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08-10-2008, 09:14 PM
Quote:
Originally Posted by ramaan
and another problem no 13..number of players sitting around a circular table..i didn't understand the qn itself...if he received the card no 15..then the next time he will receive the card with the multiples of 15 only..then how he receives the card num 87..?
And i think remaining problems are all okay.. | suppose there were only 2 players. take player A and player B. A receives 15,17,19... inc 87 (ie) all odd cards. similarly, if u take that there r 3 players, A will receive the 15th, 45 and 87 again (all multiples of 3). ur assumption is valid only if if there r at least 15 players at the table.
mock 05 scores:
QA: 82.15 (30)
DI: 93.72 (43 - since that q 49 was not considered they happily deducted 4 marks)
VA: 99.85 (53)
OA: 99.12 (126)
Last edited by an_elusive_lady; 08-10-2008 at 09:18 PM.
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RC Marathon...
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09-10-2008, 04:11 AM
Quote:
Originally Posted by nishant_rungta Team
A few doubts in the AImcat 05
1. What is the sum of the series 1/5*8 + 1/8*11 + 1/11*14 + .... + 1/242*245 ?
Can someone explain in a better way!! I din understand a bit from the solution but for the fact that there are 2 APs here!! What next??
2. If a*b*c is not equal to 0 and 2a^2 + 17b^2 + 8c^2 - 6ab - 20bc =0, then whats the value of a+b-c/a+b+c? | 5*8 .. 8*11..
5,8,11
8,11,14
sowe can think of it as (1/an - 1/a(n+1))
different is n .. so 1/n (n/an a(n+1))
about the other
2a^2 .. well its not possible to make it a perfect sqaure like this
so we multiply it by 2
4a^2+34b^2+16c^2-12ab -40bc = 0
(2a-3b)^2 + (5b-4c)^2 = 0
ence 2a =3b and 5b =4c
so we get 1/3 answer | | | | | The Following User Says Thank You to Varun Khullar For This Useful Post: | | | | | |
will I make it?
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09-10-2008, 09:57 AM
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WISHES ALL THE VERY BEST TO CAT :fist: :D
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09-10-2008, 05:05 PM
Wrote Simcat 11 today!!
VA - 21.5
QA - 11
DI - 27.5
OA - 60
Clearing all the cut offs!! But no idea about the percentile figures
Can some please help me out?? The Simcat rank would be a great add-on too 
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is learning to become an efficient multi-tasker!
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09-10-2008, 05:17 PM
Your QA score corresponds to 96.02 percentile.
Your DI score corresponds to 98 + percentile.
Your VA score corresponds to 92+ i presume,nishant.
great scores!
OA- MUST be 99 percentile. | | | | | The Following 3 Users Say Thank You to catgotmytongue For This Useful Post: | | | | | |
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10-10-2008, 08:20 PM
Hi all,
Saw this article in a magazine. Thought it would be helpful for u all... jus 36 days more days to go .. here we go.. IIM entry - the battleground beckons:
THIS year yet again, on the third sunday of November, the nation would indulge in a fierce battle of wits. The fighters, battleground and even th
e intensity of the battle would change but the prize would remain the same as before — a coveted seat in one of the best management institutes in the country. I was fortunate enough to bell the CAT in 2007, in my second attempt at it. Having failed at the first attempt and succeeding at the second, I feel I have some useful insights that will help you in understanding what works and what does not in terms of CAT preparations.
CAT is an exam that requires you to optimise and not maximise returns. Unless you start thinking of it as a fundamentally different exam, it would be hard to crack CAT. These are few small things, which can make a big difference and go a long way in ensuring success. KNOW YOURSELF AND SUIT YOURSELF
Throughout your preparation keep it in mind that you are different. You'll hear a lot of advice from teachers, seniors and friends about test taking strategies. Listen to all of that, but choose what works best for you. The only advice I can think of is — join a test series with some preparation institute. That not only brings a structure and discipline to the whole preparation but also keeps you abreast of what your competitors are learning. SPEND TIME IN ANALYSIS AND REFLECTION
The CAT preparations entail a lot of analysis and reflection as compared to most other exams. After every test you take (and take at least one in a week starting today) you should analyse the mistakes you made, the section that didn't go well and most importantly the concepts you muddled up in. In the subsequent week, just do a concentrated preparation on these subject areas through textbook and practice exercises. The trick is to unravel the root cause of the problem and not the symptoms. BE ADAPTABLE AND FLEXIBLE
There is no official course material for CAT, no fixed format and no syllabus. So, an important point is to stay adaptable and let the format of the test decide how you perform at it. The most difficult question of optimisation in CAT is to decide which section to attempt first and how much time to give to it. Another problem is when to leave the question you think you know. I'd say practice all possible strategies during preparation. Change the order of sections, time per section and choice of questions. And throughout the exam, remember, you have to maximise your score in minimum time. BRACE YOURSELF FOR THE D-DAY
The day of the exam will be a lot different from other tests you'd take during preparation. I, for example, was never a consistent performer in the test series I joined. In fact, of the 12-odd test series exams I undertook during preparation, I crossed 99 percentile only once. So did I get lucky on the day of the exam? Obviously, I would like to think otherwise. On that day everything comes down to a test of nerves. Many serious aspirants tend to under-perform on the D-day on account of nervousness. Hence, a positive frame of mind is imperative. Do anything that works for you but feel confident about yourself that day and think of it like another test you are about to take. Past performance, incomplete syllabus, the fear of a section — all this should be replaced by one encompassing belief — today is my day. And that would make all the difference. | | | | | The Following 8 Users Say Thank You to naga25french For This Useful Post: | | | | | |
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14-10-2008, 08:52 AM
Why is this Thread dormant  ??
anywayz FMS notification is out.attaching the PDF along with this post. Important Dates- Sale of Forms : 20th october to 1st december
- Date of Admission Test : 11th january 2009
- Last date for submission of forms : 1st december 2008
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14-10-2008, 05:09 PM
Logging in after a long time!!!
And I am seeing its the same with the rest also...where is everyone??
Anyways..here are my sim 11 scores...
again a less than avg performance DI-4.7...(this was the last section i attempted i left off in a hurry.. 20 mins before the time..impatience  ) VA-10 QA-7(Though this wont sufficeto clear the cut off m glad that i gained 100% accuracy-attempted 7 and got 7 correct) Overall-21.7 | | | | | | | |
will I make it?
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14-10-2008, 05:37 PM
Team!!
Doubts!!
1) What is the remainder when 12341234...... 400 digits is divided by 909? (I solved this one, but the solution was lengthy.  )
2) Find the remainder when 3^1001/1001. (Pref by Chinese remainder theorom. I've a few doubts in that concept)
3) Find the remainder when 1^7 + 2^7 +... +100^7 is divided by 202?
P.S: Anyone has last 10 years CAT papers? | | | | | The Following User Says Thank You to exile For This Useful Post: | | | | | |
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14-10-2008, 07:36 PM
Quote:
Originally Posted by exile Team!!
Doubts!!
1) What is the remainder when 12341234...... 400 digits is divided by 909? (I solved this one, but the solution was lengthy.  )
2) Find the remainder when 3^1001/1001. (Pref by Chinese remainder theorom. I've a few doubts in that concept)
3) Find the remainder when 1^7 + 2^7 +... +100^7 is divided by 202?
P.S: Anyone has last 10 years CAT papers? | for qn 1
first divide the first 4 digits by 909.u get a rem of 325.
now since its for the first 4 digits we got to multiply it by 100 to get it for 400 digits.
so u get 325000/909 which is 685.
Note :this is the standard pattern for such kind of problems! for qn 2 im getting 291 as the answer.if its right let me know.il post the soln..solved using chinese theorem.
i dont know if im right..in case im wrong pls correct me..
now 1001 is split as 13*11*7
so 3^1001/1001 is written as
3^1001/(13*11*7)
first 3^1001/13
(3^3)^333/13 is 9 as 27/13 gives rem as 1.
next 3^1001/11
((3^10)^100*3)/11 is 3 cos 3^10/11 rem is 1.
next 3^1001/7
((3^6)^166 * 3^5)/7 is 5 as 3^6/7 rem is 1.
so we can write 13x+11y+7z=1
here x=4,y=-4 and z=-1
we get 52-44-7 =1
so to find rem we use
(13*9*4)+(11*-4*3)+(7*-1*5)
= 468-132-35 = 291!!!
so answer is 291.
Last edited by getintoiimb; 14-10-2008 at 08:03 PM.
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