy c+b+m=42
hance option 3 as 11-3=8
Not sure of itz correctness,somebody comment on ths...
i also solved it this way...

when i got c>22.2...i assumed it to be 23...and it worked fine for the other case

is there any better method....?????


...so stick to the fight when you are hardest hit,
its when things go wrong that you must not quit!
   
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#7)
brij23
has no status.
Newbie PaGaL
 
Status: Offline
Posts: 3
Join Date: Apr 2006
Location: Mumbai
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 0
Thanked 0 Times in 0 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 11:04 AM

_____________________
Quant Question # 51
_____________________

Allwin went to the market and bought some chikoos, mangoes, and bananas. Allwin bought 42 fruits in all. The number of bananas is less than half the number of chikoos; the number of mangoes is more than one-third the number of chikoos and the number of mangoes is less than three-fourths the number of bananas.

How many more/less bananas did Allwin buy than mangoes?

(a) 3 (b) 6 (c) 11 (d) none of the foregoing

Soln:

Given:
b < 1/2 c m > 1/3 c
m < 3/4 b So m < 3/8 c

We know, number of mangoes is more than one third of cheekoos and less than three eighth of of chocklates. If we take number of cheekoos as 24 both the conditions cannot be satisfied. So number of mangoes has to be 23 and number of mangoes has to be 8.
The remaining number of fruits will be bananas and it will be 11

Cheekoos Bananas Mangoes
21 11 8

So Allwin bought three more bananas than mangoes.

Hence the correct answer choice would be [a].


   
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#8)
rani145541
has no status.
Hardcore PaGaL
 
Status: Offline
Posts: 291
Join Date: Jan 2006
Location: ahmedabad
Groans: 19
Groaned at 81 Times in 13 Posts
Thanks: 97
Thanked 156 Times in 59 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 11:44 AM

Quote:
Originally Posted by brij23
_____________________
Quant Question # 51
_____________________

Allwin went to the market and bought some chikoos, mangoes, and bananas. Allwin bought 42 fruits in all. The number of bananas is less than half the number of chikoos; the number of mangoes is more than one-third the number of chikoos and the number of mangoes is less than three-fourths the number of bananas.

How many more/less bananas did Allwin buy than mangoes?

(a) 3 (b) 6 (c) 11 (d) none of the foregoing

Soln:

Given:
b < 1/2 c m > 1/3 c
m < 3/4 b So m < 3/8 c

We know, number of mangoes is more than one third of cheekoos and less than three eighth of of chocklates. If we take number of cheekoos as 24 both the conditions cannot be satisfied. So number of mangoes has to be 23 and number of mangoes has to be 8.
The remaining number of fruits will be bananas and it will be 11

Cheekoos Bananas Mangoes
21 11 8

So Allwin bought three more bananas than mangoes.

Hence the correct answer choice would be [a].

I am also getting 23 11 and 8 as solution so ans is A -3
Hey i dont receive the questions.
Please tell me how to subscribe to question list so that i also get questions along with u guys.

Rani
   
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#9)
dhruvpratap
has no status.
Newbie PaGaL
 
dhruvpratap's Avatar
 
Status: Offline
Posts: 11
Join Date: Apr 2006
Location: Pune
Age: 23
Groans: 0
Groaned at 0 Times in 0 Posts
Thanks: 0
Thanked 0 Times in 0 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 11:49 AM

Quote:
Originally Posted by chetna
i also solved it this way...

when i got c>22.2...i assumed it to be 23...and it worked fine for the other case

is there any better method....?????
I also solved it this way, nothin wrong with it


Whenever you feel low, depressed, or useless, remember that you are the same sperm that won a battle against a million others.
   
Reply With Quote
Re: Quantitative questions a day 51 to 100 - The discussions
Old
  (#10)
amar_kashyap
has no status.
Addicted PaGaL
 
amar_kashyap's Avatar
 
Status: Offline
Posts: 923
Join Date: Nov 2004
Location: mumbai
Groans: 4
Groaned at 8 Times in 6 Posts
Thanks: 82
Thanked 176 Times in 80 Posts
Re: Quantitative questions a day 51 to 100 - The discussions - 18-04-2006, 12:22 PM

I am getting (d)..ie none of the foregoing..
b=c/2-k becoz bananas are less than half the chikoos, similarly
m=c/3+p
m=3b/4-x=3c/8-3k/4-x
Now c , m and b have to be integer. c must be of the form 24n.So c must be=24
Now m+b=18 becoz c+m+b=42
Now b must be 4,8,12,or 16.But as b is less than half of c it has to be less than 12 ie b=4 resulting into m=14 which is not possible becoz as indicated from third eqauation m<b

So the given scenario is not possible
hope i make some sense..


To love when it can be lost, to go on when progress seems futile, to believe with every fibre in your body to hope, to live and to never give in.....



   
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
How to get 770 in 12 days prep..?? NewView GMAT and Related Discussions 19 01-06-2008 02:57 PM
JMET 2005 Discussions Phooka Other Exams - XAT, FMS, JMET, SNAP etc 1916 26-11-2006 09:43 AM
Quantitative questions a day 1 to 50 - The discussions pagalguy Quantitative Questions and Answers 1236 10-08-2006 04:18 PM
Struggling!!! Need to improve scores.... Calvin CAT and Related Discussion 59 21-07-2006 01:01 PM
GMAT prep for the students prepared for cat jeeves sunil GMAT and Related Discussions 59 07-07-2006 08:24 PM

» Sponsors








PaGaLGuY.com is not responsible for the views and opinions of the posters.
PaGaLGuY.com is an Inzane Labs Private Limited production.
Hosted on servers powered by Neutral Web