Triangle ABC and BDC are two right angled triangles with common hyptnse BC. The sides AC and BD extended to intersect at P. Then (APXAC)/(DPXPB)=??I wonder if they actually intersect… if BC is common hyptnse, then aren’t AC and BD parallel?..pls…

Triangle ABC and BDC are two right angled triangles with common hyptnse BC. The sides AC and BD extended to intersect at P. Then (APXAC)/(DPXPB)=??I wonder if they actually intersect... if BC is common hyptnse, then aren't AC and BD parallel?..pls explain