The PaGaLGuY UnderDogs Team 2012

MBA CAT 2024
1841
@nits2811 said: As Promised solutions at 11 PM
OA for DI SET 1
1) A
2) D
3) C
4) B
5) A
If any1 has any doubt in any key u can let me kno..wld give u the solution as well...
Although I got them correct, but I would like to know a quicker way to approach them. I was manipulating the numbers here and there, and hence took a bit of time 😞
1842

Random grammar stuff. Threw up a few surprises, might be useful. I am still not convinced about "since" and "because"!



1843
QA-
OA 1. 125%.. easy hi.. 😃
2. 62%..
There are 336 seats in the theatre.
Let x be the total number of empty seats in the front row.
Number of occupied seats in the front row = 2x
Number of seats in the front row = 3x
Number of rows between the first row and the first empty row = x
Number of rows = 1 + x + 5 = x + 6
(x + 6) × 3x = 336
Factorizing, 336 = 3 × 8 × 14
∴ x = 8
Total occupied seats = 2 × 8 + 3 × 64 = 208
Percentage of occupied seats = 208/336 × 100 ≈ 62%
Hence, option 4.
1844
@nits2811 Please provide the solution ... am getting D as the answer for the fourth question ...

1845
QA: An insight into Quadratic Eqn (found this article very useful)


1846

Sorry guys due to my erratic net connection not able to post the solution..kal subha hi post kar paunga...


1847

Sorry guys due to an erratic net connection not able to post the solutions..wld do the needful 2morow morning...

1848
SCHEDULE
QA
Ratio proportion, mixtures, averages and alligations
Rest remains the same

PS:- Guys agar aisa chalta raha toh v wont b able to survive this phase...common v need more contribution...i cannot be all the time on PG to luk after...its just a month away...if every1 can come online and post something meaningful...it hardly takes 5 mins at max...
So many ppl had sent me a PM...please include me please include me...CAN i ask them where wr they 2day..??
Its easy to just come onlin..luk up the thread ..read all the stuff..solve and go...but don't u think u can also contribute something...if slowly each and every1 pitches in...it wld such a revered thread on PG...with intense learning..
PLEASE ITS A REQUEST...
1849
@nits2811 Hey hw r u planing to do phrasal verbs and homonyms...I hv an idea, as among us we all gt almost all the test series...y nt we sit back and compile list f phrasal verbs and homonym asked in our test series and then exchange the list among themselves....I m sure thru this we can get a comprehensive list...wat do u think???
1850

I have some ebooks frm TG.. on some QA concepts.. if some one need can PM me his/her email id./

1851
@pratskool I have 3 books on Numbers, TSD and Geometry. Are these the same that you are mentioning?
1852
@RoadKill said:
@pratskool I have 3 books on Numbers, TSD and Geometry. Are these the same that you are mentioning?
hmm.... just 2 extra....
1853
@pratskool said: I have some ebooks frm TG.. on some QA concepts.. if some one need can PM me his/her email id./
Barring Numbers, TSD and geometry send me the extra two [email protected]
1854
@abhi_14 said:
@nits2811 Hey hw r u planing to do phrasal verbs and homonyms...I hv an idea, as among us we all gt almost all the test series...y nt we sit back and compile list f phrasal verbs and homonym asked in our test series and then exchange the list among themselves....I m sure thru this we can get a comprehensive list...wat do u think???
Actually what i wanted to do is...v can first go thru the homonyms and Phrasal Verbs that have appeared in CAT and then go thru the mocks wala...yaar compile karke faida isliye nhi hain na..coz vocab khud se karna is very boring and when u discuss it...it gets interesting...that's y i wanted every1 to post 5 pairs everyday...thread pe discussion ho sakta h..and discuss karke cheezen dimag mein baith bhi jaati hain..
1855
DI Set 1 Solutions

1) As he had different scores in different matches and
the sum of his top five scores as well as the sum of
his lowest five scores are given, the average of the
player will be the highest if his 7th highest to 7th
lowest score are as high as possible (when scores are
arranged in ascending order).
Seventh score will be highest if the top six scores
are as close as possible:
70 + 71 + 72 + 73 + 74 + 75 = 435
Hence the seventh highest score = 69
Now, to find the highest possible average we have to
assume the 7th to 24th scores as 69 to 52.
The least five scores also contain 48 and 49.
Highest possible average 30
= 435 +153 + (60.5)×18
= 588 +1089 = 1677/30
= 55.9

2) Total runs scored in 30 matches = 30 × 45.2 = 1356
Runs scored in remaining 22 matches
= 1356 – (435 + 48 + 49) = 824.
Assume that the runs scored in 7th match onward
are 69, 68, 67, ....., 50.
Total sum in these 20 matches = 10(50 + 69)
but it is greater than 832, hence it is not possible.
So, we have to start from minimum value such that
their sum is 832.
832 = [50 + 50 + (n-1)1]n/2
⇒ 1664 = n(99 + n)
Hence maximum no of fifties scored by the batsman =
14 + 6 = 20.

3) The lowest possible score in centuries can be 100
and 101. The remaining top 4 innings account for
435 – (101 + 100) = 233 runs.
To find the maximum value of the lowest score, we
have to assume that all the scores are as close as
possible. The 3rd, 4th, 5th and 6th scores may be
62, 58, 57 and 56.
The remaining 24 scores can be successively one less
than 56 and the maximum value of the lowest score
can be
(55 – 24 + 1) = 32

4) We have to make the sum of the six lowest scores as
153 such that they are as close as possible. And,
23 + 24 + 25 + 26 + 27 + 28 = 153
The remaining eighteen innings may be consecutive
ie 29, 30, 31, ....., 46.
25th innings – 47
26th innings – 48
27th innings – 49
28th innings – 50
29th innings – 51
30th innings – 435 – (51 + 50 + 49 + 48 + 47)
= 435 – (245) = 190.

5) For highest possible score
(i) first six scores may be as close as possible
ie 70 + 71 + 72 + 73 + 74 + 75 = 435
(ii) seventh and onward scores may be
69, 68, ......49, 48, 47, 46.
Hence, the highest possible score = 75.
1856
1857
@anupam001 said:
isme thode errors bhi hain sir... kuch ke explanation bhi sahi se nahi aa ahe .. but a gud resource.,
1858

Q) 72 Hens cost _96.7_ . What is the cost of each hen if numbers marked "_" are not visible or are written in illegible hand?

1859

Q) Two towns A & B are 100 km apart. A school is to be built for 100 students of town B and 30 students of Town A. Expenditure on transport is Rs 1.2/km/person. If total expenditure on transport by all 130 students is to be as small as possible, then school should be built at..
a) 33 km from town A.
b) 33 km from town B.
c) town A.
d) town B.

1860
@ankit3007 let distance from town A be d. Cost for students in A will be 30*1.2=36 per km. Similarly, for B it will be 120 per km. We have to minimize 36d+(100-d)*120 = 12000 - 84d. Maximize d and we get the answer = town B.