posting after a very long time guys .
for all working professionals i have got a fundu site tenaday.co.in
all papers are of just 10 min all are daam dificult.
just solving these papers whenevr i get time in my IT Job :new_ukliam2::new_ukliam2:
was solving some q related to clock so samja bhaai apna funda clear nahi hae.
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That’s no help to if you are late to school is it??
To be able to solve problems about clocks quickly you must remember certain points. We’ve summarised those points below. Most are self-explanatory and for the rest, please accept our word and then work out on your own the how and the why.
The face(or dial) of a clock is divided along its circumference into 60 equal spaces called minute spaces. The minute hand moves around the whole circumference of the clock once in One Hour. The hour hand moves around the whole circumference of the clock once in 12 hours.
Thus,
the minute hand is 12times faster than the hour hand.
The minute hand passes over the 60minutes spaces, while the hour hand goes over the 5 minute spaces.
That is, in 60minutes, the minute hand gains 55minutes over the hour hand or 55/60 minute spaces in 1 minute.
Some Important Points- 1 minute space = 360/60(Since 360degrees of the circle is divided into 60minutes.
- In 1 minute, the minute hand moves 6degrees
- In one minute, the hour hand moves 360/(12 x 60) = 360/720 = 0.5degrees
In 1 minute the minute hand gains 5.5degress over the Hour hand
- The hands Coincide once i.e. they are 0 degrees apart
- The hands are twice at Right Angles (90degrees apart) .In these positions, the hands are 15 minute spaces apart.
- The hands point in Opposite direction(180degrees apart)once.In this position , the hands are 30minute spaces apart.
- The hands coincide 11 times in every 12 hours ( between 11 and 1 O’clock there is a common position at 12). Hence in a day the hands coincide 22 times
- The hands coincide every 65(5/11 ) minutes
To Find the Angle Between the Hands
Angle Theta = |30h - (11m/2)| where h = hour and m =minutes
Q.At what time between 4 and 5 will the hands of a watch coincide?
Solution:
Applying the above formula, we know that h has to equal 4 since between 4 and 5 the time will obviously read 4:__
Now if the hands coincide it means that the angle between them is 0.
So we finally have 0 = |30(4) -(11m/2)|
120 = 11m/2
or m = 240/11 minutes = 21 (9/11)minutes
which means at 21 (9/11)minutes past 4, the hands will coincide
Can you do solve for when the hands will be at Right Angles and when the hands are in Opposite Direction?
Incorrect Clocks:
A clock which gains or loses time is called an Incorrect clock.In incorrect clocks, both hands coincide at an interval
not equal to 65(5/11) minutes.
For Slow Clocks(for clocks that lose time)
Total time lost in T hours = (T x 60) { X-65(5/11)}/X minutes
where X is the time in which the hands of the incorrect clock coincide.
For Fast Clocks(for clocks that gain time)
Total time lost in T hours = (T x 60) { 65(5/11)-X}/X minutes
where X is the time in which the hands of the incorrect clock coincide.
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will keep posting if i get anything interesting
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