[warrior]

Originally Posted by siddharthaduggirala

HI Suresh,
Can u please solve this one for me!!!
A news paper agent sells TOI,HT and IN in equalnumbers to302 persons. 7 get HTand IN, 12 get TOI and IN 9 get TOI and HT and 3 get all the news papers. Now

1) How many get only one paper
2) What % get TOI or Ht but not IN
3) The difference between the number readinfg HT & IN only and HT only is ??

This is a prob from arun sharma the last one.

Thanks
Siddhartha.

see let x be the subscribers for each

so we have 3x -(7+12+9)+3=302 solving which gives me x= 109

now you can constructthe following Venn and all will follow

[IMG]file:///C:/DOCUME%7E1/NMAHES%7E1/LOCALS%7E1/Temp/moz-screenshot-1.jpg[/IMG]

[thunderboltsj69]

can some body explain the answers to this please ...

1.
a crew can row a certain course up stream in 84 mins, they can row the same course down stream in 9 mins less than the time taken to row in still water. how long would they take to row down the stream?
(a) 45 or 23 mins (b) 63 or 12 mins (c) 60 mins (d) 19 mins

2. if a,b,c,d are in continued proportion then [(a-d)/(b-c)] >= x, then what is the calue of x?

3. if A varies as C and B varies as C, then which of the following is false?
note: assume ~to be the proportionality symbol
(a) (A + B) ~ C
(b) (A - B ) ~ (1/C)
(c) (AB)^(1/2) ~ C
(d)none of these

[shyamnaren]

Originally Posted by mave

1) total no of ways is the same as no of ways of distributing 10 indistingushing balls in 3 boxes = 8 ways.

total no of favourable cases = 2 (3,3,4 & 2,4,4)
Probability = 2/8 = .25
hope am right with my method.

@mave:ur sol went way above my head.. ..would u care to elaborate??

thanks,
:satisfie:

[prade]

Originally Posted by thunderboltsj69

can some body explain the answers to this please ...

1.
a crew can row a certain course up stream in 84 mins, they can row the same course down stream in 9 mins less than the time taken to row in still water. how long would they take to row down the stream?
(a) 45 or 23 mins (b) 63 or 12 mins (c) 60 mins (d) 19 mins

2. if a,b,c,d are in continued proportion then [(a-d)/(b-c)] >= x, then what is the calue of x?

3. if A varies as C and B varies as C, then which of the following is false?
note: assume ~to be the proportionality symbol
(a) (A + B) ~ C
(b) (A - B ) ~ (1/C)
(c) (AB)^(1/2) ~ C
(d)none of these

qn 3 answer option b rest will do tomorrow...

[siddharthaduggirala]

Originally Posted by warrior

see let x be the subscribers for each

so we have 3x -(7+12+9)+3=302 solving which gives me x= 109

now you can constructthe following Venn and all will follow

[IMG]file:///C:/DOCUME%7E1/NMAHES%7E1/LOCALS%7E1/Temp/moz-screenshot-1.jpg[/IMG]

Instead of adding 25 to 302 i subtracted. May be the silliest mistake one could do!!!!:( thx buddy for ur soln.

[warrior]

Originally Posted by thunderboltsj69

can some body explain the answers to this please ...

1.
a crew can row a certain course up stream in 84 mins, they can row the same course down stream in 9 mins less than the time taken to row in still water. how long would they take to row down the stream?
(a) 45 or 23 mins (b) 63 or 12 mins (c) 60 mins (d) 19 mins

2. if a,b,c,d are in continued proportion then [(a-d)/(b-c)] >= x, then what is the calue of x?

3. if A varies as C and B varies as C, then which of the following is false?
note: assume ~to be the proportionality symbol
(a) (A + B) ~ C
(b) (A - B ) ~ (1/C)
(c) (AB)^(1/2) ~ C
(d)none of these

2. x <=3
3. b
for 1 i was able to get speed of boat/speed of stream = 63,24

[evergreen_cool]

Originally Posted by mave

duh!
(1212.... 300 digits) % 9
= 12*150 % 9
= 0.

(1212...300 digits)%121
= (121*10^297 + 121*10^294 + .... + 121)%121
= 0.

(121*10^297 + 121*10^294 + .... + 121) = 121121121...
the no. is 12121212...

[viccy_776]

[quote=thunderboltsj69]

1.

any takers

2. if a,b,c,d are in continued proportion then [(a-d)/(b-c)] >= x, then what is the calue of x? I took a,b,c,d as 1,2,4,8 ;got lhs = 3.5

took a,b,c,d as 1,3,9,27 and got lhs = 4.33

hence will say x=3

3.
(b) (A - B ) ~ (1/C)

[viccy_776]

[quote=thunderboltsj69]

1.

any takers

2. if a,b,c,d are in continued proportion then [(a-d)/(b-c)] >= x, then what is the calue of x? I took a,b,c,d as 1,2,4,8 ;got lhs = 3.5

took a,b,c,d as 1,3,9,27 and got lhs = 4.33

hence will say x=3

3.
(b) (A - B ) ~ (1/C)

[nagi_nov3]

1.
a crew can row a certain course up stream in 84 mins, they can row the same course down stream in 9 mins less than the time taken to row in still water. how long would they take to row down the stream?
(a) 45 or 23 mins (b) 63 or 12 mins (c) 60 mins (d) 19 mins

d/(u-v) = 84 -- (1)

d/u - d/(u+v) = 9

d=84(u-v)

d.v/ (u.(u+v)) =9

84.(u-v)(v) = 9.u(u+v)
28uv-28v^2=3u^2+3uv
3u^2-25uv-28.v^2=0
3u^2-21uv-4uv-28v^2=0

3u(u-7v)-4v(u-7v)=0

so u is 7v or 4/3v

from (1) d/(u-v) = 84 => d/v = 84.6 or 84.1/3

we need d/(u+v) = d/8v = 84.6/8 = 63
or d/7/3v = 3/7.(28 ) = 12

alternative

d/(u+v) = x
d/(u-v) = 84
u+v = d/x u-v = d/84
so 2u = d(1/x + 1/84)
d/u = 2/(1/x+ 1/84) = 168.x/(84+x)
given
d/u - d/(u+v) = 168x/(84+x) -x = 9
168x= (9+x)(84+x)
x^2+93x+84.9= 168x
x^2-75x+84.9=0
(x-12)(x-63)=0
so 63,12



2. if a,b,c,d are in continued proportion then [(a-d)/(b-c)] >= x, then what is the calue of x?

take values as a,ap,ap^2,ap^3

lhs= p^3-1 / p2-p = (p-1)^3-3p(p-1)/(p(p-1))
=(p-1)^2/p -3 >=x

(p-1)^2>=(x+3)P
p^2-(x+5)p+1>=0

b^2-4ac should be >=0
(x+5)^2>= 4
X^2+10x+21>=0

so x<=-7 and x>=-3

3. if A varies as C and B varies as C, then which of the following is false?
note: assume ~to be the proportionality symbol
(a) (A + B) ~ C
(b) (A - B ) ~ (1/C)
(c) (AB)^(1/2) ~ C
(d)none of these

option is b.