ShoutBox (Part 1)

@ashishpai2001 said:
Consecutive natural numbers have HCF = 1 na?
@karl said:
question yehi hai, Let a,b,c be 8x,8y,8z as 8 is the HCF.
So, a-b = 8(x-y)=8(y-z)=1.... can you check question or point me my mistake.
a - b = b - c = 8..
@Enigma001 said:
sry,,,10
approach batao..I guess ans 12 dia hua tha..not sure..:)
counting hi kiye ho?
@gyrodceite said:
Find the number of ways to paint a cube with only two colors? red and blue
ans ? :|
@gyrodceite said:
a - b = b - c = 8..
QUestion wapaas dalo
@gyrodceite said:
a,b and c are three positive natural numbers with HCF = 8.a -b = b -c = 1 and LCM of a,b,c is a 4 digit number..find the max possible value of c..?
72??
@ashishpai2001 said:
QUestion wapaas dalo
a,b and c are three positive natural numbers with HCF = 8.
a -b = b -c = 8 and LCM of a,b,c is a 4 digit number..find the max possible value of c..?
80,88,96,72?
@Brooklyn said:
72??
@gyrodceite said:
a,b and c are three positive natural numbers with HCF = 8.
a -b = b -c = 8 and LCM of a,b,c is a 4 digit number..find the max possible value of c..?80,88,96,72?
@gyrodceite said:
approach batao..I guess ans 12 dia hua tha..not sure.. counting hi kiye ho?
12 tab hoga jab red OR blue hoga ,i guess
because that will include a whole red and a blue cube.

5R 1B --> 1case
4R 2B --> 2 cases
3R 3B---> 2cases

total =5*2 =10
@gyrodceite said:
a,b and c are three positive natural numbers with HCF = 8.
a -b = b -c = 8 and LCM of a,b,c is a 4 digit number..find the max possible value of c..?80,88,96,72?
a= 8f, b = 8(f-1), c = 8(f-2)
L = 8f(f-1)(f-2)
max value of f = 11
c= 8(11-2) = 72

@gyrodceite 96

@gyrodceite said:
a,b and c are three positive natural numbers with HCF = 8.a -b = b -c = 1 and LCM of a,b,c is a 4 digit number..find the max possible value of c..?
C IS 72 ?? but i ignore a-b=b-c=1....coz that's seems impossible to me...as hcf is 8 and fifferenve is 1...how come....nyone ??


EDIT- ohh edit kar dya...dekha nhi :P
@anytomdickandhary
@Enigma001 said:
12 tab hoga jab red OR blue hoga ,i guess
because that will include a whole red and a blue cube.
5R 1B --> 1case
4R 2B --> 2 cases
3R 3B---> 2cases
total =5*2 =10
explain karna ye kya kiya hai ???
PS 10 hi hoga OA Burnside formula se bhi 10 aa rha hai
@Brooklyn said:
6c1 *2c1 + 6c2*c1 so on 2^6 * 2c1 = 2^7 ??
@Brooklyn said:
explain karna ye kya kiya hai ???
PS 10 hi hoga OA Burnside formula se bhi 10 aa rha hai
burnside formula kya hai bhai...Elaborate plz.
@Enigma001 said:
ye chodo ye glat hai aap apna appraoch btao
@Enigma001 said:
burnside formula kya hai bhai...Elaborate plz.
@Enigma001 said:
burnside formula kya hai bhai...Elaborate plz.
@Enigma001 said:
burnside formula kya hai bhai...Elaborate plz.
@Brooklyn said:
ye chodo ye glat hai aap apna appraoch btao
@Brooklyn said:
ye chodo ye glat hai aap apna appraoch btao
Basically what you have to do is paint the cube using 2 colors R and B :

Case 1 : 5faces R,1 face blue and vice versa : 1*2 =2
Case 2: 4 faces R, 2 faces blue and vice versa :2*2 = 4
Case 3: 3R,3B and vice versa : 4 cases
@Enigma001 Arey jab Red OR Blue hoga, tabhi to 10 aayega. Why are you multiplying 3R and 3B by 2? If it is red AND blue, tab to 8 aayega because all Red and all Blue are removed from the list.
@RoadKill said:
@Enigma001 Arey jab Red OR Blue hoga, tabhi to 10 aayega. Why are you multiplying 3R and 3B by 2? If it is red AND blue, tab to 8 aayega because all Red and all Blue are removed from the list.
bhai explain karna kya bola!!