Suresh's Corner: Miscellaneous Questions From Quants

[eric.segal1]

Originally Posted by the_hate

man you have posted the q's all over the forum....grt...
http://www.pagalguy.com/forum/quanti...ml#post1113186 (Quant by Arun Sharma)

yeah man quite right !! but i did take care that i dont post it anywhere where its not pertinent.
2ndly no offence dude but it wd hv been very valuable for the purpose of this thread if u answred the doubts rather that pointing out at such trivial or rather frivolous issues.
hope u take my point in the right spirit !!

[eric.segal1]

can someone plz help me with this one?
Out of 4 men and 4 women a committee of 5 pple has to be created comprising a president a vice president and 3 secretaries.
Find the number of ways of forming this committee such that there are at least 3 women in the committee and at least one woman holds the post of the president or the vice president.
Puys the answer given is
(4C4 x 4C1 x 5!/3!) + (4C2 x 4C3 x 5!/3!) - (4C2 x 4C3 x 2C2 x 2!)
puys I understood what and why they hv done in the 1st two brackets but I don’t understand wat hv they done in the 3rd bracket.
Someone plz help !!

[kamnashish]

Hi , Please some one help me how to do such problems like remainder of 7^9999/1000. I know using Euler . Please can someone expalin me in detail so that i can apply that in such problems.

Thanks in advance

[the_hate]

Originally Posted by eric.segal1

yeah man quite right !! but i did take care that i dont post it anywhere where its not pertinent.
2ndly no offence dude but it wd hv been very valuable for the purpose of this thread if u answred the doubts rather that pointing out at such trivial or rather frivolous issues.
hope u take my point in the right spirit !!

well yaar...i did mean to help...thts why i came with such a long soln taking care no point is missed...nyways i thought it wud be better if we can discuss 1 q's at one place rather than discussion going on at 10 places....beats the puropse!!!

sorry for spamming....nd dun worry...no offence taken...best of luck!!!

[eric.segal1]

Can Someone plz help me with this?
A group of 8 man r to b chosen from 12 men for rowing out of which 3 men can row on one side only & 2 can row on the other side only. Find the numbr of ways of arranging the crew with 4 members on each side.
40320
30240
60480
10080

PS: the answer given is 60480
but can someone plz give proper explaination.

[mattoo]

3/5 part of a kerosene tin is filed.if 6 bottles are taken out of it and 3 bottles are filled again, then half the tin is full.What is the capacity of the tin? (in bottles)
a) 20
b) 30
c) 45

[v_v_n]

Originally Posted by mattoo

3/5 part of a kerosene tin is filed.if 6 bottles are taken out of it and 3 bottles are filled again, then half the tin is full.What is the capacity of the tin? (in bottles)
a) 20
b) 30
c) 45

let x = capacity of tin
y= capacity of bottle

3x/5 - 1x/2 = 3 y
x/10 = 3y
x = 30 y.

it means x is multiple of 30 from option it is only 30(option b)

Correct me if i am wrong.

[sarsij]

Originally Posted by mattoo

3/5 part of a kerosene tin is filed.if 6 bottles are taken out of it and 3 bottles are filled again, then half the tin is full.What is the capacity of the tin? (in bottles)
a) 20
b) 30
c) 45

My doubt : Whats the purpose of writing 'if 6 bottles are taken out of it and 3 bottles are filled again', does it not mean that we are taking out just 3 bottles in actual (if this was meant to confuse the student, then I guess this needs to be done with a very very difficult language).

Now the solution

Let V by the total volume of the tin. And B be the volume of the bottles.

=> (3/5)V -6B + 3B = (1/2)V => (3/5 - 1/2) V = 3B
=> (1/10) V = 3B => V = 30B . Hence 30 Bottles is the capacity of the tin.

[clsuresh1]

Dear friends, I have a small news for you. I wanted to stop this thread here and continue this job in a new thread which you can visit here.

http://www.pagalguy.com/forum/quanti...ns-quants.html (Suresh's Corner: Miscellaneous Questions From Quants Part-II)

Please stop posting here..........and participate in the new thread.
I will soon request the moderator to close this thread.
Kindly support me

Regards