[varunriyer]

@ bkd
376 is right i guess [] i got the same ans.
375 nos + 4000 as well = 375



ne updates on the seed question?

and obtuse angled triangle as well ? i marked 15 , but i guess it shud b 14
one of the traingles will b 15,15,8 which would make it isosceles and hence not obtuse .....

wat say ?

horses i got

three horses between white and red

and

white came in second


confirm pls

[mjp1618]

Originally Posted by vibhu_kk

@varunriyer
how about the How many integers greater than 999 but not greater than 4000 ?

and the question on Seed ???



darn i took 4000 as 40,000 and tried solving the question, screwed a sitter

Puys anyone for f(x)=ax^2+bx+c f(5)=-3f(2).....
my answer was -4!!!!!!!!!

Yep, I got the same. What about the second question in that set?

The equation is (x^2 + x - 12) right? So a=1, b=1, c=(-12). So a+b+c is (-10) right? :confused:

[think.thru.5]

Originally Posted by varunriyer

@ bkd
376 is right i guess [] i got the same ans.
375 nos + 4000 as well = 375



ne updates on the seed question?

and obtuse angled triangle as well ? i marked 15 , but i guess it shud b 14
one of the traingles will b 15,15,8 which would make it isosceles and hence not obtuse .....

wat say ?

horses i got

three horses between white and red

and

white came in second


confirm pls

376 is right

[siauniverse]

did any one get the answer to obtuse angled triangle question 8,15,x?
i got the answer to be 5

[Expert@CL]

sure if u have an accuracey of 90%,u have a descent chance of clearing the cutoff

Originally Posted by sweetgalshruti

My form no was 222
Quants was tough but I managed to do 9 questions
Hope to clear my weak area of :meow: :meow:

[think.thru.5]

you can also haeve f(1)=0 just check

[jan_sunil]

Originally Posted by vibhu_kk

@varunriyer
how about the How many integers greater than 999 but not greater than 4000 ?

and the question on Seed ???



darn i took 4000 as 40,000 and tried solving the question, screwed a sitter

Puys anyone for f(x)=ax^2+bx+c f(5)=-3f(2).....
my answer was -4!!!!!!!!!

-4 is the only root for which f(5) = -3f(2)
f(x)=(x-3)(x+4) = x^2+x-12, f(2)=-6 and f(5)=18

[bharat131]

what was the sum coming out of a+b+c?? in th f(x) question

[vibhu_kk]

Originally Posted by mjp1618

Yep, I got the same. What about the second question in that set?

The equation is (x^2 + x - 12) right? So a=1, b=1, c=(-12). So a+b+c is (-10) right? :confused:

wasn't really sure but i got a=b and c=(-12a)
left it there; got stuck, know i was there:(

[think.thru.5]

Originally Posted by siauniverse

did any one get the answer to obtuse angled triangle question 8,15,x?
i got the answer to be 5

its strts at 8,15, 8
8,15, 9....

and ends at
8,15,22

So, 15 triangles