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CAT 2009 Study Group-Kolkata
CAT and Related Discussion Discuss information and B-schools under the toughest and most exclusive management entrance exam in India. The CAT - The Common Admission Test.

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Re: CAT 2009 Study Group-Kolkata - 27-08-2009, 11:58 AM

CL PROC 4

DI-22
QA-29
VA-36
OA-87

Your Projected Percentile for Proc Mock-4 as per the CLPP model is : 85.56

The Projected Percentile for CAT 2009 as per the CLPP model is : 92.43
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Re: CAT 2009 Study Group-Kolkata - 27-08-2009, 11:59 AM

In a colony, there are 350 residents. The number of residents who smoke cigar, hookah and cigarette as a percentage of the total number of residents is atleast 40%, atleast 30% and atleast 22% respectively.
If 50% of the residents do not smoke, then at most how many residents smoke exactly one of cigar, cigarette and hookah?
1)70
2)175
3)50
4)91
5)98


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Re: CAT 2009 Study Group-Kolkata - 27-08-2009, 12:48 PM

Quote:
Originally Posted by lopamudra0303 View Post
Puys plz help me with this....


The value of a quadratic function f(x) is a negative for all values of x, except for x = 2. If f(x = 0) = –10, then find the value of f(x = –2).

1)-80
2)-60
3)-40
4)-20
5) Data inconsistent
The function is f(x)=-10/4*(x-2)^2 at x=-2 =>f(-2)=-40 Option (3)


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Re: CAT 2009 Study Group-Kolkata - 28-08-2009, 12:13 PM

Quote:
Originally Posted by lopamudra0303 View Post
Puys plz help me with this....


The value of a quadratic function f(x) is a negative for all values of x, except for x = 2. If f(x = 0) = –10, then find the value of f(x = –2).

1)-80
2)-60
3)-40
4)-20
5) Data inconsistent
c we have a fn which has a negative value throuhgout but is non negative at x=2,, so 2 is one of the root of the eqn , but the fn is has all other neg. values so we conclude that both of its root are 2 so the fn is of form
f(x)= k(x-2)^2, where k is a -ve no.
for x=0 f(x)=-10
so k= -2.5
so x= -2 gives f(x)=-40
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Re: CAT 2009 Study Group-Kolkata - 28-08-2009, 03:58 PM

Quote:
Originally Posted by apocalyptic View Post
Each side of equilateral traingle subtends an angle 60 at the top of the tower h mts high located a centre of triangle. If s is the length of each side find h.


plz solve this in details ...i am getting ans as h=s ..is that correct?


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Re: CAT 2009 Study Group-Kolkata - 28-08-2009, 04:24 PM

attention kolkata puys....the announcement to PG Premier league teams has been made.check this link.
http://www.pagalguy.com/forum/cat-an...ml#post1643943 (The PG Regional Dream Team 2009 Discussions Thread)

So, here comes KDT-09.

So,let the game begin!!!

p.s.please dont open a separate thread for kdt-09.let our coach/mentor be the first one to post in the sacred thread for kolkata puys.

p.p.s.link for kdt-09 thread-
http://www.pagalguy.com/forum/showth...6&goto=newpost ([2009] Kolkata Dream Team)


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Last edited by rahulgupta08; 28-08-2009 at 06:01 PM.
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Re: CAT 2009 Study Group-Kolkata - 29-08-2009, 02:22 AM

Quote:
Originally Posted by lopamudra0303 View Post
plz solve this in details ...i am getting ans as h=s ..is that correct?
Each side of equilateral traingle subtends an angle 60 at the top of the tower h mts high located a centre of triangle. If s is the length of each side find h.
no i think the sides will make an eqt triangle which will be oblique
this is a case of pyramid whose base is traingular so we can think of height to be the height of this pyramid it will be s sin60 .
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Re: CAT 2009 Study Group-Kolkata - 29-08-2009, 09:07 AM

Quote:
Originally Posted by catdreams View Post
Each side of equilateral traingle subtends an angle 60 at the top of the tower h mts high located a centre of triangle. If s is the length of each side find h.
no i think the sides will make an eqt triangle which will be oblique
this is a case of pyramid whose base is traingular so we can think of height to be the height of this pyramid it will be s sin60 .

this is what i am getting...
base = 1/3 x sqrt3 / 2 x s = s/ 2xsqrt3


now h/ b= tan 60 = sqrt3 ............n by solving i am getting s/2


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Re: CAT 2009 Study Group-Kolkata - 29-08-2009, 11:21 PM

IIM B oout with CAT demo....



http://www.iimb.ernet.in/cat2009/cat%20demo/index.htm


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Re: CAT 2009 Study Group-Kolkata - 30-08-2009, 12:18 AM

sorry for being rather off-topic :

can anybody pm me the name and email id of TIME center head of Jodhpur Park ?
I am tired of explaining my problem to the receptionists over there.


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