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Originally Posted by clsuresh
Guys here comes our next question
Find the last two digits of 2^995
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is it 48
we need to find the remainder when it is divided by 100 so we have
2^993/25 or 2^13/25
now 2^13+2^7 is divisible by 25
so 2^13 will leave a remainder of 12 ( 2^7 is 128 and 12= 140-12
also we have cancelled 4 so 12*4= 48