Quote:
Originally Posted by monsterkartik Regarding the way i did that quant question. would like deepanshu, to check whether is this way correct or not
The total money distributed is
100*190 = 19000
200*220 = 44000
300*180 = 54000
Total 117000
The total money received by the students who came more than once
30*800 = 24000
40*700 = 28000
60*600 = 36000
20*300 = 6000
Tota 94000
So that means the left over money ie 117000-94000 = 23000 has to be divided in a way that there are maximum no. of students.
For this there are many combinations possible viz
and with one combination the number of students is 360, also u can get combination where the number of students are 350 and hence i took the answer as 350
Cheers
MK |
Hey MK!
friend! M a lil apprehensive abt this approach,suppose 360 and 350 both are in options. ???
Now, since 23000 is left, so one can only divide that money in terms of 100,200 and 300...
hence x+2y+3z = 230...now how does one know that what be can the right value of x,y,z. ???
The exact value is surely dependent upon the way one distributed the money earlier....like 30 boys got 800,so to maximise
x(100s), i will make sure that i use more amount of 300s and 200s rather than 100s. hence i wud get an exact usage of 300s and 200s in this combo
Similarly proceeding one can get all the exact usages of in every combo..
and finally a concrete answer in terms of x,y,z and that wud be 350.
Although if you got it correct in the paper then

.
Regards!
Marijuana!