[bhavin422]

Originally Posted by jigar_p_civil

for interest question both statement sufficient to solve question

st1 from D(t) u can find value of r and from r value u will find D(t) after 3 year

st2

from r directy u can solve


each one sufficiet

hi jigar....could you pls explain why st 1 is sufficient by itself...
if we know D(t) = 11000, how can we find r when t is also unknown...11000 may not be necessarily d amount after 1 year...it could be at any year t ...

11000 = (1+r/100)^t ..1 equation and 2 unknowns..not sufficient...

[jigar_p_civil]

Originally Posted by bhavin422

hi jigar....could you pls explain why st 1 is sufficient by itself...
if we know D(t) = 11000, how can we find r when t is also unknown...11000 may not be necessarily d amount after 1 year...it could be at any year t ...

11000 = (1+r/100)^t ..1 equation and 2 unknowns..not sufficient...

ya friend u totally correct

i am in half a sleep

[ramviswa]

1. B
2. C

[vikas130678]

Originally Posted by bhavin422

Q35S30:

Ans C

we are interested in median no of employees assigned per project..
all we need to know is the value corresponding to 50th percentile

St 1: 4 is 75th percentile..( since 25 percent of projects have 4 or more employees )...not sufficient

St 2 : 2 is 35th percentile (SInce 35 percent of projects have 2 or fewer employees ) ...not sufficient..

Both statements combined ....3 is the 50th percentile ...SUfficient...Ans C

Can you explain the percentile funda and your approach?

[bhavin422]

Originally Posted by vikas130678

Can you explain the percentile funda and your approach?

median is the middle value...half of the values are equal to or above median and other half are equal to or below median...

Percentile is the % of values equal to or below a given value...hence median is the 50th percentile ...

in the above sum, No of employees per project is always an integer value..

Hence, If suppose there are 100 projects...and if these projects are arranged sequentially acc to no of employees in every project, we want to know the no of employees in the 50th project...

hence , first 35 proj have 2 or lesser employees and last 25 have 4 or more...hence all proj from 35th to 75th have 3 employees ..(no ambiguity in no of employees for 50th proj...sufficient)

This translates to : 2 is the 35th percentile and 4 is the 75th percentile...there is only one integer between 2 and 4 which necessarily has to be the 50th percentile ..

hope this helps...

[srijack]

Someone pls explain this.

Is x an even integer?

(1) x is the square of an integer.
(2) x is the cube of an integer.

[bhavin422]

Originally Posted by srijack

Someone pls explain this.

Is x an even integer?

(1) x is the square of an integer.

(2) x is the cube of an integer.

Ans E...

St 1 : Perfect squares can be even or odd...not sufficient...
St 2 : Perfect cubes can be even or odd as well ...not sufficient...

ST 1 & st 2 : Sixth power of any integer wud be a perfect square as well as perfect cube...and sixth power of an integer cud be even or odd depending on whether integer is even or odd...not sufficient !!

[msalot]

Hey guys , thanks for the answers as well as the explanations !!!
the OA's are
for q10s30 its D(the explanition by bhavin is what i also assumed , but dunno y its mentioned D.Nonetheless i wud also go with B until someone provides some divine intervention on this one)
for q35s30 its C(got the explantion for this one,Thanks )

[ramviswa]

Originally Posted by srijack

Someone pls explain this.

Is x an even integer?

(1) x is the square of an integer.
(2) x is the cube of an integer.

Ans: E

1) - Insufficient as the square of an integer can be even or odd
2) - Insufficient as the cube of an integer can be even or odd

Comb. both of them ---> Sub. some value for which square of an integer = cube of an integer

4^3 = 8^2 ---> X is even
1^3 = 1^2 ----> X is odd

Insufficient

[shashank3012]

Originally Posted by srijack

Someone pls explain this.

Is x an even integer?

(1) x is the square of an integer.
(2) x is the cube of an integer.

1)x is the square of an integer=>x can end with 1,4,9,6,5,0 so,can be odd or even.

2)x is cube of an integer=>x can end with 1,8,7,4,5,6,3,2,9,0 so can again be odd or even

considering both the statements,x can be either odd or even.

option (E) cannot be answered by the data.