[raghav507]

Originally Posted by vpitc

1) if p, s, and t are positive prime numbers, what is the value of p^3s^3t^3?
(1) p^3st=728

(2) t=13
-----------------------

hi,
using (1)...
728 = (2^3)*7*13
so p=2, t and s can be 7 or 13
so exact value of expression cant be found out...

using (2)...
nothing can be said about the value of the expression given...as p and s are unknown...

combining both...
we get p=2,s=7,t=13
so the given expression can be evaluated...

PS:i m unable to interpret the expression properly...
if the given expression is (p)to the power(3s)to the power(3t)to the power(3) then it can be evaluated using both statements...
if it is (p^3)*(s^3)*(t^3) then it can be evaluated using first statement in itself...

[vaibhavwadhera]

Hi Prav

This is one of the questions which you have posted in the earlier Posts but i am not able to get the answer of the same..Can you please post the answer with the explanation for the same..

Here is one more......

In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many different victory circles are possible?

A) 24
B) 52
C) 96
D) 144
E) 648

Thanks & Regards
Vaibhav Wadhera

[bhavin422]

Originally Posted by vaibhavwadhera

Hi Prav

This is one of the questions which you have posted in the earlier Posts but i am not able to get the answer of the same..Can you please post the answer with the explanation for the same..

Here is one more......

In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many different victory circles are possible?

A) 24
B) 52
C) 96
D) 144
E) 648

Thanks & Regards
Vaibhav Wadhera

Is the Ans B ?

Assuming that same people with diff medals is a separate victory circle

Total ways :

1) GGG - 4! / 3! = 4
OR
2) GGS - 4! / 2! = 12
OR
3) GSS - 4! / 2! = 12
OR
4) GSB - 4! = 24

Total = 4+12+12+24 = 52

[Nipunbans]

I think, its B..

Ways to select any 3 ppl out of 4 = 4C3 => 4
Now, these 3 ppl can win in 4 formats:-
GGG, GGS, GSS, GSB (G=Gold, S=Silver, B=Brone)
GGG = only 1 arrangement => 1
GGS = 3 arrangements
GSS = 3 arrangements
GSB = 3! = 6 arrangements posssible
So, total = 1+3+3+6 => 13
And this is posible for each of those 4 selection in the first line.
So, 13*4 => 52..

Originally Posted by bhavin422

Is the Ans B ?

[Nipunbans]

IMO - E
1) 2C > 2J - 5... Insuff.. (C = Avg no. of book Carolyn reads, J = for jacob)

2) 5C = 5J +3 .. Insuff.

Together - Insuff..

Originally Posted by vpitc

2) During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

(1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

Give explanation...

[@nee!]

Originally Posted by Nipunbans

IMO - E
During a 10-week summer vacation, was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

(1) Twice the average number of books that Carolyn read per week was greater than 5 less than twice the average number of books that Jacob read per week.
(2) During the last 5 weeks of the vacation, Carolyn read a total of 3 books more than Jacob.

1) 2C > 2J - 5... Insuff.. (C = Avg no. of book Carolyn reads, J = for jacob)

2) 5C = 5J +3 .. Insuff.

Together - Insuff..

Dont u think 1 is sufficient ?

2C > 2J - 5... (C = Avg no. of book Carolyn reads, J = for Jacob)

dividing it with 2
C > j - 2.5

So , as asked in the kostin
was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

The answer would be YES !!

P.S : correct me if i am wrong !!

[Nipunbans]

Lets Suppose Jacob read / week, J = 20 books
Then Carolyn reads >= 20 * 2 - 5
So, carolyn reads more than 35 books in 2 weeks. It can be 18/week or 19 or 20 or 21 and so onn.
So insufficient

Originally Posted by @nee!

Dont u think 1 is sufficient ?

2C > 2J - 5... (C = Avg no. of book Carolyn reads, J = for Jacob)

dividing it with 2
C > j - 2.5

So , as asked in the kostin
was the average (arithmetic mean) number of books that Carolyn read per week greater than the average number of books that Jacob read per week?

The answer would be YES !!

P.S : correct me if i am wrong !!

[vpitc]

1) Each side of a certain parallelogram has length 6. if the area of the parallelogram is 18.which of the following is the measure of one of its angles?
A. 30’ B. 45’ C. 60’ D. 90’ E.120’

[Nipunbans]

Area of ||gm = perpendicular * base
18 = perp. * 6 => perp. = 3. Now, its a triangle with perp. = 3 and hyp. = 6
So, Sin A = 1/2 => A = 30'

Originally Posted by vpitc

1) Each side of a certain parallelogram has length 6. if the area of the parallelogram is 18.which of the following is the measure of one of its angles?
A. 30’ B. 45’ C. 60’ D. 90’ E.120’

[vpitc]

If M is a positive integer, then M^3 has how many digits?
(1) M has 3 digits.

(2) M^2 has 5 digits

is there any shortcut.....