The school is not safe and must be pull/pulled down??????pull or pulled??
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No of triangles
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odd one out..
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Elaborate explanation, please?
which is the best website for online test series for tier 1 ...???
please help
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EIGHT THOUSANDERS.
2^60, 3^48, 4^36, 5^24...........which is greater....procedure???
I am practicing from Kiran yearwise solved papers book(1999-Till date) for quant. Is it same as chapterwise solved papers by Kiran?
What is the best way to improve FINDING MISSING NUMBERS (Reasoning) -- practise from kiran chapterwise OR preparing from some book/blog/youtube video and then practise. TYIA
During 5Am to 10pm , how many times both hands make an angle of 90° ? How to solve such questions ?
Trypophobia?? anybody
Today's topic plays a vital role in ssc cgl tier 1 as well as tier 2 ......... ************ ALGEBRA ***************
this topic takes too much time if there is no alternative way while we have to focus how to consume less and less time .............
now , I will discuss only a few question for this chapter :-
problem type 1 :-
if 2x+1/3x =5 .... then 5x/(6x^2+20x+1) =? ...
solution :- we see that the given value is 5 ....... now what logic we must apply first .... first we must see whether there is a quadratic question exist with solution or not .... so , NO ..... no such equation where solution exists ... ( by calculating B^2-4AC value )
now , we adjust given problem in such cases :- ( try every way but do practice of such questions taki dimaag me ek pattern ban jaye ki pahle mjhe kya karna hain .... varna ghumte rhe jaoge ) ...
now , we see denominator = 6x^2 + 20 x +1 ... so , multiply the original statement with 3x and see what happens :-
6x^2 + 1=15x .... now , 5x/(20x+15x) = 1/7 ....
problem type 2:-
now , we see what happens when such type of questions exist :-
rt(3+x)+rt(3-x)/rt(3+x)-rt(3-x) = 2 .... always use C&D rule ...
what is C&D => a/b = c/d ... then a+b/a-b=c+d/c-d ....
so , rt(3+x)/rt(3-x)=3/1 .... squaring now , we get
3+x/3-x=9 ... x=12/5 ..
don't comment ..... still writing
problem type 3 :-
what happens if such question arises in the exam :-
x=5-rt(21) what is the value of rt(x)/(rt(32-2x)-rt(21)) =?
always remember , this is ssc exam not banking ....here , if there is no mistake in the question , then there is always a trick in 98% questions and rest 2% may be calculative .........
hume lagna chahiye ki yaha square 100% banega ..... agar ye nai laga to question gaya haath se
now we see :-
32-2x = 32-10+2rt(21) = 22+2rt(21) = rt(21)^2 + 1^2 + 2*rt(21)*1 =(rt(21)+1 )^2 ...
now , we see denominator part =>
rt(32-2x) -rt(21) = rt(21)+1 - rt(21) =1 ..
numerator part => rt(x) ...
now , we stuck here but remember the rule , square banega unless there is no mistake by organization in question....
rt(5-rt(21)) => multiply each by 2 .... rt(10-2rt(21)/2)= rt((rt(7)^2+rt(3)^2-2*rt(7)*rt(3))/2) =(rt(7)-rt(3))^2/2 ..
so , rt(x) = rt(7)-rt(3)/2
many of such questions arise in the exam but remember the rule ...
a similar type :-
if x = 4rt(15)/ rt(5)+rt(3) ... what is the value of
x+rt(20)/x-rt(20) + x+rt(12)/x-rt(12) =?
now , we see in such cases :-
x/rt(20) = 2rt(3)/rt(5)+rt(3) ... and x/rt(12) = 2rt(5)/rt(5)+rt(3) ..
(x/rt(20))+1 = 3rt(3)+rt(5) / rt(5)+rt(3) ... now , you can solve it easily .... do it :)
problem type 4 :-
this type plays a vital role and always arise in the exam :-
if xy/x+z=a , yz/y+z=c , xz/x+z= b ..... what is the value of x if a,b,c not equal to zero ...
options :- 2abc/(ab+bc-ca) .... 2abc/bc+ca-ab ...... 2abc/ab+ac-bc and last 2abc/ab+bc+ca ...
now , we must do such by options , now if you solve such then 100% get in trouble during exam and 2 or more mins you will lose ...
now , we come on tricky part ...
let x=1,y=2 , z=3 ... don't take equal values where options are such ...
and a= 2/3 ,b= 3/4 , c= 6/5 ...
now , 2abc = 2*2/3 * 3/4 * 6/5 = 6/5 ..
ab = 1/2 , bc= 9/10 , ca = 4/5 ...
now , we see all fraction parts are easy to convert it into % otherwise sum and subtraction is hectic ..
hence , 2abc = 120% ... ab=50 , bc=90 , ca=80 ..
so , we know value of x=1 ... which is 100% ... hence 120/(90+80-50) = 100% ... = 2abc/(bc+ca-ab) ....
still writing ...
problem type 5:-
if we get such a question :-
if a+1/b =1 , b+1/c =1 ... then c+1/a = ? ...
now , we do some calculations and blah blah .......... we must think in a tricky way :-
when two variables are added and give sum 1 .... then they may be 50%-50% means 1/2 .. 1/2 ...
now , put a=1/2 , b=2 ... this value satisfies ...
now , in 2nd given equation , b=2 then 2+1/c =1 ... c= -1 ..
c+1/a = -1+2 = 1
another question :-
if a^2+b^2=2 and c^2+d^2 = 1 ... then value of (ad-bc)^2 + (ac+bd)^2 = ?
now , we see we have to square and blah blah ........ no ,no it will consume your time ..
so , we see a=b=1 ..... c=d=1/rt(2) ( as we discussed above when two variables are added ) ...
so , ad-bc=0 ... ad+bc=1/rt(2)+1/rt(2) = rt(2) ..
squaring and adding = 0+2=2 ...
I m assuming you can do such questions yourself easily :- so i will not discuss such types :-
x-1/x = 5 .. then x^2+1/x^2 ... but here , i would like to say first see if there is a solution for equation or not ... then proceed ..
another :- if x+9/x =6 , then x^2+9/x^2 = ?
now , remember the formula first see if there is a solution :-
x^2-6x+9=0 .. B^2-4AC= 0 ...
so , x=3 ... hence 9+9/9 = 10 ..
problem type 6 :-
if m+ 1/m-2=4 ... then (m-2)^2 + 1/(m-2)^2 = ?
in such cases , make the such as we have to find ...
m-2+1/m-2 = 4-2 =2 ... let m-2 = t ..
t+1/t=2 ... then t^2+1/t^2 you know solve it yourself and will get 2
koi mujahe batao ki is baar ganeral awareness hai ya general knowledge...
Pinnacle People ? Anyone there ?