[mits.4oct]

Hi suresh..
I am preparing for CAT 2007 and have joined CL. But I am not satisfied with the way classes are conducted there. I have already paid the full amount so cant think of leaving it now. I am doing Quant from CL notes and Arun Sharma book, I want to take TIME notes but feel it would be an overburden to do questios from these 3 materials. Please suggest me what to do now coz I am not gaining confidence despite doing lots of practice(may be coz I am having wrong material with me)

[kondapalli]

Originally Posted by Apple

answer shd be 1 - pi / 6 - sqrt(3) / 4 .ur answer is negative and i dont think area can be negative .
Cheers

Guys I also got the answer. it's a great problem.
Hi Apple,

The area is not negative. It is positive only. It comes around .043.

[zapped]

just subscribing !

[rahul26]

HI Suresh,
Plz help with this question.
Remainder of 2^2002/1001 ??

[vyomb]

HI Suresh,
Plz help with this question.
Remainder of 2^2002/1001 ??

hi @rahul26
ur query is already answered at the following thread..
http://www.pagalguy.com/forum/quanti...ystem-458.html (Number System)
pls be guided....

[abhishekpalsing]

Hi Hanuman

plz give the funda of inverse remainder as u used in the ques
:--- Remainder when 6^98 is divided by 101

[thisisananth]

Originally Posted by clsuresh

Yes the answer is 1.

Sagar I have a different and simple approach.

Here comes our next basic funda.

All of us know that the remainder obtained when a number is divided by10 is nothing but the unit's digit of that no.

Had u ever thought of the remainder that is obtained when divided by 9. It is nothing but the single digit sum of that number.

For example the single digit sum of 4658 = 4 + 6 + 5 + 8 = 23 = 2 + 3 =5.
Now when 4658 is divided by 9 the remainder is nothing but the remainder obtained when sum of the digits of 4658 i.e 23 is divided by 9 which in turn is nothing but the remainder obtained when 2+3 = 5 is divided by 9.

So that's the funda here folks.

Finally the remainder obtained when 4444^3333 is divided by 9 is nothing but the single digit sum.
4444^3333 % 9
= 7^ 3333 % 9
= 343^ 111 % 9
= 1.
Since the remainder obtained when N is divided by 9 is 1 the single digit sum is 1.

Remember if the remainder obtained is 0 then the single digit sum is not 0 but ofcourse it is 9

Please explain the part in blue. How is it true?

[tushar_agarwal03]

hello Suresh Sir,Hope you remember me... Would like to get in touch with you... Could you please provide me with your contact no. and by the way where are you these days?

[Ashish_4_cat]

Originally Posted by thisisananth

Please explain the part in blue. How is it true?

7^333 = 7 ^(3*111)
7 ^ 3 = 343

so 7 ^ 333 = 343 ^ 111
3+4+3 = 10 = 1+ 0 =1
(divisibility of 9 )

now 1 ^ nythying is 1 ....
hence remainder is 1 ....

[clsuresh]

Folks, i wish you all the best for your exam............
The last recipe from me from the topic of numbers just to revise some of the important concepts.................

1. Find the last three digits of 7 ^ 9999

2. S = { 1,2,3,4,5,.................,2999,3000}. P is a subset of S such if x belongs to P, 2x does not belong to P. Find the maximum number of elements in P

3. N= [sqrt(2) + sqrt(3)]^1980 . Find the immediate digit that is after the decimal point of N. Also find the digit that immediately precedes the decimal point of N.

4. Mr and Mrs. Ram have invited 3 couples for a small part. Certain number of shake hands took place. No person shook hand with his/her spouse, no person shook hand with the same person more than once and of course no person shook his/her own hand. After the party Mr. Ram asked the remaining members including his wife about the number of shake hands that each them gave and to his surprise he found that everyone of them gave different number of shake hands. How many shake hands did Mrs. Ram give?

Try out these......