ShoutBox (Part 1)

Jobs & Careers
20031
@Estallar12 said:
Ahaaan. Aapne TAG kiya Vaani Ma'am - I thought humse khafa khafa ho.
Romeo Estallar in Full Form :P
20032
@aimingCAT12 said:
@YouMadFellow @fisherking @Estallar12 sab like karo bas! jawab koi nai dega!
Arey ruko to sahi.. Thoda kaam karne do.. warna free me itni salary le raha hu main to :P..
20033
The number of ways in which a score of 11 can be made from a throw of three person, each throwing a single dice once
(a) 45
(b) 18
(c) 27
(d) N.O.T.
20034
@Estallar12 said:
Ahaaan. Aapne TAG kiya Vaani Ma'am - I thought humse khafa khafa ho.
main kyu khafa hone lagi :/ tum hi bas SB pe aate ho..fatafat posts like karte ho aur chale jate ho. time kahan hota hai aapke paas
20035
@parassharmarock said:
The number of ways in which a score of 11 can be made from a throw of three person, each throwing a single dice once
(a) 45
(b) 18
(c) 27
(d) N.O.T.
27 ?

1,4,5 / 1,5,5 / 2,3,6 / 2,4,5 / 3,3,5/ 3,4,4 and their arrangements
20036
@parassharmarock 27..??
20037
@milestogo3 said:
lopa jee...ek doubt tha...not in LR though.
izaazat hai?
bolo
20038

Puys what was the highest score in cat last year?Whar score do i need to get more than 99.5 percentile.Thanks

20039
@YouMadFellow said:
@lopagargg @Brooklyn Us 4*4 wale question me triangle kaisa banega yeh samajh me nahi aa raha ! I mean the third point is in a perpendicular axes to the two points ka matlab ? Right angled triangle ? Google didn't help much and I didn't bother much too .. What did you guys think of it ?
ahem...me and quant i considered x-y axis till x,y=4
20040

yeah 27

20041
@lopagargg said:
ahem...me and quant i considered x-y axis till x,y=4
Haan, maine bhi wohi kiya 😃 .. but uske aage triangle bhi to banane hai naa ? :)
20042
@YouMadFellow said:
@lopagargg @Brooklyn Us 4*4 wale question me triangle kaisa banega yeh samajh me nahi aa raha ! I mean the third point is in a perpendicular axes to the two points ka matlab ? Right angled triangle ? Google didn't help much and I didn't bother much too .. What did you guys think of it ?
I think select 1 vertical and one horizontal line...jitne bhi points honge in dono lines mein..jitne bhi possible triangles form ho sakte hain wohi answer hona chhaiye...
20043

Guys, have a question- going to take 2/3 CL mocks offline in coming 10 odd days before CAT.

Which ones are closer to CAT level(as we all know nothing is similar to CAT!!)?

Time walon ne aakhri test mein watt lagayi thi....so, want to nail some oder paper.

Replies awaited.

TIA

20044
@YouMadFellow said:
@lopagargg @Brooklyn Us 4*4 wale question me triangle kaisa banega yeh samajh me nahi aa raha ! I mean the third point is in a perpendicular axes to the two points ka matlab ? Right angled triangle ? Google didn't help much and I didn't bother much too .. What did you guys think of it ?
5C1*5C1 ( 5C1*5C2 + 5C2*5C1 - 4C1*4C1) = 25*84 = 2100

Koi aur method??
20045
@blade014 PM 10 and 5
20046
@sasu1ke said:
Puys what was the highest score in cat last year?Whar score do i need to get more than 99.5 percentile.Thanks
a very subjective question no 1 can answer that till the results are out...but i guess anything in excess of 120 ( raw score )....shld definitely b 99.6+...highest score was 384 last year...which is roughly 154 ( raw score )....so if u score anything in excess of 140 in any paper...u r bound to get very close to 100% ile...but forget these and focus on mauling the CAT...
20047
@MI8888 said:
I think select 1 vertical and one horizontal line...jitne bhi points honge in dono lines mein..jitne bhi possible triangles form ho sakte hain wohi answer hona chhaiye...
So, that means the triangles will be right angled triangles ? And the vertices can lie on a diagonal too , right ?
20048
@YouMadFellow said:
So, that means the triangles will be right angled triangles ? And the vertices can lie on a diagonal too , right ?
No no...triangles right angles nahi hain sab...
Ex- select any horizontal or vertical line..select any possible 2 points on that line and the third point can lie anywhere you want...so third point will be on a axis which is perpendicular to those 2 points...
20049

i guess somthing like taking two points on x axis as base like x=0 to 1, x=0 to 2, x=1 to 2 and so on...in the same fashion we can repeat for y....

20050
@MI8888 said:
5C1*5C1 ( 5C1*5C2 + 5C2*5C1 - 4C1*4C1) = 25*84 = 2100
Koi aur method??
options were close to 9xxx