[amar_sinha]

Originally Posted by nuttyvarun

that's what even I marked.. but OA is option E...

I am sure OA is wrong.. until unless someone can prove both of us wrong today..

Hi Varun,

The answer should be E.
Please find my explanation:

If x and y are positive, is x^3> y?
(1) (x)^1/2 > y
(2) x > y

Consider two cases:
When x=4, y=1.
These values will suffice the condition 1.
and condition 2. and the answer to the question will be yes x^3 > y.
If one uses these kind of value, he will make the mistake that both from 1 and 2 the statement can be answered. So the option D.

But consider the case:
x=1/4, y=1/5.

These values suffices condition 1. But x^3 is not >y.
These values suffices condition 2. But x^3 is not >y.

So statement 1 and statement 2 cannot answer the question. x^3 may be or may not be greater than y depending upon the values of x and y.
So the answer is E.

[guy with guts]

Originally Posted by nuttyvarun

good that someone agreed that E cannot be the answer..

BTW how come B.. if sq. root of x is greater than y, i.e. (x)^1/2 > y, then we have x > y... which is sufficient

so answer should be D and not B.. isnt it..??..

No.Try with x=.2 and y=.4.
I think the answer is indeed E only.

[amar_sinha]

I have posted the answer and explanation above. The answer should be E.

[amar_sinha]

Originally Posted by nuttyvarun

that's what even I marked.. but OA is option E...

I am sure OA is wrong.. until unless someone can prove both of us wrong today..

Varun, the numbers may be fraction also. So you cannot determine the numbers from the two statements.
So the answer should be E.

[amar_sinha]

Originally Posted by guy with guts

I think VMT>0 is given , the question can be rearranged as-
(v*m*t)^2*m/t^6
1.m>v2-cant say
2.m>t^-4 , so m>t^-6- so B is right anwer.



[/LEFT]

V^2.M^3.T^-4 = V^2.M^3/T^4.
Irrespective of the value of v and t being positive or negative, the value of V^2 and T^4 will always be positive. So the value of the function depend on M. If M is positive, the function will be positive else it will be negative.
From 1, we can conclude that m will be greater than zero as v^2 will always be positive.
From 2, we can conclude that m will be greater then zero as 1/t^4 will always be positive.
So the answer is D. Using either of the statements, the question can be answered.

[nuttyvarun]

Originally Posted by nuttyvarun

one more

What is the value of (x - y)^4?
(1) The product of x and y is 7.

(2) x and y are integers.

Originally Posted by guy with guts

C.From second we can conclude x,y is either 1 or 7.Being positive power , answer will alswyas be same.

Originally Posted by nuttyvarun

that's what even I marked.. but OA is option E...

I am sure OA is wrong.. until unless someone can prove both of us wrong today..

Originally Posted by amar_sinha

Hi Varun,

The answer should be E.
Please find my explanation:

If x and y are positive, is x^3> y?
(1) (x)^1/2 > y
(2) x > y

Consider two cases:
When x=4, y=1.
These values will suffice the condition 1.
and condition 2. and the answer to the question will be yes x^3 > y.
If one uses these kind of value, he will make the mistake that both from 1 and 2 the statement can be answered. So the option D.

But consider the case:
x=1/4, y=1/5.

These values suffices condition 1. But x^3 is not >y.
These values suffices condition 2. But x^3 is not >y.

So statement 1 and statement 2 cannot answer the question. x^3 may be or may not be greater than y depending upon the values of x and y.
So the answer is E.

Amar and Mr.Gutsy.. I believe both of u are getting confused with so many questions and posts.. incidentally both of u are talking sense only, knowingly or unknowingly

Amar.. I was talking about some other ques I guess whn I said option E was wrong.. but anyway, thanks for such eleborate explanation for the other ques.. appreciate it

[Praywin2005]

Hey crack this..
If x and y are consecutive odd integers, what is the sum of x and y?
(1) The product of x and y is negative.
(2) One of the integers is equal to –1.

[jigar_p_civil]

Originally Posted by nuttyvarun

one more

What is the value of (x - y)^4?
(1) The product of x and y is 7.

(2) x and y are integers.

i think both statement need to solve example

but if u have put What is the value of (x - y)^3? then it will more interesting...

[bhavin422]

Originally Posted by Praywin2005

Hey crack this..
If x and y are consecutive odd integers, what is the sum of x and y?
(1) The product of x and y is negative.
(2) One of the integers is equal to –1.

Ans A

St 1 : product is -ve, hence one is +ve and other -ve, so nos are -1 and 1 ...Sufficient

St 2 : if one integer is -1, other could be 1 or -3, not sufficient ..

[nuttyvarun]

Originally Posted by Praywin2005

Hey crack this..
If x and y are consecutive odd integers, what is the sum of x and y?
(1) The product of x and y is negative.
(2) One of the integers is equal to –1.

choice 1 itself is sufficient to answer the question... I wud hav emarked option A