@YouMadFellow
A triangle has a perimeter of P units.If all the sides are integers,then find the no of possibilities for sides when P=30
1)19
2)114
3)38
4)57
5)36
@anupam001 said:jitna mujhe pata hai 3:5 is similar to 1:3 jiske 4 meeting point honge 90 180 270 360
Thik hai, ye solve karo.
Ques: Find the first meeting of two runners, who started from a point A in opposite direction, with speeds in the ratio 3:5
@fisherking said:@YouMadFellow A triangle has a perimeter of P units.If all the sides are integers,then find the no of possibilities for sides when P=30 1)19 2)114 3)38 4)57 5)36
19?
I mean 19 possible tringles
I mean 19 possible tringles
:D
@gyrodceite said:19? I mean 19 possible tringles
Method??Humara bhi aaya aur correct hain par humne ekdum brute force lagaya.Agar koi accha method hain toh post kardo yaar
@YouMadFellow said:Thik hai, ye solve karo.Ques: Find the first meeting of two runners, who started from a point A in opposite direction, with speeds in the ratio 3:5
total meeting points will be 8
so L/8 , 2L/8 , 3L/8, 4L/8, 5L/8, 6L/8, 7L/8, L..
L/8 is the first meeting point :)
so L/8 , 2L/8 , 3L/8, 4L/8, 5L/8, 6L/8, 7L/8, L..
L/8 is the first meeting point :)
@fisherking said:@YouMadFellow A triangle has a perimeter of P units.If all the sides are integers,then find the no of possibilities for sides when P=30 1)19 2)114 3)38 4)57 5)36
19 ?
x + y + z = 30
z = 1, Not possible
z = 2 -> 1 ( 14,14,2)
and so on till z = 8 ( 4 triangles)
+ one equilateral triangle (10,10,10) . Total = 19
@fisherking said:@YouMadFellow A triangle has a perimeter of P units.If all the sides are integers,then find the no of possibilities for sides when P=30 1)19 2)114 3)38 4)57 5)36
19
Tn = (n+3)^2/ 48 when n is odd
Tn = n^2/48 when n is even
here n=30
@fisherking said:Method??Humara bhi aaya aur correct hain par humne ekdum brute force lagaya.Agar koi accha method hain toh post kardo yaar
[ P^2 /48 ] if P is even and [(P+3)^2/48] when P is odd..here P is the parameter and [] is the floor function
isko bhi quant thread bna do 😁 :D
@gyrodceite said:total meeting points will be 8 so L/8 , 2L/8 , 3L/8, 4L/8, 5L/8, 6L/8, 7L/8, L..L/8 is the first meeting point
For first meeting point :
d/(5x) = (2pi*r - d) / 3x
=> d = 2pi*r * 5/8 => d/2pi*r = 5/8
Lunch time :)
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@YouMadFellow said:For first meeting point :d/(5x) = (2pi*r - d) / 3x=> d = 2pi*r * 5/8 => d/2pi*r = 5/8
oops sorry I made a mistake for the first meeting point..ty for pointing out..:)
@gyrodceite said:[ P^2 /48 ] if P is even and [(P+3)^2/48] when P is odd..here P is the parameter and [] is the floor function
Hai rabba iss nadaan se question main tumne yeh vinaashkaari function kaha se nikaal diya quant raja??Hume bhi thoda gyaan do
@YouMadFellow said:For first meeting point :d/(5x) = (2pi*r - d) / 3x=> d = 2pi*r * 5/8 => d/2pi*r = 5/8
and I guess Examiner will mention whether clockwise or anticlockwise..or is there some convention for this?
@YouMadFellow said:19 ?x + y + z = 30z = 1, Not possiblez = 2 -> 1 ( 14,14,2)and so on till z = 8 ( 4 triangles)+ one equilateral triangle (10,10,10) . Total = 19
Humne bhi yahi method se kiya par udhar to ek bhayank sa method aa gaya complete with ceiling function and all 
@YouMadFellow said:Thik hai, ye solve karo.Ques: Find the first meeting of two runners, who started from a point A in opposite direction, with speeds in the ratio 3:5
@gyrodceite said:total meeting points will be 8 so L/8 , 2L/8 , 3L/8, 4L/8, 5L/8, 6L/8, 7L/8, L..L/8 is the first meeting point
first meeting point to 3L/8 hoga kitne honge toal confusiya gaya hun
@anupam001 said:first meeting point to 3L/8 hoga kitne honge toal confusiya gaya hun
for the first meeting point we are suppose to equate the time only I guess
so let say speed are 3x and 5x then time taken by both should be equal
i.e d/3x = (L-d)/5x
d = 3(L-d)/5
8d = 3L
d = 3L/8
yes sir yahi aa raha h..and if if take from other direction it will be 5l/8
so woh bhi galat nahi h ..:D
so let say speed are 3x and 5x then time taken by both should be equal
i.e d/3x = (L-d)/5x
d = 3(L-d)/5
8d = 3L
d = 3L/8
yes sir yahi aa raha h..and if if take from other direction it will be 5l/8
so woh bhi galat nahi h ..:D
m+n when running in opposite direction and here m and n should be co-prime
m-n when same
if the speed of A ,B and C are in the ratio 2:3:5.
A and B are running in clockwise direction and C in anticlockwise direction then find the total number of distinct meeting points?@anupam001