[shivam_01]

Originally Posted by jain12345

here goes the third one

3. The number of solutions of the equation is
(a) 4

(b) 2

(c) 1

(d) 0

Equations please and by the way waht is this Spark ?????

[warrior16nov.]

Originally Posted by jain12345

hi guys here goes the second question

2. In copying a quadratic equation of the form x^2 + px + q =0, a student wrote the coefficient of x incorrectly and the roots were found to be 3 and 10; another student wrote the same equation but he wrote the constant term incorrectly and thus he found the roots to be 4 and 7. The roots of the correct equation are.
(a) 5,6

(b) 4,6

(c) 4, 5

(d) None of these

is the answer option a

[jain12345]

Originally Posted by shivam_01

Equations please and by the way waht is this Spark ?????

oops sorry

its 2x^2 + 9lxl-5 = 0

[shivam_01]

Originally Posted by jain12345

oops sorry

its 2x^2 + 9lxl-5 = 0

4 solutions .....

[jain12345]

Originally Posted by shivam_01

Equations please and by the way waht is this Spark ?????

hi SPARK is a classroom coaching in pune..
i joined the free workshop.

[jain12345]

Originally Posted by shivam_01

4 solutions .....

no its not 4

[shivam_01]

Originally Posted by shivam_01

4 solutions .....

how can i do it wrong
its 2 solutions when x>0 x= 1/2
and when x<0 x = -5

[implex]

Originally Posted by shivam_01

4 solutions .....

it can't be 4
sum of roots is - and product of roots negative
so one root is positive and one root neagtive
hence given the mod in the question
we shall have 2 roots

[jain12345]

@shivam_01

now u got it correct

here goes the next one
4. If a, b, c Є {1,2,3,4,5}, the number of equations of the form ax ^ 2 + bx + c = 0 which have real roots is
(a)25

(b) 26

(c) 27

(d) 24

[shivam_01]

Originally Posted by jain12345

@shivam_01

now u got it correct

here goes the next one
4. If a, b, c Є {1,2,3,4,5}, the number of equations of the form ax ^ 2 + bx + c = 0 which have real roots is
(a)25

(b) 26

(c) 27

(d) 24

condition is b^2 >= 4ac Real roots

hence when b = 2 => a,c =1 1 value
=> b = 3 a,c = (1,1) (1,2) (2,1) ... so on

total 25 values