Two bodies A and B start from opposite ends P and Q of a straight road. They meet at a point 0.6D from P . Find the point of their fourth meeting. hw to solve this type of question
@nidhiv said:Two bodies A and B start from opposite ends P and Q of a straight road. They meet at a point 0.6D from P . Find the point of their fourth meeting. hw to solve this type of question
as time is constant
speed ratio is 3:2
THEY WOULD HAVE COVERED A TOTAL DISTANCE OF 70 AFTER THIER 4TH MEETING
A covered 42 and B covered 28
now tracking we can see that A is .2D from P
sry i didn't get the last point
if A covered 42
then we can break it into 10 from A to B
10 from B to A
10 from A to B
10 from B to A
then 2 from A
so now A is at .2D from A
A and B working separately can do a piece of work in 6 and 9 days respectively; they work on alternate days starting with A on the first day. In how many days will the work be done? Please help me explain the same.
- 10 days
- 3 days
- 7 days
- 11 days
Shaurya and Arjit take a straight road to the same terminal point and travel with same constant speed. At the initial moment, the position of two and terminalpoint forms an quilateral trianle. When arjit covered a distance of 80km, the triangle becomes right-angled. When Arjit waas at a distance of 120 km from the terminal point, shaurya arrived at the point. FInd the distance between them at the initial moment assuming there are integral distance throughout the moment described.
The number of days taken by A and B together to complete a piece of work is the ratio of 6. When you sum up the no of days taken by A and B separately u will end up in a 2 digit prime no. What's the no of days taken by them to do the work together
How to solve this?