Quote:
Originally Posted by nishant_rungta Team
A few doubts in the AImcat 05
1. What is the sum of the series 1/5*8 + 1/8*11 + 1/11*14 + .... + 1/242*245 ? |
More often than not, i try to look for a pattern in such questions by breaking the entire term into small parts..
Here, i added the first two terms first.. 1/(5*

+ 1/ (8*11)
on solving, i got 2/(5*11)
Then, i added the first three terms .. 1/(5*

+ 1/ (8*11) + 1/(11*14)
On solving i got, 3/(5*14)
So, i observed that the numerator was the no. of terms i added and the denominator was the product of n1 and n2
n1= first no. in the denominator of the first term
n2= second no. in the denominator of the last term in the series.
So, in the given question, it would translate into n/( 5*245)
I found out the no. of terms in the series-
245=8+(n-1)3 (since common diff is 3)
n=80
so, answer should be 80/(5*245) = 16/245
is the answer right??? i remember solving it this way at my place after the mock..