[khyatikabra]

what will be the answer to this question :
If you have 3 tickets to a lottery for which 10 tickets were sold and 5 prizes are to be given, the probability that you will win at least one prize is:
a. 7/12
b. 9/12
c. 1/12
d. 11/12
please explain. thanks!

[khyatikabra]

Originally Posted by khyatikabra

what will be the answer to this question :
If you have 3 tickets to a lottery for which 10 tickets were sold and 5 prizes are to be given, the probability that you will win at least one prize is:
a. 7/12
b. 9/12
c. 1/12
d. 11/12
please explain. thanks!

i got the answer! its 11/12.. correct me if i m wrong..
my logic : Probability that you will win at least one prize = 1 – probability that you will not win any prize. therefore 1-(7C5/10C5) i.e. 1-(1/12) = 11/12
7C5 coz all 5 prize will b from the remaining 7 tickets and 10C5 coz from 10 tickets, 5 prizes will be picked.

[naiquevin]

Originally Posted by khyatikabra

what will be the answer to this question :
If you have 3 tickets to a lottery for which 10 tickets were sold and 5 prizes are to be given, the probability that you will win at least one prize is:
a. 7/12
b. 9/12
c. 1/12
d. 11/12
please explain. thanks!

i think 11/12 is right

if the 3 tickets are such that none of them has any prize on them, then these three can be selected from 5 in 5C3 ways = 10 ways

total ways of selecting 3 tickets from 10 is 10C3 = 120 ways

so probability that none wins a prize = 10/120

so atleast one = 1 - 1/12 = 11/12

[mohannmohan]

can anyone send me attachment shortcut method of train,mixture,alligations etc

please please send me attachment

[N kiranmai]

helooooooooooooooooooo