Quote:
Originally Posted by bluefalcon.7691 QUestions I was not able to solve.Please find time to solve and respond:
1: For every positive integer n h(n) is product of all even interegrs 2 to n inclusive.If P is the smallest prime factor of h(100)+1 , then p lies between:
Options are:
A: Between 2 and 10
B:Between 10 and 20
C:Between 20 and 30
D:Between 30 and 40
E: greater than 40
2:Alice's take home pay last year was the same each month and she saved the same fraction of her take home pay each month.The total amount of money that she had saved at the end of the year was 3 times the amount of that portion of her monthly take home pay that she did not save. If all the money that she saved last year was from her take home pay, what fraction of her take home pay did save each month.
Answer options:
A 1/2
B 1/3
C 1/4
D 1/5
E 1/6 |
2nd question one is already answered so i will answer only the 1st one.
Well h(100) + 1 = > 2*4*....*100 + 1 ==> (2*1)*(2*2)...*(2*50) + 1
so we can reduce h(100) + 1 = 2^50(1*2*...*50) + 1.
for any given number to be a factor of h(100) + 1 , the entire h(100) + 1 , should be divisible
Since all numbers from 2 to 50 is a factor of h(100) , then none of them can be a factor of h(100) + 1.
Thus answer is E , greater than 40